\(x\cdot x\cdot x\) hay \(x+x+x\)??

Ý là x nhân x = 16 á giúp mk :<

\(\left(x+1\right)^{x+3}=\left(x+1\right)^{x+1}\)

\(\Leftrightarrow\left(x+1\right)^{x+1}\cdot x\cdot\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=0\\x=-2\end{matrix}\right.\)

\(\Leftrightarrow164-4\left(x-5\right)=80\\ \Leftrightarrow4\left(x-5\right)=84\\ \Leftrightarrow x-5=21\Leftrightarrow x=26\)

0,4 : \(x\) = 1,6 - 0,5 : \(x\)

0,5 : \(x\) + 0,4 : \(x\) = 1,6

(0,5 + 0,4) :    \(x\) =  1,6 

              0,9 : \(x\) = 1,6

                     \(x\) = 0,9 : 1,6

                     \(x\) = 0,5625

help me: tìm n biết 2^n + 3^n = 5^n với n E N

\(\Leftrightarrow100x-5050=5550\)

hay x=106

a: ĐKXĐ: x∉{1;-1;2}

\(P=\left(\frac{x}{x+1}-\frac{1}{1-x}+\frac{1}{1-x^2}\right):\frac{x-2}{x^2-1}\)

\(=\left(\frac{x}{x+1}+\frac{1}{x-1}-\frac{1}{\left(x-1\right)\left(x+1\right)}\right)\cdot\frac{\left(x-1\right)\left(x+1\right)}{x-2}\)

\(=\frac{x\left(x-1\right)+x+1-1}{\left(x-1\right)\left(x+1\right)}\cdot\frac{\left(x-1\right)\left(x+1\right)}{x-2}\)

\(=\frac{x^2-x+x}{x-2}=\frac{x^2}{x-2}\)

b: Để P nguyên thì \(x^2\) ⋮x-2

=>\(x^2-4+4\) ⋮x-2

=>4⋮x-2

=>x-2∈{1;-1;2;-2;4;-4}

=>x∈{3;1;4;0;6;-2}

Kết hợp ĐKXĐ, ta được: x∈{3;4;0;6;-2}

c: \(P=\frac{x^2}{x-2}\)

\(=\frac{x^2-4+4}{x-2}=x+2+\frac{4}{x-2}=x-2+\frac{4}{x-2}+4\ge2\cdot\sqrt{\left(x-2\right)\cdot\frac{4}{x-2}}+4\)

=>P>=2*2+4=8

Dấu '=' xảy ra khi \(\left(x-2\right)^2=4\)

=>x-2=2

=>x=4(nhận)

\(x.2+x.8=250\\ x.\left(2+8\right)=250\\ x.10=250\\ x=250:10\\ x-25\\ \Rightarrow x=25\)

dấu chấm là nhân

X x(2+8)=250

X x 10=250

X       =250:10

X       =25

\(\left(390:x-90:x\right)=3\)
\(\Rightarrow\left(390-90\right):x=3\)
\(\Rightarrow300:x=3\)
\(\Rightarrow x=300:3\)
\(\Rightarrow100\)

(390:x-90:x)=3

(390-90):x=3

300:x=3

x=300:3

x=100

=>5x+20-3x+6=x

=>2x+26=x

=>x=-26

cảm ơn nha