giup minh voi may ban oi 

a: =-3/4+1/2-1/13+3/13=-1/4+2/13=-13/52+8/52=-5/52

b: =10/11+1/11-1/8=1-1/8=7/8

c: =4(2,86+3,14)-30,05+9x0,75

=24-30,05+6,75

=0,7

a: \(=\dfrac{1}{3}+\dfrac{1}{8}-\dfrac{3}{16}\cdot4=\dfrac{11}{24}-\dfrac{3}{64}=\dfrac{88}{192}-\dfrac{9}{192}=\dfrac{79}{192}\)

b: \(=\dfrac{5}{8}\cdot\left(-16\right)=-10\)

c: \(=\left(\dfrac{8}{5}+\dfrac{1}{3}\right):\dfrac{29}{5}-\dfrac{4}{81}\cdot9\)

\(=\dfrac{29}{15}\cdot\dfrac{5}{29}-\dfrac{4}{9}=\dfrac{1}{3}-\dfrac{4}{9}=-\dfrac{1}{9}\)

\(c,=4\cdot\left(-\dfrac{1}{8}\right)-2\cdot\dfrac{1}{4}-\dfrac{3}{2}+1=-\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{3}{2}+1=-\dfrac{3}{2}\\ \left(5x+\dfrac{2}{3}\right)^2=\dfrac{1}{4}\Rightarrow\left[{}\begin{matrix}5x+\dfrac{2}{3}=\dfrac{1}{2}\\5x+\dfrac{2}{3}=-\dfrac{1}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x=-\dfrac{1}{6}\\5x=-\dfrac{7}{6}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{30}\\x=-\dfrac{7}{30}\end{matrix}\right.\\ c,x:2=\left(-4\right):5\Rightarrow x=-\dfrac{4}{5}\cdot2=-\dfrac{8}{5}\)

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$Zn + H_2SO_4 \to ZnSO_4 + H_2$
$n_{H_2} = n_{Zn} = \dfrac{19,5}{65} = 0,3(mol)$
$V_{H_2} = 0,3.22,4 = 6,72(lít)$

$2Al + 3H_2SO_4 \to Al_2(SO_4)_3 + 3H_2$
Theo PTHH : 

$n_{Al} = \dfrac{2}{3}n_{H_2} = 0,2(mol)$
$m_{Al} = 0,2.27 = 5,4(gam)$