bậc to thế ==

ừ

a. ĐKXĐ: \(x\ne1\)

\(\dfrac{11x-4}{x-1}+\dfrac{10x+4}{2-2x}=\dfrac{2\cdot\left(11x-4\right)}{2\cdot\left(x-1\right)}-\dfrac{10x+4}{2x-2}\)

\(=\dfrac{22x-8}{2\left(x-1\right)}-\dfrac{10x+4}{2\left(x-1\right)}\)\(=\dfrac{22x-8-10x-4}{2\left(x-1\right)}\)

\(=\dfrac{12x-12}{2\left(x-1\right)}\)\(=\dfrac{12\left(x-1\right)}{2\left(x-1\right)}=6\)

b. ĐKXĐ: \(x\ne-2;x\ne\dfrac{1}{2}\)

\(\dfrac{1}{x+2}+\dfrac{5}{2x^2+3x-2}=\dfrac{2x-1}{\left(2x-1\right)\left(x+2\right)}+\dfrac{5}{\left(2x-1\right)\left(x+2\right)}\)

\(=\dfrac{2x-1+5}{\left(2x-1\right)\left(x+2\right)}=\dfrac{2x+4}{\left(2x-1\right)\left(x+2\right)}\)

\(=\dfrac{2\left(x+2\right)}{\left(2x-1\right)\left(x+2\right)}=\dfrac{2}{2x-1}\)

\(\text{#}Toru\)

5,5 + \(\dfrac{3}{4}\) - 5 + \(\dfrac{1}{4}\)

(5,5 - 5) + (\(\dfrac{3}{4}\) + \(\dfrac{1}{4}\))

= 0,5  + 1

= 1,5 

\(\dfrac{5}{2}\) x  \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) : \(\dfrac{3}{2}\)

= \(\dfrac{5}{2}\) x \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) x \(\dfrac{2}{3}\)

=  (\(\dfrac{5}{2}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)

= (\(\dfrac{10}{4}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)

= \(\dfrac{11}{4}\) x \(\dfrac{2}{3}\)

= \(\dfrac{11}{6}\) 

Tính \(x\): 

  435  - [\(x\) + 16] = 425 : 17

  435 - [\(x\) + 16] = 25

          [\(x\) + 16] = 435 - 25

           \(x\) + 16 = 410

           \(x\)        = 410 - 16

          \(x\)         = 394

16:Sửa đề: \(\frac12x+\frac16\left(x-2\right)=\frac34-2x\)

=>\(\frac12x+\frac16x-\frac26=\frac34-2x\)

=>\(\frac46x-\frac13=\frac34-2x\)

=>\(\frac23x+2x=\frac34+\frac13\)

=>\(\frac83x=\frac{9}{12}+\frac{4}{12}=\frac{13}{12}\)

=>\(x=\frac{13}{12}:\frac83=\frac{13}{12}\times\frac38=\frac{13}{4\times8}=\frac{13}{32}\)

19: \(\frac{5}{12}x+3=\frac13-\frac{7}{12}x\)

=>\(\frac{5}{12}x+\frac{7}{12}x=\frac13-3\)

=>\(\frac{12}{12}x=\frac13-\frac93=-\frac83\)

=>\(x=-\frac83\)

20: \(\frac12x+\frac52=\frac72x-\frac34\)

=>\(\frac12x-\frac72x=-\frac34-\frac52\)

=>\(-3x=-\frac34-\frac{10}{4}=-\frac{13}{4}\)

=>\(3x=\frac{13}{4}\)

=>\(x=\frac{13}{4}:3=\frac{13}{12}\)

Bạn nên viết đề bằng công thức toán và ghi đầy đủ yêu cầu đề để mọi người hiểu đề của bạn hơn nhé.

Bài này là dạng bất phương trình vô tỉ ạ

`3x-16:2^3=31`

`=>3x-16:8=31`

`=>3x-2=31`

`=>3x=31+2`

`=>3x=33`

`=>x=11`

__

`2^10:2^8+3[4.7+3.4]`

`=2^2+3[4(3+7)]`

`=4+3[4.10]`

`=4+3.40`

`=4+120`

`=124`

__

`4^6:4^3-2^2 . 2^3`

`=4^3-2^5`

`=64-32`

`=32`

__

`141+2^5 . 2^4-3^1 . 3^2`

`=141+2^9-3^3`

`=141+512-9`

`=644`

__

`x+2^5:2^4=4.4^2`

`=>x+2=4^3`

`=>x=64-2`

`=>x=62`

Câu a:

x - 1: 4/3 + 9/16 = - 5^2/4^2

x - 1 x 3/4 + 9/16 = - 25/16

x - 3/4 + 9/16 = - 25/16

x - 3/4 = -25/16 - 9/16

x - 3/4 = -17/8

x = - 17/8 + 3/4

x = -11/8

Vậy x = -11/8

Câu b:

5/2x + 2 - 3 1/2 = 1/6

5/2x + 2 - 7/2 = 1/6

5/2x = 1/6 + 7/2 - 2

5/2x = 1/6 + 21/6 - 12/6

5/2x = 5/3

x = 5/3 : 5/2

x = 2/3