M={12+23;12+45;34+23;34+45}

M={35;57;79}

M={35,57,79}

k mik nha

a) Ta có (a^m)ⁿ = a^m.a^m...a^m (định nghĩa) (có n thừa số a^m)

                   = a^{m + m + .... + m} (có n hạng tử m)

                   = a^m.n (đpcm)

b) Ta có 5³³³ = 5^3.111 =  (5³)¹¹¹ = 125¹¹¹

3⁵⁵⁵ = 3^5.111 = (3⁵)¹¹¹ = 243¹¹¹

Nhận thấy 125 < 243 

=> 125¹¹¹ < 243¹¹¹

=> 5³³³ < 3⁵⁵⁵

b) Ta có 2⁴⁰⁰ = 2^4.100 = (2⁴)¹⁰⁰ = 16¹⁰⁰

4²⁰⁰ = 4^2.100 = (4²)¹⁰⁰ = 16¹⁰⁰

=> 2⁴⁰⁰ = 4²⁰⁰ (= 16¹⁰⁰) 

A= {-3;-2;-1;0;1}

b/ x=5; y=9 hoặc x=9;y=5 hoặc (nhiều lắm, miễn khi phân tích nó ra thừa số nguyên tố có 5 và 3² là dc)

Bài 1

a) \(\frac{5}{6}=\frac{x-1}{x}\)

<=> 5x=6x-6

<=> 5x-6x=-6

<=> -11x=-6

<=> \(x=\frac{6}{11}\)

b)c)d) nhân chéo làm tương tự

Câu 1

b; 1/2=x+1/3x

x.(1+ 1/3) = 1/2

x.4/3 = 1/2

x = 1/2 : 4/3

x = 3/8

Vậy x = 3/8

c; 3/2+x=5/2x+1

5/2x - x = 3/2 - 1

x(5/2 - 1) = 1/2

x.3/2 = 1/2

x = 1/2 : 3/2

x = 1/2 x 2/3

x = 1/3

Vậy x = 1/3

d/5/8x−2=−4/7−x

a,=4¹⁰

b,=3¹⁶

c,=3ⁿ

d,=10¹⁶

e,=...

a) \(16^6:4^2=\left(4^2\right)^6:4^2=4^{12}:4^2=4^{10}\)

b) \(27^8:9^4=\left(3^3\right)^8:\left(3^2\right)^4=3^{24}:3^8=3^{16}\)

c) \(12^n:2^{2n}=12^n:4^n=3^n\)

d) \(4^{14}\times5^{18}=\left(4^7\right)^2\times\left(5^9\right)^2=\left(4^7\times5^9\right)^2\)

\(a,\frac{3}{4}.\left(x+2\right)+\frac{1}{2}.\left(x-\frac{1}{2}\right)=\frac{15}{4}\)

\(\frac{3}{4}.x+\frac{3}{4}.2+\frac{1}{2}.x+\frac{1}{2}.\left(-\frac{1}{2}\right)=\frac{15}{4}\)

\(\left(\frac{3}{4}.x+\frac{1}{2}.x\right)+\frac{3}{2}-\frac{1}{4}=\frac{15}{4}\)

\(\left(\frac{3}{4}+\frac{1}{3}\right).x=\frac{15}{4}+\frac{1}{4}-\frac{3}{2}\)

\(\frac{5}{4}.x=\frac{5}{2}\)

\(x=\frac{5}{2}:\frac{5}{4}\)

\(x=2\)

\(b,3.x-\frac{3}{5}=0\)

\(3.x=0+\frac{3}{5}\)

\(3.x=\frac{3}{5}\)

\(x=\frac{3}{5}:3\)

\(x=\frac{1}{5}\)

\(c,\frac{-2}{3}.x-\frac{1}{3}.\left(2.x-3\right)=\frac{3}{2}\)

\(\frac{-2}{3}.x-\frac{2}{3}.x+1=\frac{3}{2}\)

\(\left(\frac{-2}{3}-\frac{2}{3}\right).x=\frac{3}{2}-1\)

\(-\frac{4}{3}.x=\frac{1}{2}\)

\(x=\frac{1}{2}:\left(\frac{-4}{3}\right)\)

\(x=\frac{-3}{8}\)

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