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\(\frac{1}{2}=\frac{3}{-6}\)vì \(1.-6=3.2\)
Các câu sau tương tự vậy ấy
Tk mk nha
Ta xét A= \(\frac{1}{5^2}+\frac{1}{6^2}+..+\frac{1}{100^2}\)
\(\frac{1}{5^2}+\frac{1}{6^2}+...+\frac{1}{100^2}>\frac{1}{5.6}+\frac{1}{6.7}...+\frac{1}{100.101}\)
=> \(A>\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{100}-\frac{1}{101}\)
=> \(A>\frac{1}{5}-\frac{1}{101}\)
=> \(A>\frac{96}{505}>\frac{96}{576}=\frac{1}{4}\)
Ta có : \(A< \frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{99.100}\)
=> \(A< \frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{99}-\frac{1}{100}\)
=> \(A< \frac{1}{4}-\frac{1}{100}\)
=> \(A< \frac{6}{25}< \frac{6}{24}=\frac{1}{4}\)
a
\(5\frac{4}{7}:x+=13\)
\(\frac{39}{7}:x=13\)
\(x=\frac{39}{7}:13\)
\(x=\frac{3}{7}\)
\(\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=1\)
\(x=1:\frac{4}{7}\)
\(x=\frac{7}{4}=1\frac{3}{4}\)
a) \(\left(-\frac{3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-9}{4}\right):\frac{3}{7}\)
= \(\left(-\frac{3}{4}+\frac{2}{5}\right)\cdot\frac{7}{3}+\left(\frac{3}{5}+\frac{-9}{4}\right)\cdot\frac{7}{3}\)
= \(\left(-\frac{15}{20}+\frac{8}{20}\right)\cdot\frac{7}{3}+\left(\frac{12}{20}-\frac{45}{20}\right)\cdot\frac{7}{3}\)
= \(-\frac{7}{20}\cdot\frac{7}{3}-\frac{33}{20}\cdot\frac{7}{3}\)
=\(\frac{7}{3}\cdot\left(-\frac{7}{20}-\frac{33}{20}\right)\)
=\(\frac{7}{3}\cdot\left(-2\right)\)
=\(-\frac{14}{3}\)
\(\left(6-2\frac{4}{5}\right).3\frac{1}{8}-1\frac{3}{5}:\frac{1}{4}\)
\(=\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\)
\(=\frac{16}{5}.\frac{25}{8}-\frac{32}{5}\)
\(=10-\frac{32}{5}\)
\(=\frac{18}{5}\)
Thực hiện phép tính
a ) \(\frac{2}{5}+\frac{-1}{6}-\frac{3}{4}-\frac{-2}{3}\)
= \(\frac{2}{5}+\frac{-1}{6}+\frac{-3}{4}+\frac{2}{3}\)
= \(\left(\frac{2}{5}+\frac{-3}{4}\right)+\left(\frac{-1}{6}+\frac{2}{3}\right)\)
= \(\left(\frac{8}{20}+\frac{-15}{20}\right)+\left(\frac{-1}{6}+\frac{4}{6}\right)\)
= \(\left(\frac{8+\left(-15\right)}{20}\right)+\left(\frac{\left(-1\right)+4}{6}\right)\)
= \(\frac{-7}{20}+\frac{1}{2}\)
= \(\frac{-7}{20}+\frac{10}{20}=\frac{\left(7\right)+10}{20}=\frac{3}{20}\)
tk mk nha
đang âm rất nhiều rồi , giúp nha !!!!!
a) = 3/3 x ( -24/54 +45/54 ) : 7/12
= 1 x 21/54 x 12/7
= 18/27
( hiện tại mik chỉ lm đc thế này thui. thông cảm nk )
S = \(\frac12\times\frac13\) + \(\frac13\times\frac14\) + \(\frac14\times\frac15\) + \(\frac15\times\frac16\) + \(\frac17\times\frac18\) + \(\frac18\times\frac19\)
S = \(\frac12\) - \(\frac13\) + \(\frac13\) - \(\frac14\) + \(\frac14\) - \(\frac15\) + \(\frac15\) - \(\frac16\) + \(\frac17\) - \(\frac18\) + \(\frac18\) - \(\frac19\)
S = \(\frac12\) - \(\frac19\)
S = \(\frac{9}{18}-\frac{2}{18}\)
S = \(\frac{7}{18}\)
\(\frac{51}{92}\)
Tích nha
51/92
51/92
đáp án bằng 51/92
đúng 100%
tích cho tui nha
cảm ơn
tui bị trừ 50 điểm rồi
nhớ ủng hộ nha
huhu
giải chi tiêt gium mk nha
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):2+\frac{1}{6}-\frac{1}{4}=\frac{7}{46}\)
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):2+\frac{1}{6}=\frac{7}{46}+\frac{1}{4}\)
\(\left(x+\frac{1}{4}-\frac{1}{3}\right):2=\frac{37}{92}-\frac{1}{6}\)
\(x+\frac{1}{4}-\frac{1}{3}=\frac{65}{276}.2\)
\(x+\frac{1}{4}-\frac{1}{3}=\frac{65}{138}\)
\(x+\frac{1}{4}=\frac{37}{46}\)
\(x=\frac{37}{46}-\frac{1}{4}=\frac{51}{92}\)
thôi huhu tui đang tìm điểm giúp đi huhu khóc huhu
Ta có :
(x + \(\frac{1}{4}\)- \(\frac{1}{3}\)) : 2 + \(\frac{1}{6}-\frac{1}{4}=\frac{7}{46}\)
(x + \(\frac{3}{12}-\frac{4}{12}\)) : 2 + \(\frac{2}{12}-\frac{3}{12}=\frac{7}{46}\)
(x - \(\frac{1}{12}\)) : 2 - \(\frac{1}{12}\)= \(\frac{7}{46}\)
(x - \(\frac{1}{12}\)) : 2 = \(\frac{7}{46}+\frac{1}{12}\)
(x - \(\frac{1}{12}\)) : 2 = \(\frac{42}{276}+\frac{23}{276}\)
(x - \(\frac{1}{12}\)) : 2 = \(\frac{65}{276}\)
x - \(\frac{1}{12}=\frac{65}{276}.2\)
\(x-\frac{1}{12}=\frac{65}{138}\)
\(x=\frac{65}{138}+\frac{1}{12}\)
\(x=\frac{130}{276}+\frac{23}{276}\)
\(x=\frac{153}{276}=\frac{51}{92}\)
Ủng hộ mk nha !! ^_^
thanks nhiu nha^_^