a) 513-(184)-(997-46)+146 = -476

1: \(347\cdot2^2-2^2\cdot\left(216+184\right):8\)

\(=347\cdot4-4\cdot400:8\)

\(=347\cdot4-4\cdot50=4\cdot\left(347-50\right)=4\cdot297=1188\)

2: \(132-\left\lbrack116-\left(132-128\right)^2\right\rbrack\)

\(=132-\left\lbrack116-4^2\right\rbrack\)

=132-(116-16)

=132-100

=32

3: \(16:\left\lbrace400:\left\lbrack200-\left(37+46\cdot3\right)\right\rbrack\right\rbrace\)

=16:{400:[200-(37+138)]}

=16:{400:[200-175]}

=16:{400:25}

=16:16

=1

4: \(\left\lbrace184:\left\lbrack96-124:31\right\rbrack-2\right\rbrace\cdot3651\)

\(=\left\lbrace\frac{184}{96-4}-2\right\rbrace\cdot3651\)

=(184:92-2)*3651

=0

5: \(46-\left\lbrack\left(16+71\cdot4\right):15\right\rbrack-2\)

=46-[(16+284):15]-2

=46-300:15-2

=46-20-2

=46-22

=24

6: \(3^3\cdot18+72\cdot4^2-41\cdot18\)

\(=18\left(3^3-41\right)+72\cdot16\)

\(=18\cdot\left(27-41\right)+18\cdot64\)

=18(-14+64)

=18*50

=900

7: \(\left(56\cdot46-25\cdot23\right):23\)

\(=56\cdot\frac{46}{23}-25\)

=112-25

=87

8: \(\left(28\cdot54+56\cdot36\right):21:2\)

\(=18\cdot28\left(3+2\cdot2\right):42\)

\(=18\cdot\frac{28}{42}\cdot7=18\cdot\frac23\cdot7=12\cdot7=84\)

9: \(\left(76\cdot34-19\cdot64\right):\left(38\cdot9\right)\)

\(=\frac{19\cdot\left(4\cdot34-64\right)}{38\cdot9}=\frac{4\cdot34-64}{9\cdot2}=\frac{4\cdot\left(34-16\right)}{18}=4\)

10: \(\left(2+4+6+\cdots+100\right)\cdot\left(36\cdot333-108\cdot111\right)\)

\(=\left(2+4+6+\cdots+100\right)\cdot36\cdot111\left(3-3\right)\)

=0

11: \(\left(5\cdot4^{11}-3\cdot16^5\right):4^{10}\)

\(=\left(5\cdot4^{11}-3\cdot4^{10}\right):4^{10}\)

\(=5\cdot\frac{4^{11}}{4^{10}}-3\cdot\frac{4^{10}}{4^{10}}\)

=20-3

=17

12: \(\frac{7256\cdot4375-725}{3650+4375\cdot7255}=\frac{7255\cdot4375+4375-725}{7255\cdot4375+3650}\)

\(=\frac{7255\cdot4375+3650}{7255\cdot4375+3650}\)

=1

1: \(347\cdot2^2-2^2\cdot\left(216+184\right):8\)

\(=347\cdot4-4\cdot400:8\)

\(=347\cdot4-4\cdot50=4\cdot\left(347-50\right)=4\cdot297=1188\)

2: \(132-\left\lbrack116-\left(132-128\right)^2\right\rbrack\)

\(=132-\left\lbrack116-4^2\right\rbrack\)

=132-(116-16)

=132-100

=32

3: \(16:\left\lbrace400:\left\lbrack200-\left(37+46\cdot3\right)\right\rbrack\right\rbrace\)

=16:{400:[200-(37+138)]}

=16:{400:[200-175]}

=16:{400:25}

=16:16

=1

4: \(\left\lbrace184:\left\lbrack96-124:31\right\rbrack-2\right\rbrace\cdot3651\)

\(=\left\lbrace\frac{184}{96-4}-2\right\rbrace\cdot3651\)

=(184:92-2)*3651

=0

5: \(46-\left\lbrack\left(16+71\cdot4\right):15\right\rbrack-2\)

=46-[(16+284):15]-2

=46-300:15-2

=46-20-2

=46-22

=24

6: \(3^3\cdot18+72\cdot4^2-41\cdot18\)

\(=18\left(3^3-41\right)+72\cdot16\)

\(=18\cdot\left(27-41\right)+18\cdot64\)

=18(-14+64)

=18*50

=900

7: \(\left(56\cdot46-25\cdot23\right):23\)

\(=56\cdot\frac{46}{23}-25\)

=112-25

=87

8: \(\left(28\cdot54+56\cdot36\right):21:2\)

\(=18\cdot28\left(3+2\cdot2\right):42\)

\(=18\cdot\frac{28}{42}\cdot7=18\cdot\frac23\cdot7=12\cdot7=84\)

9: \(\left(76\cdot34-19\cdot64\right):\left(38\cdot9\right)\)

\(=\frac{19\cdot\left(4\cdot34-64\right)}{38\cdot9}=\frac{4\cdot34-64}{9\cdot2}=\frac{4\cdot\left(34-16\right)}{18}=4\)

10: \(\left(2+4+6+\cdots+100\right)\cdot\left(36\cdot333-108\cdot111\right)\)

\(=\left(2+4+6+\cdots+100\right)\cdot36\cdot111\left(3-3\right)\)

=0

11: \(\left(5\cdot4^{11}-3\cdot16^5\right):4^{10}\)

\(=\left(5\cdot4^{11}-3\cdot4^{10}\right):4^{10}\)

\(=5\cdot\frac{4^{11}}{4^{10}}-3\cdot\frac{4^{10}}{4^{10}}\)

=20-3

=17

12: \(\frac{7256\cdot4375-725}{3650+4375\cdot7255}=\frac{7255\cdot4375+4375-725}{7255\cdot4375+3650}\)

\(=\frac{7255\cdot4375+3650}{7255\cdot4375+3650}\)

=1

Giải;

1) \(347.222-222.\left(216+184\right):8\) 

\(=347.222-222.400:8\) 

\(=347.222-222.50\) 

\(=222.\left(347-50\right)\) 

\(=222.297\)

\(=65934\) 

2) \(132-\left[116-\left(132-128\right).22\right]\) 

\(=132-\left[116-4.22\right]\) 

\(=132-\left[116-88\right]\) 

\(=132-28\) 

\(=104\) 

3) \(16:\left\{400:\left[200-\left(37+46.3\right)\right]\right\}\) 

\(=16:\left\{400:\left[200-\left(37+138\right)\right]\right\}\) 

\(=16:\left\{400:\left[200-175\right]\right\}\) 

\(=16:\left\{400:25\right\}\) 

\(=16:16\) 

\(=1\) 

4) \(\left\{184:\left[96-124:31\right]-2\right\}.3651\) 

\(=\left\{184:\left[96-4\right]-2\right\}.3651\) 

\(=\left\{184:92-2\right\}.3651\) 

\(=\left\{2-2\right\}.3651\) 

\(=0.3651\) 

\(=0\) 

5) \(46-\left[\left(16+71.4\right):15\right]-2\) 

\(=46-\left[\left(16+284\right):15\right]-2\) 

\(=46-\left[300:15\right]-2\)

 \(=46-20-2\) 

\(=24\)

6) \(3^3.18+72.4^2-41.18\) 

\(=18.\left(27-41\right)+72.16\) 

\(=18.-14+1152\) 

\(=-252+1152\) 

\(=900\)

Giải: (tiếp)

7) \(\left(56.46-25.23\right):23\) 

\(=\left(2576-575\right):23\) 

\(=2001:23\) 

\(=87\) 

8) \(\left(28.54+56.36\right):21:2\) 

\(=\left(1512+2016\right):21:2\) 

\(=3528:21:2\) 

\(=84\) 

9) \(\left(76.34-19.64\right):\left(38.9\right)\) 

\(=\left(2584-1216\right):342\) 

\(=1368:342\) 

\(=4\) 

10) \(\left(2+4+6+...+100\right).\left(36.333-108.111\right)\) 

\(=\left(2+4+6+...+100\right).\left(11988-11988\right)\) 

\(=\left(2+4+6+...+100\right).0\) 

\(=0\) 

11) \(\left(5.4^{11}-3.16^5\right):4^{10}\) 

\(=5.4^{11}:4^{10}-3.16^5:4^{10}\) 

\(=5.4-3.1\) 

\(=20-3\) 

\(=17\) 

12) \(7256.4375-725:3650+4375.7255\) 

\(=4375.\left(7256+7255\right)-\dfrac{29}{146}\) 

\(=4375.14511-\dfrac{29}{146}\) 

\(=63485624,8\) 

Câu 12 ko chắc!

Mình cần gấp bài 1 , 2 và bài 5 mọi người giúp mình với ạ còn 15p nữa thoy ạ , mọi người giúp với ạ

a: \(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^2}\)

\(=\frac{3^2}{3^5}\cdot\frac{3^8}{3^2}=\frac{1}{3^3}\cdot3^6=3^3=27\)

b: \(4^6\cdot256^2\cdot2^4=\left(2^2\right)^6\cdot\left(2^8\right)^2\cdot2^4\)

\(=2^{12}\cdot2^{16}\cdot2^4=2^{12}\cdot2^{20}=2^{32}\)

c: \(4^6\cdot9^5+6^9\cdot120\)

\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)

\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

Ta có \(8^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)

d: \(4^2\cdot25^2+32\cdot125\)

\(=2^4\cdot5^4+2^5\cdot5^3\)

\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=70\)

4: \(=\dfrac{2+3}{7}+\dfrac{1+6}{9}-\dfrac{5}{6}=\dfrac{5}{7}+\dfrac{7}{9}-\dfrac{5}{6}=\dfrac{83}{126}\)

5: \(=\dfrac{-5-2}{7}+\dfrac{3+1}{4}-\dfrac{1}{5}=-\dfrac{1}{5}\)

6: \(=\dfrac{-3-28}{31}+\dfrac{-6-1}{17}+\dfrac{1-5}{25}=-1-\dfrac{7}{17}-\dfrac{4}{25}=-\dfrac{668}{425}\)

4. \(\dfrac{2}{7}+\dfrac{1}{9}+\dfrac{3}{7}+\dfrac{5}{9}+\dfrac{-5}{6}\)

\(=\left(\dfrac{2}{7}+\dfrac{3}{7}\right)+\left(\dfrac{1}{9}+\dfrac{5}{9}\right)+\dfrac{-5}{6}\)

\(=\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{-5}{6}\)

\(=\dfrac{30+28+\left(-35\right)}{42}=\dfrac{23}{42}\)
 

5. \(\dfrac{-5}{7}+\dfrac{3}{4}+\dfrac{-1}{5}+\dfrac{-2}{7}+\dfrac{1}{4}\)

\(=\left(\dfrac{-5}{7}+\dfrac{-2}{7}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\dfrac{-1}{5}\)

\(=\dfrac{-7}{7}+\dfrac{4}{4}+\dfrac{-1}{5}\)

\(=-1+1+\dfrac{-1}{5}\)

\(=-\dfrac{1}{5}\)
 

6. \(\dfrac{-3}{31}+\dfrac{-6}{17}+\dfrac{1}{25}+\dfrac{-28}{31}+\dfrac{-1}{17}+\dfrac{-1}{5}\)

\(=\left(\dfrac{-3}{31}+\dfrac{-28}{31}\right)+\left(\dfrac{-6}{17}+\dfrac{-1}{17}\right)+\dfrac{1}{25}+\dfrac{-1}{5}\)

\(=\dfrac{-31}{31}+\dfrac{-7}{17}+\dfrac{1}{25}+\dfrac{-1}{5}\)

\(=-1+\dfrac{-7}{17}+\dfrac{1}{25}+\dfrac{-1}{5}\)

\(=\dfrac{-425+\left(-175\right)+17+\left(-85\right)}{425}=\dfrac{-668}{425}\)

chx làm :)))

à nhìn nhầm