Rút gọn biểu thức sau: A=(2x+3)^2+(3x-2)^2+2(2x+3)(3x-2)
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a) \(\left(3x-2\right)^2-\left(2x+3\right)\left(2x-3\right)\)
\(=9x^2-12x+4-4x^2+9\)
\(=5x^2-12x+13\)
b) \(3x\left(5x-2\right)-\left(2x^2-1\right)\left(2-x\right)\)
\(=15x^2-6x-\left(4x^2-2x^3-2+x\right)\)
\(=15x^2-6x-4x^2+2x^3+2-x\)
\(=11x^2-7x+2x^3+2\)
( 2x - 3 )( 2x + 3 ) - ( 3x - 4 )2 + ( 2x + 3 )2
= 4x2 - 9 - ( 9x2 - 24x + 16 ) + 4x2 + 12x + 9
= 8x2 + 12x - 9x2 + 24x - 16
= -x2 + 36x - 16
`Answer:`
`a)`
`A=5(x+1)^2-3(x-3)^2-4(x^2-4)`
`=>A=5(x^2+2x+1)-3(x^2-6x+9)-4x^2+16`
`=>A=5x^2+10x+5-3x^2+18x-27-4x^2+16`
`=>A=(5x^2-3x^2-4x^2)+(10x+18x)+(5-27+16)`
`=>A=-2x^2+28x-6`
`b)`
`B=5(x+1)^2-3(x-3)^2-4(x+2)(x-2)`
`=2x(3x+5)-3(3x+5)-2x(x^2-4x+4)-[(2x)^2-3^2]`
`=6x^2+10x-9x-15-2x^3+8x^2-8x-4x^2+9`
`=(6x^2-4x^2+8x^2)-2x^3+(10x-9x-8x)+(-15+9)`
Thay `x=-7` vào ta được:
`B=10(-7)^2-2(-7)^3-7(-7)-6`
`=>B=10.49-2(-343)+49-6`
`=>B=490+686+49-6`
`=>B=1219`
a: Đặt A=3(5x-2)-|x-5|
TH1: x>=5
=>x-5>=0
A=3(5x-2)-|x-5|
=15x-6-(x-5)
=15x-6-x+5
=14x-1
TH2: x<5
=>x-5<0
A=3(5x-2)-|x-5|
=15x-6-(5-x)
=15x-6-5+x
=16x-11
b: Đặt B=|2x+3|+2x+7
TH1: x>=-3/2
=>2x+3>=0
B=|2x+3|+2x+7
=2x+3+2x+7
=4x+10
TH2: x<-3/2
=>2x+3<0
B=|2x+3|+2x+7
=-2x-3+2x+7
=4
c: đặt C=3x-1+|1-3x|
=3x-1+|3x-1|
TH1: x>=1/3
=>3x-1>=0
C=3x-1+|3x-1|
=3x-1+3x-1
=6x-2
TH2: x<1/3
=>3x-1<0
C=3x-1+|3x-1|
=3x-1+1-3x
=0
d: Đặt D=3(x-1)-2|x+3|
TH1: x>=-3
=>x+3>=0
D=3(x-1)-2|x+3|
=3(x-1)-2(x+3)
=3x-3-2x-6
=x-9
TH2: x<-3
=>x+3<0
D=3(x-1)-2|x+3|
=3x-3-2(-x-3)
=3x-3+2x+6
=5x+3
a: A=(4x+5)^2-2*(4x+5)(4x-5)+(4x-5)^2
=(4x+5-4x+5)^2
=10^2=100
b: B=(3x-2)^2*(3x+2)^2-2(2x+3)(2x-3)
=(9x^2-4)^2-2(4x^2-9)
=81x^4-72x^2+16-8x^2+18
=81x^4-80x^2+34
\(a,A=\left(4x-5\right)^2+\left(4x+5\right)^2+2\left(5+4x\right)\left(5-4x\right)\)
\(=\left(5-4x\right)^2 +2\left(5-4x\right)\left(4x+5\right)+\left(4x+5\right)^2\)
\(=\left(5-4x+4x+5\right)^2\)
\(=10^2\)
\(=100\)
\(b,B=\left(3x-2\right)^2\left(3x+2\right)^2-2\left(2x+3\right)\left(2x-3\right)\)
\(=\left(9x^2-4\right)^2-2\left(4x^2-9\right)\)
\(=81x^4-72x^2+16-8x^2+18\)
\(=81x^4-80x^2+34\)
#\(Urushi\)
\(a,=x^2+6x+9+2x^2+5xy^2=3x^2+6x+5xy^2+9\\ b,=9x^2-12x+4-9x^2+1=-12x+5\)
Câu 1:
a) 2x(3x+2) - 3x(2x+3) = 6x^2+4x - 6x^2-9x = -5x
b) \(\left(x+2\right)^3+\left(x-3\right)^2-x^2\left(x+5\right)\)
\(=x^3+6x^2+12x+8+x^2-6x+9-x^3-5x^2\)
\(=2x^2+6x+17\)
c) \(\left(3x^3-4x^2+6x\right)\div\left(3x\right)=x^2-\dfrac{4}{3}x+2\)
A = (2x + 3)2 + (3x - 2)2 + 2(2x + 3)(3x - 2) = (2x + 3 + 3x - 2)2 = (5x + 1)2