a/ 5;4;3;2;1;0;-1;-2;-3

b/x<0 hoac x>4022

a) \(\left|x-1\right|\le4\)

Vì \(\left|x-1\right|\ge0\)

\(\Rightarrow\left|x-1\right|\in\left\{0;1;2;3;4\right\}\)

Xét bảng sau

Vậy \(x\in\left\{1;2;0;3;-1;4;-2;5;-3\right\}\)

Hình như sai đề bài

<=> \(\frac{\left(x+2014\right)}{2011}+1+\frac{\left(x+2013\right)}{2012}+1=\frac{\left(x+2012\right)}{2013}+1+\frac{\left(x+2011\right)}{2014}+1\)

\(\Rightarrow\frac{\left(x+4025\right)}{2011}+\frac{\left(x+4025\right)}{2012}=\frac{\left(x+4025\right)}{2013}+\frac{\left(x+4025\right)}{2014}\)

=> \(\frac{\left(x+4025\right)}{2011}+\frac{\left(x+4025\right)}{2012}-\frac{\left(x+4025\right)}{2013}-\frac{\left(x+4025\right)}{2014}=0\)

=> \(\left(x+4025\right)\left\lbrack\left(\frac{1}{2011}+\frac{1}{2012}\right)-\left(\frac{1}{2013}+\frac{1}{2014}\right)\right\rbrack=0\)

vì \(\left(\frac{1}{2011}+\frac{1}{2012}\right)>\left(\frac{1}{2013}+\frac{1}{2014}\right)\)

=> \(\left\lbrack\left(\frac{1}{2011}+\frac{1}{2012}\right)-\left(\frac{1}{2013}+\frac{1}{2014}\right)\right\rbrack>0\) hay ≠0

=> \(x+4025=0\)

\(x=-4025\)

a) x thuộc [-3;-2;-1;0;1;2;3;4;5]                                                                                              b) không biết

suy ra hai truong hop

1 : x-2011=x-2012

suy ra x-x=2011-2012(loai)

2 : x-2011=-(x-2012)

suy ra : x-2011=-x+2012                                

2x=2011+2012

2x=4023

x=2011.5

kho..................lam............................tich,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,minh..........................troi........................ret............................wa.................ung ho minh.................hu....................hu..............hu................hat..............hat....................s