So sánh các phân số
a)\(\dfrac{12}{14};\dfrac{1212}{1414};\dfrac{121212}{141414}\)
b)\(\dfrac{24}{35};\dfrac{2424}{3535};\dfrac{242424}{353535}\)
c)\(\dfrac{22}{25}\) và \(\dfrac{224466}{255075}\)
d)\(\dfrac{122436}{132639}\)và \(\dfrac{12}{13}\)
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ta có : `12/14 = 6/7`
`13/24=(13xx7)/(24xx7)= 91/168`
`6/7=(6xx24)/(7xx24)= 144/168`
mà : `91<144`
`=> 13/24 < 12/14`
\(\dfrac{13}{24}\) = \(\dfrac{13\times7}{24\times7}\) = \(\dfrac{91}{168}\)
\(\dfrac{12}{14}\) = \(\dfrac{12\times12}{14\times12}\) = \(\dfrac{144}{168}\)
\(\dfrac{91}{689}< \dfrac{144}{168}\)
\(\dfrac{13}{24}\) < \(\dfrac{12}{14}\)
a) 3 2 + − 4 3 = 1 6
1 10 + − 4 5 = − 7 10
Mà 1 6 > − 7 10 nên 3 2 + − 4 3 > 1 10 + − 4 5
b) 1 2 + 1 3 + 1 4 + 1 5 + 1 6 = 29 20 < 2
Nên 1 2 + 1 3 + 1 4 + 1 5 + 1 6 < 2
a: \(\frac{11}{32}>\frac{11}{33}=\frac13\)
\(\frac13=\frac{16}{48}>\frac{16}{49}\)
Do đó: \(\frac{11}{32}>\frac{16}{49}\)
b: \(\frac{46}{71}<\frac{46}{69}=\frac23\)
\(\frac23=\frac{38}{57}<\frac{38}{55}\)
Do đó: \(\frac{46}{71}<\frac{38}{55}\)
c: \(\frac{12}{47}>\frac{12}{48}=\frac14\)
\(\frac14=\frac{29}{116}>\frac{29}{117}\)
Do đó: \(\frac{12}{47}>\frac{29}{117}\)
d: \(\frac{18}{53}>\frac{18}{54}=\frac13\)
\(\frac13=\frac{34}{102}>\frac{34}{103}\)
Do đó: \(\frac{18}{53}>\frac{34}{103}\)
a) \(\dfrac{5}{9}< \dfrac{7}{9}\)
b) \(\dfrac{7}{6}>\dfrac{6}{6}\)
c) \(\dfrac{3}{14}< \dfrac{5}{14}\)
d) \(\dfrac{5}{8}< \dfrac{9}{8}\)
`17/20 = 119/140`
`11/14=110/140`
`=> 119/140 > 110/140`
`=> 17/20 > 11/14`
\(\dfrac{17}{20}=\dfrac{17\cdot14}{20\cdot14}=\dfrac{238}{280}\)
\(\dfrac{11}{14}=\dfrac{11\cdot20}{14\cdot20}=\dfrac{220}{280}\)
mà 238>220
nên \(\dfrac{17}{20}>\dfrac{11}{14}\)
12/13 = 0.9230769231
11/14 = 0.7857142857
Vậy phân số 11/14 nhỏ hơn
a)Ta có : \(\dfrac{1212}{1414}=\dfrac{12.101}{14.101}=\dfrac{12}{14}\)
\(\dfrac{121212}{242424}=\dfrac{12.10101}{24.10101}=\dfrac{12}{24}\)
Vậy \(\dfrac{12}{24}=\dfrac{1212}{2424}=\dfrac{121212}{242424}\)
Ta có : \(\dfrac{2424}{3535}=\dfrac{24.101}{35.101}=\dfrac{24}{35}\)
\(\dfrac{242424}{353535}=\dfrac{24.10101}{35.10101}=\dfrac{24}{35}\)
Vậy \(\dfrac{24}{35}=\dfrac{2424}{3535}=\dfrac{242424}{353535}\)