(x-34).15=0

=>x-34=0

x=0+34

x=34

18.(x-16)=18

x-16=18:18

x-16=1

x=1+16

x=17

( x - 34 ) . 15 = 0

x - 34            = 0 ; 15 ( coi x - 34 là thừa số )

x - 34           = 0

x                 = 0 + 34

x                 = 34

18. ( x - 16 ) = 18

       x - 16   =18 : 18

       x - 16   = 1

       x          = 16 + 1

       x          = 17

\(\left(x-34\right)\cdot15=0\)

\(\Leftrightarrow x-34=0\)

\(\Leftrightarrow x=34\)

a)\(\left(x-34\right).15=0\Leftrightarrow x-34=0\Leftrightarrow x=34\)

b)\(18\left(x-16\right)=18\Leftrightarrow x-16=1\Leftrightarrow x=17\)

a) x - 34 = 0 

=> x = 34

b) x - 16 = 1

=> x = 17

a, x= 34

b, x= 17

(x-34).15=0

(x-34)    =0:15

(x-34)     =0

x           =0+34

\(\Rightarrow\)x=34

18.(x-16)=18

     (x-16)=18:18

       x-16=1

\(\Rightarrow\)x=17

( x - 34 ) x 15 = 0

=> x - 34       = 0

=>       x       = 34 + 0 = 34

18 x ( x - 16 ) = 18

=> x - 16       = 1

=>        x       = 16 + 1 = 17

b: \(\Leftrightarrow x-15-27-x+x-13=-1\)

\(\Leftrightarrow x-55=-1\)

hay x=54

a) ( x - 34 ) . 15 = 0

=> x - 34 = 0 => x = 34

b) 18 . ( x - 16 ) = 18

=> x - 16 = 1 => x = 17

\(a.\left(x-34\right).15=0\Leftrightarrow x-34=\frac{0}{15}\Leftrightarrow x=34\)Vậy x là 34.

\(b.18.\left(x-16\right)=18\Leftrightarrow x-16=\frac{18}{18}\Leftrightarrow x=17\)Vậy x là 17.

d: \(\frac{3}{x}+\frac{y}{3}=\frac56\)

=>\(\frac{3}{x}=\frac56-\frac{y}{3}=\frac{5-2y}{6}\)

=>x(5-2y)=18

=>x(2y-5)=-18

mà 2y-5 lẻ và x>0

nên (x;2y-5)∈{(18;1);(2;9);(6;3)}

=>(x;2y)∈{(18;6);(2;14);(6;8)}

=>(x;y)∈{(18;3);(2;7);(6;4)}

c: \(\frac{x}{9}-\frac{3}{y}=\frac{1}{18}\)

=>\(\frac{x}{9}-\frac{1}{18}=\frac{3}{y}\)

=>\(\frac{2x-1}{18}=\frac{3}{y}\)

=>y(2x-1)=54

mà 2x-1 lẻ

nên (2x-1;y)∈{(1;54);(3;18);(9;6);(27;2)}

=>(2x;y)∈{(2;54);(4;18);(10;6);(28;2)}

=>(x;y)∈{(1;54);(2;18);(5;6);(14;2)}

b: \(\frac{x}{6}-\frac{2}{y}=\frac{1}{30}\)

=>\(\frac{x}{6}-\frac{1}{30}=\frac{2}{y}\)

=>\(\frac{5x-1}{30}=\frac{2}{y}\)

=>y(5x-1)=60

mà 5x-1 chia 5 dư 4

nên (5x-1;y)∈{(4;15)}

=>(5x;y)∈{(5;15)}

=>(x;y)∈{(1;15)}

a: \(\frac{x}{2}-\frac{4}{y}=\frac15\)

=>\(\frac{x}{2}-\frac15=\frac{4}{y}\)

=>\(\frac{5x-2}{10}=\frac{4}{y}\)

=>y(5x-2)=40

mà 5x-2 chia 5 dư 3

nên (5x-2;y)∈{(8;5)}

=>(5x;y)∈{(10;5)}

=>(x;y)∈{(2;5)}

a. |x-34|.15=0

=> |x-34|=0:15

=> |x-34|=0

=> x-34=0

=> x=0+34

=> x=34

b. 18.|x-16|=18

=> |x-16|=18:18

=> |x-16|=1

=> x-16=1       hoặc x-16=-1

=> x=1+16       hoặc x=-1+16

=> x=17           hoặc x=15 ( nếu chưa học số âm thì bỏ trường hợp này)

a. |x - 34|.15 = 0

=> |x - 34| = 0

=> x - 34 = 0

=> x = 0 + 34

=> x = 34

vậy___