A=-2/9+(-3)/4+3/5+1/15+1/57+1/3-1/36
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HN
3
BT
1
NL
Nguyễn Lê Phước Thịnh
CTVHS
28 tháng 1 2024
\(\dfrac{-2}{9}-\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{1}{15}+\dfrac{1}{57}+\dfrac{1}{3}-\dfrac{1}{36}\)
\(=\left(-\dfrac{2}{9}-\dfrac{3}{4}-\dfrac{1}{36}\right)+\left(\dfrac{3}{5}+\dfrac{1}{15}+\dfrac{1}{3}\right)+\dfrac{1}{57}\)
\(=\dfrac{-8-27-1}{36}+\dfrac{9+1+5}{15}+\dfrac{1}{57}\)
\(=-\dfrac{36}{36}+\dfrac{15}{15}+\dfrac{1}{57}\)
\(=\dfrac{1}{57}\)
6 tháng 3 2017
A=\(\dfrac{-2}{9}\)+\(\dfrac{-3}{4}\)+\(\dfrac{3}{5}\)+\(\dfrac{1}{15}\)+\(\dfrac{1}{57}\)+\(\dfrac{1}{3}\)+\(\dfrac{-1}{36}\)
A=(\(\dfrac{-2}{9}\)+\(\dfrac{-3}{4}\)+\(\dfrac{-1}{36}\))+(\(\dfrac{3}{5}\)+\(\dfrac{1}{15}\)+\(\dfrac{1}{3}\))
A=-1+1=0
B=\(\dfrac{1}{2}\)+\(\dfrac{-1}{5}\)+\(\dfrac{-5}{7}\)+\(\dfrac{1}{6}\)+\(\dfrac{-3}{35}\)+\(\dfrac{1}{3}\)+\(\dfrac{1}{41}\)
B=(\(\dfrac{-1}{5}\)+\(\dfrac{-5}{7}\)+\(\dfrac{-3}{35}\))+(\(\dfrac{1}{2}\)+\(\dfrac{1}{6}\)+\(\dfrac{1}{3}\))+\(\dfrac{1}{41}\)
B=-1+1+\(\dfrac{1}{41}\)=\(\dfrac{1}{41}\)
4 tháng 5 2020
câu 1 : A=-2/9+-3/4+3/5+1/15+1/57+1/3+-1/36
=(-2/9+-3/4+-1/36)+(3/5+1/15+1/3)
Vậy p/s 1/57 đâu bạn ?
IL
0
U
11 tháng 8 2018
\(A=\frac{-2}{9}+\frac{-3}{4}+\frac{3}{5}+\frac{1}{15}+\frac{1}{57}+\frac{1}{3}+\frac{-1}{36}\)
\(A=\left(\frac{-2}{9}+\frac{-3}{4}+\frac{1}{3}+\frac{-1}{36}\right)+\left(\frac{3}{5}+\frac{1}{15}\right)+\frac{1}{57}\)
\(A=\left(\frac{-8}{36}+\frac{-27}{36}+\frac{12}{36}+\frac{-1}{36}\right)+\left(\frac{9}{15}+\frac{1}{15}\right)+\frac{1}{57}\)
\(A=\frac{-2}{3}+\frac{2}{3}+\frac{1}{57}\)
\(A=\frac{-38}{57}+\frac{38}{57}+\frac{1}{57}\)
\(A=\frac{1}{57}\)
NL
Nguyễn Lê Phước Thịnh
CTVHS
30 tháng 1
a: Ta có: \(A=\frac{-2}{9}+\frac{-3}{4}+\frac35+\frac{1}{15}+\frac{1}{57}+\frac13+\frac{-1}{36}\)
\(=\left(-\frac29-\frac34-\frac{1}{36}\right)+\left(\frac35+\frac{1}{15}+\frac13\right)+\frac{1}{57}\)
\(=\left(-\frac{8}{36}-\frac{27}{36}-\frac{1}{36}\right)+\left(\frac{9}{15}+\frac{1}{15}+\frac{5}{15}\right)+\frac{1}{57}\)
\(=-1+1+\frac{1}{57}=\frac{1}{57}\)
b: \(B=\frac12+\frac{-1}{5}+\frac{-5}{7}+\frac16+\frac{-3}{35}+\frac13+\frac{1}{41}\)
\(=\left(\frac12+\frac13+\frac16\right)-\left(\frac15+\frac57+\frac{3}{35}\right)+\frac{1}{41}\)
\(=\left(\frac36+\frac26+\frac16\right)-\left(\frac{7}{35}+\frac{25}{35}+\frac{3}{35}\right)+\frac{1}{41}\)
\(=1-1+\frac{1}{41}=\frac{1}{41}\)
c: \(C=\frac{-1}{2}+\frac35+\frac{-1}{9}+\frac{1}{127}+\frac{-7}{18}+\frac{4}{35}+\frac27\)
\(=\left(-\frac12-\frac19-\frac{7}{18}\right)+\left(\frac35+\frac27+\frac{4}{35}\right)+\frac{1}{127}\)
\(=\left(-\frac{9}{18}-\frac{2}{18}-\frac{7}{18}\right)+\left(\frac{21}{35}+\frac{10}{35}+\frac{4}{35}\right)+\frac{1}{127}\)
\(=-1+1+\frac{1}{127}=\frac{1}{127}\)
A=−29+−34+35+115+157+13−136A=-29+-34+35+115+157+13-136
→A=(−29+−34+13−136)+(35+115)+157→A=(-29+-34+13-136)+(35+115)+157
→A=(
Gọi ƯCLN(12n+1,30n+2)=d(d>0,d∈Z)ƯCLN(12n+1,30n+2)=d(d>0,d∈Z)
⇒12n+1⋮d,30n+2⋮d⇒12n+1⋮d,30n+2⋮d
⇒60n+5⋮d,60n+4⋮d⇒60n+5⋮d,60n+4⋮d
⇒60n+5−60n−4⋮d⇒60n+5-60n-4⋮d
⇒1⋮d⇒1⋮d
⇒d∈Ư(1)={1,−1}⇒d∈Ư(1)={1,-1}
⇒12n+130n+2
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