tra mạng đi bn

tl : re ơi, tra mạng nó ra dài lắm mình muốn viết một bài ngắn nhắn thui

Giải:

2 số đó là :

0+0=0

Ai k cho mik ,mik k lại cho

2 số đó là :

 0 + 0 = 0

    Đ/s : 0 và 0

\(x+\dfrac{1}{5}-\dfrac{3}{7}=\dfrac{6}{35}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{3}{7}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{15}{35}\)
\(x+\dfrac{1}{5}=\dfrac{21}{35}\)
\(x=\dfrac{21}{35}-\dfrac{1}{5}\)
\(x=\dfrac{21}{35}-\dfrac{7}{35}\)
\(x=\dfrac{14}{35}=\dfrac{2}{5}\)

\(x\) + \(\dfrac{1}{5}\) - \(\dfrac{3}{7}\) = \(\dfrac{6}{35}\) 

\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{6}{35}\) + \(\dfrac{3}{7}\)

\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{3}{5}\)

\(x\)       = \(\dfrac{3}{5}\) - \(\dfrac{1}{5}\)

\(x\) =\(\dfrac{2}{5}\)

\(\left(x+\dfrac{1}{3}\right)\times\dfrac{9}{14}\times\dfrac{7}{3}-\dfrac{1}{3}=1:\dfrac{9}{5}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}-\dfrac{1}{3}=\dfrac{5}{9}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}=\dfrac{5}{9}+\dfrac{1}{3}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}=\dfrac{8}{9}\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{8}{9}:\dfrac{3}{2}\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{16}{27}\\ \Rightarrow x=\dfrac{16}{27}-\dfrac{1}{3}\\ \Rightarrow x=\dfrac{7}{27}\)

\(50\%+\dfrac{1}{2}+\dfrac{1}{7}\times\dfrac{2}{5}+\dfrac{1}{7}\times\dfrac{3}{5}\)

\(=\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{2}{35}+\dfrac{3}{35}\)

\(=1+\dfrac{5}{35}\)

\(=1+\dfrac{1}{7}\)

\(=\dfrac{8}{7}\)

\(50\%+\dfrac{1}{2}+\dfrac{1}{7}x\dfrac{2}{5}+\dfrac{1}{7}x\dfrac{3}{5}\)

\(=\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{7}x\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\)

\(=1+\dfrac{1}{7}x1\)

\(=\dfrac{7}{7}+\dfrac{1}{7}=\dfrac{8}{7}\)

50% + 1/2 + 1/7 × 2/5 + 1/7 × 3/5

= 1/2 + 1/2 + 1/7 × (2/5 + 3/5)

= 1 + 1/7 × 1

= 1 + 1/7

= 7/7 + 1/7

= 8/7

sau 2 giờ ô tô đi đc số phần quãng đường là:

   1/4+1/6=5/12(quãng đường)

               đs:........

\(\frac{2^3.3}{2^23^2.5}=\frac{2}{3.5}=\frac{2}{15}\)

\(\frac{2^3.3}{2^2.3^2.5}=\frac{2}{3.5}=\frac{2}{15}\)

Thiếu dấu nhân ở chỗ \(2^2.3^2\)nha