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A = \(\frac{3.4+3.7}{6.5+9}\)

A = \(\frac{3.\left(4+7\right)}{3.\left(10+3\right)}\)

A = \(\frac{11}{13}\)

B = \(\frac{6.9-2.17}{63.3-119}\)

B = \(\frac{2.\left(27-17\right)}{7.\left(27-17\right)}\)

B = \(\frac27\) = \(\frac{26}{91}\)

A = \(\frac{11}{13}\) = \(\frac{77}{91}\)

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A = \(\frac{3.4+3.7}{6.5+9}\)

A = \(\frac{3.\left(4+7\right)}{3.\left(10+3\right)}\)

A = \(\frac{11}{13}\)

B = \(\frac{6.9-2.17}{63.3-119}\)

B = \(\frac{2.\left(27-17\right)}{7.\left(27-17\right)}\)

B = \(\frac27\)

A = \(\frac{11}{13}\) = \(\frac{77}{91}\)

B = \(\frac27=\frac{26}{91}\)

\(\frac{3.4+3.7}{6.5+9}\)và \(\frac{6.9-2.17}{63.3-119}\)

\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)

\(\frac{6.9-2.17}{63.3-119}=\frac{54-54}{63.3-11}=0\)

ta có:

\(\frac{3.4+3.7}{6.5+9}=\frac{3.\left(4+7\right)}{3.\left(2.5\right)+3.3}=\frac{3.\left(4+7\right)}{3.\left(2.5+3\right)}\)

\(=\frac{3.\left(4+7\right)}{3.\left(10+3\right)}=\frac{3.11}{3.13}=\frac{3}{3}.\frac{11}{13}=1.\frac{11}{13}=\frac{11}{13}\)

và \(\frac{6.9-2.17}{63.3-119}=\frac{2.\left(3.9\right)-2.17}{7.\left(9.3\right)-7.17}=\frac{2.\left(3.9-17\right)}{7.\left(9.3-17\right)}\)

\(=\frac{2}{7}.\frac{\left(3.9\right)-17}{\left(9.3\right)-17}=\frac{2}{7}.1=\frac{2}{7}\)

Vậy ta sẽ quy đồng mẫu số hai phân số: \(\frac{11}{13}\)và \(\frac{2}{7}\)(MSC: 91)

Ta có: \(\frac{11}{13}=\frac{11.7}{13.7}=\frac{77}{91}\)

và \(\frac{2}{7}=\frac{2.13}{7.13}=\frac{26}{91}\)

Ta còn quy đồng được tử số của hai phân số \(\frac{11}{13}\)và \(\frac{2}{7}\)(tử chung: 22)

ta có: \(\frac{11}{13}=\frac{11.2}{13.2}=\frac{22}{26}\)

và \(\frac{2}{7}=\frac{2.11}{7.11}=\frac{22}{77}\)

\(\frac{3.4+3.7}{6.5+9}\)

\(=\frac{3.\left(4+7\right)}{30+9}\)

\(=\frac{11}{13}\)

\(\frac{6.9-2.17}{63.3-119}\)

\(=\frac{54-34}{189-119}\)

\(=\frac{2}{7}\)

A = \(\frac{3.4+3.7}{6.5+9}\)

A = \(\frac{3.\left(4+7\right)}{3.\left(10+3\right)}\)

A = \(\frac{11}{13}\)

B = \(\frac{6.9-2.17}{63.3-119}\)

B = \(\frac{2.\left(27-17\right)}{7.\left(27-17\right)}\)

B = \(\frac27\)

A = \(\frac{11}{13}\) = \(\frac{77}{91}\)

B = \(\frac27=\frac{26}{91}\)

\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)

\(\frac{6.9-2.17}{63.3-11}=\frac{54-54}{63.3-11}=0\)

a: 27/-180=-27/180=-3/20=-21/140

-6/-35=6/35=24/120

-3/-28=3/28=15/140

b: \(\dfrac{3\cdot4+3\cdot7}{6\cdot5+9}=\dfrac{3\left(4+7\right)}{30+9}=\dfrac{11}{13}=\dfrac{2849}{13\cdot259}\)

\(\dfrac{6\cdot9-2\cdot17}{63\cdot6-119}=\dfrac{54-34}{259}=\dfrac{20}{259}=\dfrac{260}{259\cdot13}\)