a) \(\frac{-315}{540}=\frac{-7}{12}\)

b) \(\frac{25.13}{26.35}=\frac{5.1}{2.7}=\frac{5}{14}\)

c) \(\frac{6.9-2.17}{63.3-119}=\frac{2.1-2.17}{7.1-119}=\frac{2.\left(1-17\right)}{7.1-119}=\frac{2.\left(-16\right)}{7-119}=\frac{-32}{-112}=\frac{32}{112}=\frac{2}{7}\)

Làm đến đây là choáng r

Các câu típ theo bn làm nhé

d) 3.13-13.18/15.40-80 = 13.(3-18)/520= 13.(-15)/ 520 = -125/520=-3/8

`[x+35]/1984-[x+30]/1989+[x+19]/2000+[x+23]/[1996=-2`

`<=>[x+35]/1984+1-[x+30]/1989-1+[x+19]/2000+1+[x+23]/1996+1=0`

`<=>[x+2019]/1984-[x+2019]/1989+[x+2019]/2000+[x+2019]/1996=0`

`<=>(x+2019)(1/1984-1/1989+1/2000+1/1996)=0`

  `=>x+2019=0`

`<=>x=-2019`

\(\dfrac{x+35}{1984}-\dfrac{x+30}{1989}+\dfrac{x+19}{2000}+\dfrac{x+23}{1996}\text{=}-2\)

\(\Leftrightarrow\dfrac{x+35}{1984}-\dfrac{x+30}{1989}+\dfrac{x+19}{2000}+\dfrac{x+23}{1996}+3-1\text{=}0\)

\(\Leftrightarrow\left(\dfrac{x+35}{1984}+1\right)-\left(\dfrac{x+30}{1989}+1\right)+\left(\dfrac{x+19}{2000}+1\right)+\left(\dfrac{x+23}{1996}+1\right)\text{=}0\)

\(\Leftrightarrow\dfrac{x+2019}{1984}-\dfrac{x+2019}{1989}+\dfrac{x+2019}{2000}+\dfrac{x+2019}{1996}\text{=}0\)

\(\Leftrightarrow\left(x+2019\right)\left(\dfrac{1}{1984}-\dfrac{1}{1989}+\dfrac{1}{2000}+\dfrac{1}{1996}\right)\text{=}0\)

\(\Leftrightarrow\left(x+2019\right)\text{=}0\)

\(\Leftrightarrow x\text{=}-2019\)

a) 4/5(3/7+4/7)=4/5

câu b,c cũng dễ

a) 4/5 x 3/7 + 4/5 x 4/7

= 4/5 x ( 3/7 + 4/7 )

= 4/5 x 1

= 4/5

2/\(\frac{10}{11}\)

câu 1:

\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}\)

\(\hept{\begin{cases}15=3\cdot5\\35=5\cdot7\end{cases}}\\ \hept{\begin{cases}3=3\\63=3^2\cdot7\\99=3^2\cdot11\end{cases}}\)

=>\(\frac{2310}{3465}+\frac{462}{3465}+\frac{198}{3465}+\frac{110}{3465}+\frac{70}{3465}\)

=>\(\frac{2310+462+198+110+70}{3465}\)

=>\(\frac{3150}{3465}\)=\(\frac{10}{11}\)

c: \(78\cdot31+78\cdot24+78\cdot17+72\cdot22\)

\(=78\cdot\left(31+24+17\right)+72\cdot22\)

\(=72\cdot78+72\cdot22=72\cdot100=7200\)

d: \(\left(456\cdot11+912\right)\cdot37:13:74\)

\(=\frac{456\left(11+2\right)}{13}\cdot\frac{37}{74}=456\cdot\frac12=\frac{456}{2}=228\)

e: [\(\left(315+372\right)\cdot3+\left(372+315\right)\cdot7\) ]:\(\left(26\cdot13+74\cdot14\right)\)

\(=687\cdot\left(3+7\right):\left\lbrack26\cdot13+74\cdot13+74\right\rbrack\)

=687*10:[1300+74]

=687*10:1374

=5