Câu a:

(4 5/37 - 3 4/5 + 8 15/29) - (3 5/37 - 6 14/29)

= (4 5/37 - 3 5/37) + (8 15/29 + 6 14/29) - 3 4/5

= 1 + 15 - 3 4/5

= 16 - 3 - 4/5

= 13 - 4/5

= 61/5

Câu b:

(2\(\frac56\) + 1\(\frac49\)) : (10\(\frac{1}{12}\) - 9\(\frac12\))

= (17/6 + 13/9) :(121/12 - 19/2)

= (51/18 + 26/18) :(121/12 - 114/2)

= 77/18 : 7/12

= 77/18 x 12/7

= 22/3

Câu a:

(4\(\frac{5}{37}\) - 3\(\frac45\) + 8\(\frac{15}{29}\)) - (3\(\frac{5}{37}\) - 6\(\frac{14}{29}\))

= 4\(\frac{5}{37}\) - 3\(\frac45\) + 8\(\frac{15}{29}\) - 3\(\frac{15}{37}\) + 6\(\frac{14}{29}\)

= (4 - 3) + (\(\frac{5}{37}-\frac{5}{37}\)) + (8 + 6) + (\(\frac{15}{29}\) + \(\frac{14}{29}\)) - 3 - \(\frac45\)

= 1 + 0 + 14 + 1 - 3 - \(\frac45\)

= 1 + 14 + 1 - 3 - \(\frac45\)

= 15 + 1 - 3 - \(\frac45\)

= 16 - 3 - \(\frac45\)

= 13 - \(\frac45\)

= \(\frac{61}{5}\)

\(a.=\left(\frac{153}{37}-\frac{19}{5}+\frac{199}{23}\right)-\left(\frac{116}{37}-\frac{188}{29}\right)\)

\(=\frac{153}{37}-\frac{19}{5}+\frac{199}{23}-\frac{116}{37}+\frac{188}{29}\)

\(=\frac{37}{37}-\frac{19}{5}+\frac{199}{23}+\frac{188}{29}\)tự giải tiếp ^^

\(b.=\frac{8}{3}.\frac{-15}{4}.\frac{4}{5}\)

\(=\frac{8.\left(-15\right).4}{3.4.5}\)

\(=\frac{-480}{60}=-8\)

thank u vẻ rỳ much

Help me :((

\(B=1\frac{6}{41}\cdot\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}\div\frac{4+\frac{4}{15}+\frac{4}{4}+\frac{4}{2013}}{5+\frac{5}{15}+\frac{5}{4}+\frac{5}{2013}}\right)\cdot\frac{124242423}{237373735}\)

\(B=\frac{47}{41}\cdot\left[\frac{12\left(1+\frac{1}{19}-\frac{1}{37}-\frac{1}{53}\right)}{3\left(1+\frac{1}{19}-\frac{1}{37}-\frac{1}{53}\right)}\div\frac{4\left(1+\frac{1}{15}+\frac{1}{4}+\frac{1}{2013}\right)}{5\left(1+\frac{1}{15}+\frac{1}{4}+\frac{1}{2013}\right)}\right]\cdot\frac{123}{235}\)

\(B=\frac{47}{41}\cdot\left[\frac{12}{3}\div\frac{4}{5}\right]\cdot\frac{123}{235}\)

\(B=\frac{3}{5}\cdot3\cdot\frac{5}{4}\)

\(B=\frac{9}{4}\)