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DD
Đoàn Đức Hà
Giáo viên
3 tháng 6 2021
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)
\(2\times A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)
\(2\times A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\right)\)
\(A=1-\frac{1}{128}\)
\(A=\frac{127}{128}\)
DD
Đoàn Đức Hà
Giáo viên
3 tháng 6 2021
\(B=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(2\times B=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\)
\(B=1-\frac{1}{16}=\frac{15}{16}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\Leftrightarrow4\times x+\frac{15}{16}=1\)
\(\Leftrightarrow4\times x=\frac{1}{16}\)
\(\Leftrightarrow x=\frac{1}{64}\)
WH
29 tháng 4 2018
Trả lời
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{8+4+2+1}{16}=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}\)
\(\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}\)
\(\Leftrightarrow4x=\frac{8}{16}\)
\(\Leftrightarrow4x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}:4\)
\(\Leftrightarrow x=\frac{1}{8}\)
Vậy x=\(\frac{1}{8}\)
29 tháng 4 2018
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\left(\frac{8+4+2+1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}\)
\(\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}\)
\(\Leftrightarrow4x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}:4\)
\(\Leftrightarrow x=\frac{1}{8}\)
SL
1
LV
9 tháng 12 2015
4x + 1/2 + 1/4 + 1/8 + 1/16 =1
4x +15/16= 1
4x = 1 - 15/16
4x = 1/16
x = 1/64
VG
3
UN
2
TH
0
TT
1
DT
1
17 tháng 3 2016
1760:
x+x+x+x+1/2+1/4+1/8+1/16 = 1
x . 4 + 15/16 = 1
x . 4 = 1 – 15/16 = 1/16
x = 1/16 : 4 = 1/64
NA
6
(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1
(x+x+x+x)+(1/2+1/4+1/8+1/16)=1
4x+(1/2+1/4+1/8+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/16:4
x=1/64
(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1
(x+x+x+x)+(1/2+1/4+1/8+1/16)=1
4x+(1/2+1/4+1/8+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/16:4
x=1/64
\(\Rightarrow\) x + 1/2 + x + 1/4 + x + 1/8 + x + 1/16 = 1
\(\Rightarrow\) (x + x + x + x) + (1/2 + 1/4 + 1/8 +1/16) = 1
\(\Rightarrow\) 4x + 15/16 = 1
\(\Rightarrow\) 4x = 1 - 15/16 \(\Rightarrow\) 4x = 1/16
\(\Rightarrow\) x = 1/64
Vậy x = 1/64
Chúc bạn học tốt
(X+1/2) + (X+1/4) + (X+1/8) + (X+1/16) =1
Xx (1/2+1/4+1/8+1/6=1
Xx4 + 15/16=1
X= (1-15/16):4
X=1/64
bơ làng bơ xóm Nobita Kun copy bài nguyen quoc dat ( hãy ủng hộ cho nguyen quoc dat )
(X+1/2) + (X+1/4) + (X+1/8) + (X+1/16) =1
Xx (1/2+1/4+1/8+1/6=1
Xx4 + 15/16=1
X= (1-15/16):4
X=1/64
( X + 1/2 ) + (X + 1/4 ) + (X + 1/8 ) +( X +1/16) = 1
X+ 1/2 +X + 1/4 +X + 1/8 + X + 1/16 = 1
4* X + 15/16 = 1
4*X = 1 -15/16
4* X = 1/16
X = 1/16 : 4
X = 1/64
OK
ta có: ( x + x + x + x ) + (1/2 + 1/4 + 1/8 = 1/18 ) = 1
4x + 15/16 = 1
4x = 1 - 15/16
4x = 1/16
x = 1/16 : 4 = 1/64
duyệt nha và đồng thởi chúc học tốt hơn
﴾x+1/2﴿+﴾x+1/4﴿+﴾x+1/8﴿+﴾x+1/16﴿=1
﴾x+x+x+x﴿+﴾1/2+1/4+1/8+1/16﴿=1
4x+﴾1/2+1/4+1/8+1/16﴿=1
4x+15/16=1 4x=1‐15/16
4x=1/16 x=1/16:4
x=1/64
học tốt nha bn ! ^o^
(X+1/2) + (X+1/4) + (X+1/8) + (X+1/16) =1
Xx (1/2+1/4+1/8+1/6=1
Xx4 + 15/16=1
X= (1-15/16):4
X=1/64