\(2+\left(x.\frac{1}{4}\right)=\frac{3}{5}\)

=> \(\left(x.\frac{1}{4}\right)=\frac{3}{5}-2\)

=> \(x.\frac{1}{4}=-\frac{7}{5}\)

=> \(x=\left(-\frac{7}{5}\right):\frac{1}{4}\)

=> \(x=-\frac{28}{5}\)

Vậy \(x=-\frac{28}{5}.\)

\(\frac{5}{6}:\left(\frac{2}{3}.x\right)=\frac{20}{3}\)

=> \(\left(\frac{2}{3}.x\right)=\frac{5}{6}:\frac{20}{3}\)

=> \(\frac{2}{3}.x=\frac{1}{8}\)

=> \(x=\frac{1}{8}:\frac{2}{3}\)

=> \(x=\frac{3}{16}\)

Vậy \(x=\frac{3}{16}.\)

Chúc bạn học tốt!

2+(x.\(\frac{1}{4}\))=\(\frac{3}{5}\)

=>x.\(\frac{1}{4}\)=\(\frac{3}{5}\)-2

=>x.\(\frac{1}{4}\)=\(\frac{-7}{5}\)

=>x=\(\frac{-7}{5}\):\(\frac{1}{4}\)

=>x=\(\frac{-28}{5}\)

\(\frac{5}{6}\):(\(\frac{2}{3}\).x)=\(\frac{20}{3}\)

\(\frac{2}{3}\).x=\(\frac{5}{6}\):\(\frac{20}{3}\)

\(\frac{2}{3}\).x=\(\frac{1}{8}\)

x=\(\frac{1}{8}\):\(\frac{2}{3}\)

x=\(\frac{3}{16}\)

\(\frac{x}{5}=\frac23\)

\(x\) = \(\frac23\times5\)

\(x=\frac{10}{3}\)

Vậy \(x=\frac{10}{3}\)

\(\frac{x}{3}-\frac12=\frac15\)

\(\frac{x}{3}\) = \(\frac15\) + \(\frac12\)

\(\frac{x}{3}\) = \(\frac{2}{10}+\frac{5}{10}\)

\(\frac{x}{3}=\frac{7}{10}\)

\(x=\frac{7}{10}\times3\)

\(x=\frac{21}{10}\)

Vậy \(x=\frac{21}{10}\)

\(\frac{x}{5}+\frac12=\frac{6}{10}\)

\(\frac{x}{5}=\frac{6}{10}-\frac12\)

\(\frac{x}{5}=\frac{6}{10}-\frac{5}{10}\)

\(\frac{x}{5}=\frac{1}{10}\)

\(x=\frac{1}{10}\times5\)

\(x=\frac12\)

Vậy \(x=\frac12\)

\(\frac{x+3}{15}\) = \(\frac13\)

\(x+3=\frac13\times15\)

\(x+3=5\)

\(x=5-3\)

\(x=2\)

Vậy \(x=2\)

a)\(\frac{3}{4}+\frac{1}{4}:x=-3\)

                \(\frac{1}{4}:x=-3-\frac{3}{4}\)

                 \(\frac{1}{4}:x=\frac{-15}{4}\)

                        \(x=\frac{1}{4}:\frac{-15}{4}\)

                        \(x=\frac{-1}{15}\)

b)         \(\frac{-5}{x}=\frac{20}{28}\)

 \(\Rightarrow\)\(-5:x=\frac{20}{28}\)

                   \(x=-5:\frac{20}{28}\)

                   \(x=-7\)

c)\(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)

   \(\frac{2}{3}x\)          \(=\frac{1}{10}+\frac{1}{2}\)

   \(\frac{2}{3}x\)          \(=\frac{6}{10}\)

        \(x\)          \(=\frac{6}{10}:\frac{2}{3}\)

        \(x\)          \(=\frac{9}{10}\)

d)\(1\frac{2}{9}x+\frac{8}{3}=\frac{-2}{3}\)

   \(1\frac{2}{9}x\)        \(=\frac{-2}{3}-\frac{8}{3}\)

   \(1\frac{2}{9}x\)        \(=\frac{-10}{3}\)

           \(x\)        \(=\frac{-10}{3}:1\frac{2}{9}\)

           \(x\)        \(=\frac{-30}{11}\)

Câu Cuối)\(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)

\(\Rightarrow\)     \(x:2-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)

              \(x:2-\frac{11}{5}=\frac{448}{392}\)

              \(x:2\)           \(=\frac{448}{392}+\frac{11}{5}\)

              \(x:2\)           \(=\frac{117}{35}\)

              \(x\)               \(=\frac{117}{35}.2\)

              \(x\)               \(=\frac{234}{35}\)

Bạn cho mình 1 .

Chúc bạn học tốt .

đếch giúp!ai bảo câu hỏi của ngọc trả lời ko tử tế cơ!thằng nào ngu như mày thì thằng đó chết nhe răng giống mày!

a) = 3/3 x ( -24/54 +45/54 ) : 7/12

   = 1 x 21/54 x 12/7

   = 18/27 

( hiện tại mik chỉ lm đc thế này thui. thông cảm nk )

S = \(\frac12\times\frac13\) + \(\frac13\times\frac14\) + \(\frac14\times\frac15\) + \(\frac15\times\frac16\) + \(\frac17\times\frac18\) + \(\frac18\times\frac19\)

S = \(\frac12\) - \(\frac13\) + \(\frac13\) - \(\frac14\) + \(\frac14\) - \(\frac15\) + \(\frac15\) - \(\frac16\) + \(\frac17\) - \(\frac18\) + \(\frac18\) - \(\frac19\)

S = \(\frac12\) - \(\frac19\)

S = \(\frac{9}{18}-\frac{2}{18}\)

S = \(\frac{7}{18}\)

0,7.2\(\frac23\).20.0,375.\(\frac{5}{28}\)

= \(\frac{7}{10}\) .\(\frac83\).20.\(\frac38\).\(\frac{5}{28}\)

= (\(\frac{7}{10}\).\(\frac{5}{28}\).20).(\(\frac83\).\(\frac38\))

= (\(\frac18.20\)). 1

= \(\frac52\)

B = (9,75 .21\(\frac37\) + \(\frac{39}{4}\).18\(\frac47\))

B = (\(\frac{39}{4}\).\(\frac{150}{7}\frac{}{7}\)+ \(\frac{39}{4}\).\(\frac{130}{7}\))

B = \(\frac{39}{4}\).(\(\frac{150}{7}\) + \(\frac{130}{7}\))

B = \(\frac{39}{4}\).\(\frac{280}{7}\)

B = 390

a) \(\frac{9}{20}\)                                                   c) \(\frac{-55}{4}\)                                                                                                                                 

b) \(\frac{116}{75}\)                                                d) \(\frac{-76}{45}\)

đúng hết đấy nhé mình tính kĩ lắm ko sai đâu

       chúc may mắn

|\(\frac32x\) + \(\frac12\)| = |4\(x\) - 1|

\(\left[\begin{array}{l}\frac32x+\frac12=-4x+1\\ \frac32x+\frac12=4x-1\end{array}\right.\)

\(\left[\begin{array}{l}\frac32x+4x=1-\frac12\\ \frac32x-4x=-1-\frac12\end{array}\right.\)

\(\left[\begin{array}{l}\frac{11}{2}x=\frac12\\ -\frac52x=-\frac32\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12:\frac{11}{2}\\ x=-\frac32:\frac{-5}{2}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12\times\frac{2}{11}\\ x=-\frac32\times\frac{-2}{5}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{1}{11}\\ x=\frac35\end{array}\right.\)

Vậy \(x\in\) {\(\frac{1}{11};\frac35\)}

|\(\frac54x\) - \(\frac72\)| - |\(\frac58x\) + \(\frac35\)| = 0

|\(\frac54x\) - \(\frac72\)| = |\(\frac58x\) + \(\frac35\)|

\(\left[\begin{array}{l}\frac54x-\frac72=-\frac58x-\frac35\\ \frac54x-\frac72=\frac58x+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac54x+\frac58x=\frac72-\frac35\\ \frac54x-\frac58x=\frac72+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac{15}{8}x=\frac{29}{20}\\ \frac58x=\frac{41}{10}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{29}{10}:\frac{15}{8}\\ x=\frac{41}{10}:\frac58\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{116}{75}\\ x=\frac{164}{25}\end{array}\right.\)

Vậy \(x\in\) {\(\frac{116}{75}\); \(\frac{164}{25}\)}

a) \(2x-\frac{2}{3}-7x=\frac{3}{2}-1\\ 2x-7x-\frac{2}{3}=\frac{1}{2}\\ -5x=\frac{1}{2}+\frac{2}{3}\\ -5x=\frac{7}{6}\\ x=\frac{7}{6}:\left(-5\right)\\ x=\frac{-7}{30}\)Vậy \(x=\frac{-7}{30}\)

b) \(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\\ \frac{3}{2}x-\frac{1}{3}x=\frac{2}{5}-\frac{1}{4}\\ \frac{7}{6}x=\frac{3}{20}\\ x=\frac{3}{20}:\frac{7}{6}\\ x=\frac{9}{70}\)Vậy \(x=\frac{9}{70}\)

c) \(\frac{2}{3}-\frac{5}{3}x=\frac{7}{10}x+\frac{5}{6}\\ \frac{2}{3}-\frac{5}{6}=\frac{7}{10}x+\frac{5}{3}x\\ \frac{-1}{6}=\frac{71}{30}x\\ x=\frac{-1}{6}:\frac{71}{30}\\ x=\frac{-5}{71}\)Vậy \(x=\frac{-5}{71}\)

d) \(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\\ 2x+\frac{1}{2}x=\frac{5}{6}+\frac{1}{4}\\ \frac{5}{2}x=\frac{13}{12}\\ x=\frac{13}{12}:\frac{5}{2}\\ x=\frac{13}{30}\)Vậy \(x=\frac{13}{30}\)

e) \(3x-\frac{5}{3}=x-\frac{1}{4}\\ 3x-x=\frac{5}{3}-\frac{1}{4}\\ 2x=\frac{17}{12}\\ x=\frac{17}{12}:2\\ x=\frac{17}{24}\)Vậy \(x=\frac{17}{24}\)

Èo, chăm thế? Chăm hơn cả mik cơ, gần 11 h rồi onl thì thấy bài được bạn HISI làm hết rồi :((