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c: \(x^3-8x^2+x+42\)
\(=x^3+2x^2-10x^2-20x+21x+42\)
\(=\left(x+2\right)\left(x^2-10x+21\right)\)
\(=\left(x+2\right)\left(x-3\right)\left(x-7\right)\)
a: \(x^3+6x^2+11x+6\)
\(=x^3+3x^2+3x^2+9x+2x+6\)
\(=\left(x+3\right)\left(x^2+3x+2\right)\)
\(=\left(x+3\right)\left(x+1\right)\left(x+2\right)\)
g) (x+2)(x+3)(x+4)(x+5)-24 = \(\left[\left(x+2\right)\left(x+5\right)\right]\left[\left(x+3\right)\left(x+4\right)\right]-24\)
=\(\left[x^2+7x+10\right]\left[x^2+7x+12\right]\)
đặt \(x^2+7x+10=a\)
ta có \(a\left(a+2\right)-24=a^2+2a-24\)
\(=a^2+2a+1-25\)
\(=\left(a+1\right)^2-5^2\)
\(=\left(a+1-5\right)\left(a+1+5\right)\)
\(=\left(a-4\right)\left(a+6\right)\)
\(\Rightarrow\) \(\left(x^2+7x+10-4\right)\left(x^2+7x+10+6\right)=\left(x^2+7x+6\right)\left(x^2+7x+16\right)\)
a) = (x +5)2 - 22 = (x+5 -2)(x+5 +2) = (x+3)(x+7)
b) = x(x2 -1) -6(x-1)= x(x+1)(x-1) -6(x-1) = (x-1)(x(x+1)-6)
a)\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\)
b)\(\left(x-3\right)\left(x-7\right)\left(x+2\right)\)
c)\(\left(x-3\right)\left(x+3\right)\left(x+2\right)\left(x+1\right)\)
d)\(\left(x+5\right)\left(x-3\right)\left(x+1\right)\left(x+2\right)\)
a) x3 + 6x2 + 11x + 6
= (x3 + x2) + (5x2 + 5x) + (6x + 6)
= x2(x + 1) + 5x(x + 1) + 6(x + 1)
= (x2 + 5x + 6)(x + 1)
= (x2 + 2x + 3x + 6)(x + 1)
= [x(x + 2) + 3(x + 2)](x + 1)
= (x + 3)(x + 2)(x + 1)
b) x3 - 8x2 + x + 42
= x3 + 2x2 - 10x2 - 20x + 21x + 42
= x2(x + 2) - 10x(x + 2) + 21(x + 2)
= (x2 - 10x + 21)(x + 2)
= (x2 - 3x - 7x + 21)(x + 2)
=[x(x - 3) - 7(x - 3)](x + 2)
=(x - 7)(x - 3)(x + 2)
c) x4 + 3x3 - 7x2 - 27x - 18
= x4 + x3 + 2x3 + 2x2 - 9x2 - 9x - 18x - 18
= x3(x + 1) + 2x2(x + 1) - 9x(x + 1) - 18(x + 1)
= (x3 + 2x2 - 9x - 18)(x + 1)
= [x2(x + 2) - 9(x + 2)](x + 1)
=(x2 - 9)(x + 2)(x + 1)
= (x - 3)(x + 3)(x + 2)(x + 1)
d) x4 + 5x3 - 7x2 - 41x - 30
= x4 + x3 + 4x3 + 4x2 - 11x2 - 11x - 30x - 30
= x3(x + 1) + 4x2(x + 1) - 11x(x + 1) -30(x + 1)
= (x3 + 4x2 - 11x - 30)(x + 1)
= (x3 + 2x2 + 2x2 + 4x - 15x - 30)(x + 1)
= [x2(x + 2) + 2x(x + 2) - 15(x +2)](x + 1)
=(x2 + 2x - 15)(x + 2)(x + 1)
= (x2 - 3x + 5x - 15)(x + 2)(x +1)
= [x(x - 3) + 5(x - 3)](x + 2)(x + 1)
= (x - 3)(x + 5)(x + 2)(x + 1)
NHỚ TIK CHO MIK NHA, đừng có mà đọc suông xong bỏ đi đấy. mik là đầy đủ hơn cái bn ở dưới nên cho mik nhiều tik hơn nhé
một đòn bẫy dài một mét .đặt ở đâu để có thể dùng 3600n có thể nâng tảng đá nặng 120kg?
$\textbf{5)}$
$(4x-5)(x+2)-(x+5)(x-3)-3x^2-x$
$=(4x^2+3x-10)-(x^2+2x-15)-3x^2-x$
$=4x^2+3x-10-x^2-2x+15-3x^2-x$
$=5.$
Dài 166
b) 2x2+3x-27=2x2-6x+9x-27=2x(x-3)+9(x-3)=(x-3)(2x+9)



a, \(x^3+5x^2+8x+4=x^3+x^2+4x^2+4x+4x+4\)
\(=x^2\left(x+1\right)+4\left(x^2+2x+1\right)=x^2\left(x+1\right)+4\left(x+1\right)^2=\left(x^2+4\right)\left(x+1\right)\)
b, \(x^3-6x^2-x+30=x^3+2x^2-8x^2-16x+15x+30\)
\(=x^2\left(x+2\right)-8x\left(x+2\right)+15\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2-8x+15\right)=\left(x+2\right)\left(x^2-8x+16-1\right)\)
\(=\left(x+2\right)\left[\left(x-4\right)^2-1\right]=\left(x+2\right)\left(x-3\right)\left(x-5\right)\)
câu b là 6x mà