Câu 2:

3x-y+10=0

=>y=3x+10

I thuộc Δ nên I(x;3x+10)

IA=IB

=>\(IA^2=IB^2\)

=>\(\left(x+1\right)^2+\left(3x+10-2\right)^2=\left(x+2\right)^2+\left(3x+10-3\right)^2\)

=>\(\left(x+1\right)^2+\left(3x+8\right)^2=\left(x+2\right)^2+\left(3x+7\right)^2\)

=>\(x^2+2x+1+9x^2+48x+64=x^2+4x+4+9x^2+42x+49\)

=>50x+65=46x+53

=>50x-46x=53-65

=>4x=-12

=>x=-3

=>\(y=3x+10=3\cdot\left(-3\right)+10=-9+10=1\)

I(-3;1); A(-1;2)

=>\(R=IA=\sqrt{\left(-1+3\right)^2+\left(2-1\right)^2}=\sqrt{2^2+1^2}=\sqrt5\)

Phương trình đường tròn (C) là:

\(\left(x+3\right)^2+\left(y-1\right)^2=R^2=5\)

1.

 \(C_{12}H_{22}O_{11}+H_2O\rightarrow C_6H_{12}O_6+C_6H_{12}O_6\)

\(C_6H_{12}O_6\xrightarrow[xt:enzim]{t^o:30-35^o}2C_2H_5OH+2CO_2\)

\(C_2H_5OH+O_2\underrightarrow{xt:men\left(giấm\right)}CH_3COOH+H_2O\)

\(CH_3COOH+C_2H_5OH\underrightarrow{H_2SO_4đặc,t^o}CH_3COOC_2H_5+H_2O\)

1.

Bài 1:

a. \(p=dh=10300\cdot36=370800\left(N/m^2\right)\)

b. \(160cm^2=0,016m^2\)

\(p=\dfrac{F}{S}\Rightarrow F=S\cdot p=0,016\cdot370800=5932,8\left(N\right)\)

Bài 2:

Ta có: \(p_2>p_1\left(1165000>875000\right)\)

\(\Rightarrow\) Tàu đăng lặn xuống, vì khi càng xuống áp suất lại càng tăng.

\(\left\{{}\begin{matrix}p'=dh'\Rightarrow h'=\dfrac{p'}{d}=\dfrac{875000}{10300}\approx84,9\left(m\right)\\p''=dh''\Rightarrow h''=\dfrac{p''}{d}=\dfrac{1165000}{10300}\approx113\left(m\right)\end{matrix}\right.\)

Bài 3:

\(20cm=0,2m\)

\(p=dh=8000\cdot\left(1,8-0,2\right)=12800\left(N/m^2\right)\)

Bài 4:

\(p=dh=10000\cdot2,8=28000\left(N/m^2\right)\)

\(150cm^2=0,015m^2\)

\(p=\dfrac{F}{S}\Rightarrow F=S\cdot p=0,015\cdot28000=420\left(N\right)\)

Hiệu điện thế hai đầu cuộn thứ cấp:

\(\dfrac{U_1}{U_2}=\dfrac{N_1}{N_2}\Rightarrow\dfrac{12}{U_2}=\dfrac{500}{50}\)

\(\Rightarrow U_2=1,2V\)

Câu 1.

\(CH_3COOH+NaOH\rightarrow CH_4\uparrow+Na_2CO_3\)

\(2CH_4\xrightarrow[LLN]{1500^oC}C_2H_2+2H_2\uparrow\)

\(C_2H_2+H_2\underrightarrow{t^o,xtPd}C_2H_4\)

a)\(C_2H_4+HBr\rightarrow C_2H_5Br\)

b)\(C_2H_4+HCl\underrightarrow{as}C_2H_5Cl\)

pt 1 và 2 bạn viết sai rồi :))