đùa nhau à

?

b, 92 : 4 - 27 = \(\dfrac{x+350}{x}\) + 315

   23 - 27       = 1 + \(\dfrac{350}{x}\) + 315

         316 + \(\dfrac{350}{x}\) = -4

                  \(\dfrac{350}{x}\) = - 316  - 4

                  \(\dfrac{350}{x}\) = -320

           -320 \(x\)   = 350

                     \(x\) = 350: (-320)

                   \(x\) = - \(\dfrac{35}{32}\) (loại)

Vậy \(x\) \(\in\)  \(\varnothing\) 

c, 720 : [ 41 - (2\(x\) - 5)] = 2³.5

             41 - (2\(x\) - 5)   = 720 : (2³.5)

              41 - 2\(x\) + 5   = 18

              46 - 2\(x\)         =18

                      2\(x\)        = 46 - 18

                      2\(x\)       = 28

                        \(x\)       = 28: 2

                        \(x\)       = 14

Vậy \(x\) = 14

a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)

=>\(\left[2\left(10-x\right)+51\right]:3=5\)

=>\(\left[2\left(10-x\right)+51\right]=15\)

=>\(2\left(10-x\right)=15-51=-36\)

=>10-x=-36/2=-18

=>\(x=10-\left(-18\right)=10+18=28\)

b: \(\left(x-12\right)-15=20-\left(17+x\right)\)

=>\(x-12-15=20-17-x\)

=>\(x-27=3-x\)

=>\(2x=30\)

=>\(x=\dfrac{30}{2}=15\)

c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)

=>\(720-\left[41-2x+5\right]=8\cdot5=40\)

=>\(\left[41-2x+5\right]=720-40=680\)

=>-2x+46=680

=>-2x=680-46=634

=>\(x=\dfrac{634}{-2}=-317\)

\(a,x-36:18=12-15\\ \Rightarrow x-2=-3\\ \Rightarrow x=-1\\ b,92-\left(17+x\right)=72\\ \Rightarrow17+x=20\\ \Rightarrow x=3\\ c,720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=18\\ \Rightarrow x=9\\ d,\left(x+2\right)^3-23=41\\ \Rightarrow\left(x+2\right)^3=64\\ \Rightarrow\left(x+2\right)^3=4^3\\ \Rightarrow x+2=4\\ \Rightarrow x=2\)

b: =>x+17=20

hay x=3

d: =>x+2=4

hay x=2

280 - ( x - 140 ) : 35 = 270

<=>    ( x - 140 ) : 35 = 280 -270

<=>    ( x -140 ) : 35 = 10

<=>      x -140          = 10 . 35

<=>      x  -140         = 350

<=>      x                 = 350 + 140

<=>     x                  = 490 

1) 280 - ( x - 140 ) : 35 = 270

=> ( x - 140 ) : 35 = 280 - 270 = 10

     x - 140 = 350

=> x = 350 + 140

=> x = 390

2) ( 190 - 2x ) : 35 - 32 = 16

     190 - 2x = ( 16 + 32 ) . 35 = 1680

    x = ( 190 - 1680 ) : 2

   x = -745

3) 720 : { 41 - ( 2x - 5 )} -2.5

Sai đề.

4) ( x : 23 + 45 ) . 37 - 22 = 24 .105

    x : 23 + 45 = ( 24.105 + 22 ) : 37

    x : 23 = 2542/37 - 45 = 877/37

    x = 877/37.23 = 20171/37

5) ( 3x - 4 ) ( x - 1 ) = 0

=> 3x - 4 = 0 hoặc x - 1 = 0

3x - 4 = 0      hoặc x - 1 = 0

=> x = 4/3        => x = 1

Vậy x \(\in\) { 4/3;1 }

6) 2^2x : 4 = 8³

=> 2^2x = 8³ . 4 = 2048 = 2¹¹

=> 2x = 11

=> x = 11/2 

a,  70 - 5 ( x - 3 ) = 45

⇔ 5 . x - 3 = 70 - 45

⇔ 5 x - 3 = 35

⇔ x - 3 = 35 : 5 ⇔ x - 3 = 7

⇔ x = 10

b,  10 + 2 x = 4 5 : 4 3

⇔ 10 + 2 x = 4 2 ⇔ 10 + 2 x = 16

⇔ 2 x = 4 ⇔ x = 2

c,  60 - 3 x - 2 = 51

⇔ 3 x - 2 = 60 - 51

⇔ 3 x - 2 = 9

⇔ x - 2 = 3 ⇔ x = 5

d,  4 x - 20 = 2 5 : 2 3

⇔ 4 x - 20 = 2 2 ⇔ 4 x - 20 = 4

⇔ 4 x = 24 ⇔ x = 6

a: \(280-\left(x-140\right):35=270\)

=>(x-140):35=280-270=10

=>x-140=350

=>x=350+140

=>x=490

b: \(\left(190-2x\right):35-32=16\)

=>\(\left(190-2x\right):35=32+16=48\)

=>\(190-2x=35\cdot48=1680\)

=>2x=190-1680=-1490

=>x=-745

c: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=2^3\cdot5\)

=>\(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=8\cdot5=40\)

=>41-(2x-5)=720:40=18

=>2x-5=41-18=23

=>2x=28

=>x=14

d: \(\left(x:23+45\right)\cdot37-22=2^4\cdot105\)

=>\(\left(\frac{x}{23}+45\right)\cdot37=16\cdot105+22=1702\)

=>\(\frac{x}{23}+45=46\)

=>\(\frac{x}{23}=1\)

=>x=23

e: \(\left(3x-4\right)\left(x-1\right)^3=0\)

=>\(\left[\begin{array}{l}3x-4=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac43\\ x=1\end{array}\right.\)

f: \(2^{2x-1}:4=8^3\)

=>\(2^{2x-1-2}=2^9\)

=>2x-3=9

=>2x=12

=>x=6

g: \(x^{17}=x\)

=>\(x^{17}-x=0\)

=>\(x\left(x^{16}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{16}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{16}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\\ x=-1\end{array}\right.\)

h: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-4\right)\left(x-6\right)=0\)

=>x∈{4;5;6}

i: \(\left(x+2\right)^5=2^{10}\)

=>\(\left(x+2\right)^5=\left(2^2\right)^5=4^5\)

=>x+2=4

=>x=2

k: 1+2+3+...+x=78

=>\(\frac{x\left(x+1\right)}{2}=78\)

=>x(x+1)=156

=>\(x^2+x-156=0\)

=>(x+13)(x-12)=0

=>x=-13(loại) hoặc x=12(nhận)

l: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

n: \(5^{x}:5^2=125\)

=>\(5^{x-2}=5^3\)

=>x-2=3

=>x=5

m: \(\left(x+1\right)^2=\left(x+1\right)^0\)

=>\(\left(x+1\right)^2=1\)

=>\(\left[\begin{array}{l}x+1=1\\ x+1=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=-2\end{array}\right.\)

o: Số số hạng của dãy số 2;4;..;52 là:

(52-2):2+1=50:2+1=25+1=26(số)

Tổng của dãy số 2;4;...;52 là:

\(\left(52+2\right)\cdot\frac{26}{2}=54\cdot13=702\)

(2+x)+(4+x)+...+(52+x)=780

=>26x+702=780

=>26x=78

=>x=3

p: \(70=2\cdot5\cdot7;80=2^4\cdot5\)

=>ƯCLN(70;80)=\(2\cdot5=10\)

70⋮x; 80⋮x

=>x∈ƯC(70;80)

=>x∈Ư(10)

mà x>8

nên x=10

q: \(12=2^2\cdot3;25=5^2;30=2\cdot3\cdot5\)

=>BCNN(12;25;30)=\(2^2\cdot3\cdot5^2=300\)

x⋮12; x⋮25; x⋮30

=>x∈BC(12;25;30)

=>x∈B(300)

mà 0<x<500

nên x=300

a, \(x-105:21=15\)

\(x-5=15\)

\(x=20\)

b, \(\left(x-105\right):21=15\)

\(x-105=315\)

\(x=315+105=420\)

c, \(\left(x:23+45\right).67=8911\)

\(x:23+45=133\)

\(x:23=88\)

\(x=88.23=2024\)

d, \(720:\left[41-\left(2x-5\right)\right]=8.5\)

\(720:\left[41-\left(2x-5\right)\right]=40\)

\(41-\left(2x-5\right)=18\)

\(2x-5=23\)

\(2x=28\)

\(x=14\)

Chúc bạn học tốt

Bài 5: Tìm x thuộc số tự nhiên:

a) x - 105 : 21= 15

x - 5 = 15

x = 15 + 5

x = 20

b) (x - 105) : 21 = 15

x - 105 = 15 . 21

x - 105 = 315

x = 315 + 105

x = 420

c) ( x : 23 + 45) . 67 = 8911

x : 23 + 45 = 8911 : 67

x : 23 + 45 = 133

x : 23 = 133 - 45

x : 23 = 88

x = 88 . 23

x = 2024.

d) 720: [41 - (2 . x - 5)] = 8 . 5

720: [41 - (2 . x - 5)] = 40

41 - (2 . x - 5) = 720 : 40

41 - (2 . x - 5) = 18

2 . x - 5 = 41 - 18

2 . x - 5 = 23

2 . x = 23 + 5

2 . x = 28

x = 28 : 2

x = 19