321 x 3 + 321 x 5 + 321 x 2

= 321 x (3 + 5 + 2)

= 321 x 10

= 3 210.

321 x 3 + 321 x 5 + 321 x 2

= 321 x (3 + 5 + 2)

= 321 x 10

= 3210

=26x74+26x26-40x58

=26x100-100x23.2

=100x2.8

=280

=1605

a, 71-(33+x)=26

33+x=71-26

33+x=45

x=45-33

x=12

Vậy x=12

\(71-\left(33+x\right)=26\\ \left(33+x\right)=71-26\\ \left(33+x\right)=45\\ x=45-33\\ x=12\)

Ta có: \(\left\{{}\begin{matrix}p+e+n=82\\p=e\\p+e=52\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}p=e=26\\n=30\end{matrix}\right.\)

 ⇒ Chọn C

???????????????????????????

nope :v

64 X 52 + 37 X 52 - 2 X 26

= 64 X 52 + 37 X 52 - 52

= 52 X ( 64 + 37 - 1)

= 52 X 100

= 5200

 64 x 52 + 37 x 52 - 2 x 26

=64 x 52 + 37 x 52 - 52 x 1

=52 x ( 64 + 37 -1 )

=52 x 100

=5200

tk nhé

A) x/13+15/26=46/52

x/13+15/26=23/26

x/13=23/26-15/26

x/13=4/13

x=4

7/3:5/1=14/15

a: \(x-\frac13x+\frac15x=-\frac{26}{5}\)

=>\(x\left(1-\frac13+\frac15\right)=-\frac{26}{5}\)

=>\(x\left(\frac23+\frac15\right)=-\frac{26}{5}\)

=>\(x\cdot\left(\frac{10}{15}+\frac{3}{15}\right)=-\frac{26}{5}\)

=>\(x\cdot\frac{13}{15}=-\frac{26}{5}\)

=>\(x=-\frac{26}{5}:\frac{13}{15}=-\frac{26}{5}\cdot\frac{15}{13}=-2\cdot3=-6\)

b: \(\frac23\left(x+\frac95\right)-\frac{3}{10}\left(5x-\frac13\right)=\frac{7}{15}\)

=>\(\frac23x+\frac{18}{15}-\frac32x+\frac{1}{10}=\frac{7}{15}\)

=>\(\frac{-5}{6}x+\frac65+\frac{1}{10}=\frac{7}{15}\)

=>\(-\frac56x+\frac{13}{10}=\frac{7}{15}\)

=>\(-\frac56x=\frac{7}{15}-\frac{13}{10}=\frac{14}{30}-\frac{39}{30}=\frac{-25}{30}=-\frac56\)

=>x=1