a, x + 13334 = 5001

    x             = 5001 - 13334

    x             = -8333

\(f\left(x\right)=x^{312}-x^{313}+x^{314}-x^{315}+x^{446}\)

\(=\left(x^{312}-1\right)-\left(x^{313}-x\right)+\left(x^{314}-1\right)-\left(x^{315}-x\right)+\left(x^{446}-1\right)-2x+3\)

\(=\left[\left(x^2\right)^{156}-1\right]-x\left[\left(x^2\right)^{156}-1\right]+\left[\left(x^2\right)^{157}-1\right]-x\left[\left(x^2\right)^{157}-1\right]+\left[\left(x^2\right)^{223}-1\right]-2x+3\)

\(=\left(x^2-1\right)A_{\left(x\right)}-x\left(x^2-1\right)B_{\left(x\right)}+\left(x^2-1\right)C_{\left(x\right)}-x\left(x^2-1\right)D_{\left(x\right)}+\left(x^2-1\right)E_{\left(x\right)}-2x+3\)

Vậy số dư là -2x+3

a: \(3636:\left(12\cdot x-91\right)=36\)

=>\(12x-91=\frac{3636}{36}=101\)

=>12x=91+101=192

=>\(x=\frac{192}{12}=16\)

b: \(446+2\cdot\left(125-x\right)=546\)

=>\(2\left(125-x\right)=546-446=100\)

=>125-x=50

=>x=125-50=75

c: \(\left(x-36\right):18=10+2\)

=>\(\left(x-36\right):18=12\)

=>\(x-36=18\cdot12=216\)

=>x=216+36=252

• x-96=466-x-150          ​                                                     
• x-96-466+x+150=0
• 2x-412=0
• 2x=412
• x=206
• vậy...

x-96=(446-x)-150

x-96=446-x-150

x+x=96+446-150

2x=392

x=392:2

x=196

Vậy x=196

Học tốt!

#Huyền#

\(345:5.131\)

\(=69.131\)

\(=9039\)

Học Tốt

\(2423:3-446\)

\(=807,666667-446\)

\(=360,666667\)

Học Tốt

Ta có: 3636:(12x−91)=36

12x–91=3636:36

12x–91=101

12x=101+91

12x=192

x=192:12

x=16

Vậy x=16

440 + 2. (125 – x) = 546

2. (125 - x)=546 - 440

2. (125 - x)=106

125 - x=106 : 2

125 - x=53

x=125-53

x=72

a, 324 489 + 446 357

b, 986 769 – 342 538

c, 287 x 24

d, 13068 : 27

ai bít

1223 63808

hết nha chúc bạn

bạn vào đây xem câu trả lời

https://www.youtube.com/watch?v=fvGaHwKrbUc

562=2x281

446=2x223

123=3x41

ƯCLN(562;446;123)=1