Tìm x
7+x/12=2/3
25-x/18=1/2
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1.8100
2. 34 x 18 + 18 x 66
= 18 x ( 34 + 66)
= 18 x 100 = 1800
3. X × ( 8 + 12) = 160 + 20 × 12
= X x 20 = 160 + 240
= X x 20 = 400
X = 400 : 20 = 20
4. X x 12 - X x 2 = 2020
(12 - 2) x X = 2020
10 x X = 2020
X = 2020 : 10 = 202
1.8100
2. 34 x 18 + 18 x 66
= 18 x ( 34 + 66)
= 18 x 100 = 1800
3. X × ( 8 + 12) = 160 + 20 × 12
= X x 20 = 160 + 240
= X x 20 = 400
X = 400 : 20 = 20
4. X x 12 - X x 2 = 2020
(12 - 2) x X = 2020
10 x X = 2020
X = 2020 : 10 = 202
\(\frac{7+x}{12}=\frac{2}{3}\)
\(=>\left(7+x\right).3=2.12\)
\(=>21+3x=24\)
\(=>3x=3\)
\(=>x=1\)
vay \(x=1\)
\(\frac{25-x}{18}=\frac{1}{2}\)
\(=>\left(25-x\right).2=18\)
\(=>50-2x=18\)
\(=>-2x=32\)
\(=>x=-16\)
vay \(x=-16\)
(-12)x7+(-8)x7+4x(-25)+(-6)x(-25)=(-12-8)x7+(-25)(4x-6x)=7x(-20)+(-25)(-2x)=-140x+50x=-90x
bài 1
a) 155 - 10.(x+1) = 55
=>10 .(x+1) = 100
=>x + 1 = 10
=>x = 9
còn lại tương tự
a, \(\frac{7+x}{12}=\frac{2}{3}\)
\(\frac{7+x}{12}=\frac{8}{12}\)
\(x=8-7\)
\(x=1\)
Bài 1:
a: \(\frac{x}{7}-\frac12=\frac{1}{y+1}\)
=>\(\frac{2x-7}{14}=\frac{1}{y+1}\)
=>(2x-7)(y+1)=14
mà 2x-7 lẻ
nên (2x-7;y+1)∈{(1;14);(-1;-14);(7;2);(-7;-2)}
=>(2x;y)∈{(8;13);(6;-15);(14;1);(0;-3)}
=>(x;y)∈{(4;13);(3;-15);(7;1);(0;-3)}
b: \(\frac{5}{x}-\frac{y}{4}=\frac18\)
=>\(\frac{5}{x}=\frac{y}{4}+\frac18=\frac{2y+1}{8}\)
=>x(2y+1)=40
mà 2y+1 lẻ
nên (x;2y+1)∈{(40;1);(-40;-1);(8;5);(-8;-5)}
=>(x;2y)∈{(40;0);(-40;-2);(8;4);(-8;-6)}
=>(x;y)∈{(40;0);(-40;-1);(8;2);(-8;-3)}
c: \(\frac{2}{y}-\frac{1}{x}=\frac{8}{xy}+1\)
=>\(\frac{2x-y}{xy}=\frac{8+xy}{xy}\)
=>xy+8=2x-y
=>xy-2x+y+8=0
=>x(y-2)+y-2+10=0
=>(x+1)(y-2)=-10
=>(x+1;y-2)∈{(1;-10);(-10;1);(-1;10);(10;-1);(2;-5);(-5;2);(-2;5);(5;-2)}
=>(x;y)∈{(0;-8);(-11;3);(-2;12);(9;1);(1;-3);(-6;4);(-3;7);(4;0)}
mà y<>0 và x<>0
nên (x;y)∈{(-11;3);(-2;12);(9;1);(1;-3);(-6;4);(-3;7)}
1.\(7+\frac{x}{12}=\frac{2}{3}\)
\(\frac{x}{12}=\frac{2}{3}-7=-\frac{19}{3}\)
\(x=-\frac{19}{3}.12=-76\)
Vậy x=-76
2.\(25-\frac{x}{18}=\frac{1}{2}\)
\(\frac{x}{18}=25-\frac{1}{2}=\frac{49}{2}\)
\(x=\frac{49}{2}.18=441\)
Vậy x=441