Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, \(\dfrac{x-2}{5}=\dfrac{5}{7}\)
\(\Rightarrow7\left(x-2\right)=25\Rightarrow7x-14=25\)
\(\Rightarrow7x=39\Rightarrow x=\dfrac{39}{7}\)
b, \(\dfrac{-x-2}{3}=\dfrac{-6}{7}\)
\(\Rightarrow7\left(-x-2\right)=-18\Rightarrow-7x-14=-18\)
\(\Rightarrow-7x=-4\Rightarrow x=\dfrac{4}{7}\)
c, \(\dfrac{4}{7-x}=\dfrac{1}{3}\)
\(\Rightarrow12=7-x\Rightarrow7-x=12\)
\(\Rightarrow x=7-12=-5\)
Chúc bạn học tốt!!!
1,
\(\frac{25}{12}+\left(\frac{-4}{12}\right)=\frac{7}{4}\)
\(\frac{-10}{8}+\frac{15}{4}=\frac{5}{2}\)
\(\frac{3}{8}+\frac{-14}{6}=\frac{-47}{24}\)
\(\frac{350}{150}+\left(\frac{-200}{360}\right)=\frac{16}{9}\)
\([\frac{5}{8}+\left(\frac{-3}{4}\right)]+\frac{15}{6}=\frac{-1}{8}+\frac{15}{6}=\frac{19}{8}\)
\(\frac{7}{3}+[\left(\frac{-5}{6}\right)+\left(\frac{-2}{3}\right)]=\frac{7}{3}+\left(\frac{-3}{2}\right)=\frac{5}{6}\)
a) \(\frac{x+2015}{5}+\frac{x+2015}{6}=\frac{x+2015}{7}+\frac{x+2015}{8}\)
\(\frac{x+2015}{5}+\frac{x+2015}{6}-\frac{x+2015}{7}-\frac{x+2015}{8}=0\)
\(\left(x+2015\right).\left(\frac{1}{5}+\frac{1}{6}-\frac{1}{7}-\frac{1}{8}\right)=0\)
vì \(\frac{1}{5}+\frac{1}{6}-\frac{1}{7}-\frac{1}{8}\ne0\)
\(\Rightarrow\)x + 2015 = 0
\(\Rightarrow\)x = -2015
b) Tương tự
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow7x-7=6x+30\)
hay x=37
https://hoc24.vn/cau-hoi/x-1-x5-6-7.2213164730326
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
\(\Leftrightarrow6\left(x+5\right)=7\left(x-1\right)\)
\(\Leftrightarrow6x+30=7x-7\)
\(\Leftrightarrow30+7=7x-6x\)
\(\Leftrightarrow x=37\)
\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
đk: x < -5
\(\Rightarrow\left(x+5\right).6=\left(x-1\right).7\)
\(\Rightarrow6x+30=7x-7\)
\(\Rightarrow6x-7x=-7-30\)
\(\Rightarrow-x=-37\)
\(\Rightarrow x=37\)
( thỏa mãn)
ĐKXĐ: \(x>-5\)
ĐKXĐ: \(x>-5\)
ĐKXĐ nữa nhé: \(x>-5\)
okay :')