1,

\(\frac{25}{12}+\left(\frac{-4}{12}\right)=\frac{7}{4}\)

\(\frac{-10}{8}+\frac{15}{4}=\frac{5}{2}\)

\(\frac{3}{8}+\frac{-14}{6}=\frac{-47}{24}\)

\(\frac{350}{150}+\left(\frac{-200}{360}\right)=\frac{16}{9}\)

\([\frac{5}{8}+\left(\frac{-3}{4}\right)]+\frac{15}{6}=\frac{-1}{8}+\frac{15}{6}=\frac{19}{8}\)

\(\frac{7}{3}+[\left(\frac{-5}{6}\right)+\left(\frac{-2}{3}\right)]=\frac{7}{3}+\left(\frac{-3}{2}\right)=\frac{5}{6}\)

4,

\(\frac{X+1}{5}=\frac{3}{7}\)

\(\Rightarrow\left(X-1\right).7=3.5\)

\(\Rightarrow7X-7=15\)

\(\Rightarrow7X=22\)

\(\Rightarrow X=\frac{22}{7}\)

\(\frac{X-3}{4}=\frac{1}{2}\)

\(\Rightarrow\left(X-3\right)2=1.4\)

\(\Rightarrow2X-6=4\)

\(\Rightarrow2X=10\)

\(\Rightarrow X=5\)

a) \(\left(x+5\right)^3=64\)

\(\Leftrightarrow\left(x+5\right)^3=4^3\)

\(\Leftrightarrow x+5=4\)

\(\Leftrightarrow x=-1\)

Vậy x = - 1

b) \(x:\left(-\frac{3}{5}\right)^2=-\frac{3}{5}\)

\(\Leftrightarrow x=\left(-\frac{3}{5}\right)^2.\left(-\frac{3}{5}\right)\)

\(\Leftrightarrow x=\left(-\frac{3}{5}\right)^3\)

\(\Leftrightarrow x=-0,216\)

Vậy x = - 0, 216

c) \(\left(\frac{4}{7}\right)^4.x=\left(\frac{4}{7}\right)^6\)

\(\Leftrightarrow x=\left(\frac{4}{7}\right)^6:\left(\frac{4}{7}\right)^4\)

\(\Leftrightarrow x=\left(\frac{4}{7}\right)^2\)

\(\Leftrightarrow\text{x}=\frac{16}{49}\)

Vậy x = 16/49

d) \(\left(-\frac{1}{3}\right)^3x=\frac{1}{81}\)

\(\Leftrightarrow-\frac{1}{27}x=\frac{1}{81}\)

\(\Leftrightarrow x=\frac{1}{81}:\left(-\frac{1}{27}\right)\)

\(\Leftrightarrow x=-\frac{1}{3}\)

Vậy x = - 1/3

gõ đề bằng công thức toán nếu muốn đc trợ giúp tốt nhất

a, \(\dfrac{x-2}{5}=\dfrac{5}{7}\)

\(\Rightarrow7\left(x-2\right)=25\Rightarrow7x-14=25\)

\(\Rightarrow7x=39\Rightarrow x=\dfrac{39}{7}\)

b, \(\dfrac{-x-2}{3}=\dfrac{-6}{7}\)

\(\Rightarrow7\left(-x-2\right)=-18\Rightarrow-7x-14=-18\)

\(\Rightarrow-7x=-4\Rightarrow x=\dfrac{4}{7}\)

c, \(\dfrac{4}{7-x}=\dfrac{1}{3}\)

\(\Rightarrow12=7-x\Rightarrow7-x=12\)

\(\Rightarrow x=7-12=-5\)

Chúc bạn học tốt!!!

\(\frac{x-1}{x-5}=\frac{6}{7}\)

\(\Rightarrow\left(x-1\right).7==\left(x-5\right).6\)

\(\Rightarrow7x-7=6x-30\)

\(\Rightarrow7x-6x=-30+7\)

\(\Rightarrow x=-23\)

ai giúp mk với

chuẩn 

b ơi minh thấy đề bài nó cứ kì kì

nếu như bn viết đề bài đúng thì mình có thể lm đc cho bn đó

a) x ; y ko tồn tại vì : \(VP\leq \frac{-1}{4}<0\)