Tính
(3.4.216)2/11.213.411-169
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Sửa đề: \(B=\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}\cdot\frac{3+\frac37-\frac{3}{11}}{\frac97-\frac{9}{11}+9}\)
\(=\frac{\left(3\cdot2^2\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot2^{22}-2^{36}}\cdot\frac{3\left(1+\frac17-\frac{1}{11}\right)}{9\left(1+\frac17-\frac{1}{11}\right)}\)
\(=\frac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{35}-2^{36}}\cdot\frac13\)
\(=\frac{9\cdot2^{36}}{2^{35}\left(11-2\right)}\cdot\frac13=\frac23\)
(169-42).(169-52)…(169-122).(169-132)
=(169-42).(169-52)…(169-122).(169-169)
=(169-42).(169-52)…(169-122).0
=0
(169 - 4^2) . (169 - 5^2) ... (169 - 13^2)
=(169-4^2).(169-5^2)...(169-169)
=0
Tính giá trị biểu thức:
A = (169 - 1 . 1) . (169 - 2 . 2) . ... . (169 - 23 . 23)????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????/
\(\left(169-4^2\right).\left(169-5^2\right)...\left(169-13^2\right)\)
\(=\left(169-4^2\right).\left(169-5^2\right)...\left(169-169\right)\)
\(=0\)
\(\left(169-4^2\right).\left(169-5^2\right)...\left(169-13^2\right)\)
Mà \(13^2=169\)
\(\Rightarrow\left(169-4^2\right)\left(169-5^2\right)...\left(169-169\right)\)
\(=\left(169-4^2\right)\left(169-5^2\right)...0\)
\(=0\)
(169-1.1)(169-2.2)...(169-23.23)=(169-1.1)(169-2.2)...(169-13.13)...(169-23.23)
=(169-1.1)(169-2.2)...0...(169-23.23)
=0
\(-\dfrac{6144}{679}\)
\(\dfrac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}=\dfrac{3.2^{18}}{11.2^{13}.2^{22}-2^{36}}=\dfrac{3.2^{18}}{11.2^{35}-2^{35}.2}=\dfrac{3.2^{18}}{2^{35}\left(11-2\right)}=\dfrac{3.2^{18}}{2^{17}.2^{18}.3^2}=\dfrac{1}{2^{17}.3}\)