x+2x+3x+4x+...+100x=6060

x.(1+2+3+4+...+100) = 6060

x.5050 = 6060

x = 6/5

vt = X x (1+2+3+4+...+100)=6060

mà 1+2+3+...+100 = 100x(100+10) :2

=5050

thay vào vt =>5050X =6060 

vậy x =\(\frac{6}{5}\)

6: \(9,5\times4,7+9,5\times4,3+9,5\)

\(=9,5\times\left(4,7+4,3+1\right)\)

\(=9,5\times10=95\)

5: \(32\times1,25\times2,5+0,476+0,524\)

\(=80\times1,25+1\)

=100+1

=101

4: \(3,5\times0,5+3,5\times0,125+3,5\times22,5\times4\)

=3,5x(90+0,5+0,125)

=3,5x90,625

=317,1875

3: \(32\times1,25\times2,5+\frac{54}{10}\times8,7+5,4\times3,3-10,8\)

\(=40\times2,5+5,4\times8,7+5,4\times3,3-5,4\times2\)

=100+5,4x(8,7+3,3-2)

=100+5,4x10

=100+54

=154

2: \(15,25\times0,5+15,25\times0,25+15,25\times0,125+15,25\times6\)

=15,25x(0,5+0,25+0,125+6)

=15,25x6,875

=104,84375

1: 2020x0,56+0,34x6060+8080x0,85+2020x5,02

=2020x0,56+2020x1,02+2020x3,4+2020x5,02

=2020x(0,56+1,02+3,4+5,02)

=2020x10

=20200

\(6060:\frac{50x+20}{x}=101\)

\(\frac{50x+20}{x}=60\)

\(50x+20=60x\)

\(10x=20\)

\(x=2\)

\(6060:\frac{50x+20}{x}=101\)

\(\frac{50x+20}{x}=6060:101\)

\(\frac{50x+20}{x}=60\)

\(50x+20=60x\)

\(10x=20\)

\(x=2\)

\(60x-50x=20\)

= 2020 x 0,56 + 0,34 x 3 x 2020 + 2020 x 4 x 0,85 + 2020 x 5,02

= 2020 x 0,56 + 1,02 x 2020 + 2020 x 3,4 + 2020 x 5,02

= 2020 x ( 0,56 + 1,02 + 3,4 + 5,02 )

= 2020 x ( 1,58 + 3,4 + 5,02 )

= 2020 x ( 4,98 + 5,02 )

= 2020 x 10

= 20202

         ------------------Hết------------------       

Tính theo tính nhanh_________

 2020 x 0,56 + 0,36 x 6060 + 8080 x 0,85 + 2020 x 5,02 

=1131,2+2181,6+6868+10140,4 

=20321,2

   2020 x 0,56 +0,36x6060+8080x0,85+2020x5,02

=2020 x 0,56 +0,36x3x2020+4x2020x0,85+2020x5,02

=2020 x 0,56 +1,08x2020+3,4x2020+2020x5,02

=2020x(0,56+1,08+3,4+5,02)

= 2020x10,06

=20321.2

A.   \(\left(x+1\right)+\left(x+2\right)+......+\left(x+100\right)=5750\)

      \(x+1+x+2+....+x+100=5750\)

      \(100x+\left(1+2+3+.......+100\right)=5750\)

      \(100x+5050=5750\)

\(100x=700\)

\(x=700:100=7\)

B.   x+(1+2+......+100) = 2000

       x + 5050 = 2000

            x = 2000 - 5050

           x= -3050

C.   ( x-1 )+(x-2)+......+( x - 100 ) = 50

 x-1+x-2+.........+x-100 = 50

100x + ( -1-2-........-100  ) = 50

100x + ( - 5050 ) = 50

100x = 50 + 5050

100 x = 5100

x = 5100 : 100

x = 51

A . \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)

\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)

\(100x+5050=5750\)

\(100x=5750-5050\)

\(100x=700\)

\(\Rightarrow x=\frac{700}{100}=7\)

B. \(x+\left(1+2+3+4+5+....+100\right)=2000\)

 \(x+\frac{\left(100+1\right).100}{2}=2000\)

\(x+5050=2000\)

\(\Rightarrow x=2000-5050=-3050\)

C. \(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)+....+\left(x-100\right)=50\)

\(\left(x+x+x+...+x\right)-\left(1+2+3+...+100\right)=50\)

\(100x-5050=50\)

\(100x=5100\)

\(\Rightarrow x=\frac{5100}{100}=51\)