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\(\dfrac{7}{12}=\dfrac{3}{12}+\dfrac{4}{12}=\dfrac{1}{4}+\dfrac{1}{3}\)
\(\dfrac{13}{27}=\dfrac{9}{27}+\dfrac{4}{27}=\dfrac{1}{3}+\dfrac{4}{27}\)
\(\dfrac{7}{12}\) = \(\dfrac{1+6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{6}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{1}{2}\)
\(\dfrac{7}{12}\) = \(\dfrac{3+4}{12}\) = \(\dfrac{3}{12}\) + \(\dfrac{4}{12}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{3}\)
\(\dfrac{13}{27}\) = \(\dfrac{1+12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{12}{27}\) = \(\dfrac{1}{27}\) + \(\dfrac{4}{9}\)
\(\dfrac{13}{27}\) = \(\dfrac{4+9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{9}{27}\) = \(\dfrac{4}{27}\) + \(\dfrac{1}{3}\)
\(\dfrac{13}{27}\) = \(\dfrac{6+7}{27}\) = \(\dfrac{6}{27}\) + \(\dfrac{7}{27}\) = \(\dfrac{2}{9}\) + \(\dfrac{7}{27}\)
a: \(\frac{13}{27}=\frac{1}{27}+\frac{12}{27}=\frac{1}{27}+\frac49=\frac{1}{27}+\frac{3+1}{9}=\frac{1}{27}+\frac39+\frac19\)
\(=\frac{1}{27}+\frac19+\frac13\)
b: \(\frac{15}{16}=\frac{1}{16}+\frac{14}{16}\)
\(=\frac{1}{16}+\frac78=\frac{1}{16}+\frac{4+3}{8}=\frac{1}{16}+\frac48+\frac38\)
\(=\frac{1}{16}+\frac12+\frac{2+1}{8}=\frac{1}{16}+\frac12+\frac14+\frac18\)
c: \(\frac{39}{54}=\frac{38+1}{54}=\frac{38}{54}+\frac{1}{54}\)
\(=\frac{1}{54}+\frac{19}{27}=\frac{1}{54}+\frac{1}{27}+\frac{18}{27}\)
\(=\frac{1}{54}+\frac{1}{27}+\frac23=\frac{1}{54}+\frac{1}{27}+\frac46=\frac{1}{54}+\frac{1}{27}+\frac36+\frac16\)
\(=\frac{1}{54}+\frac{1}{27}+\frac16+\frac12\)
d: \(\frac{13}{42}=\frac{6+7}{42}=\frac{6}{42}+\frac{7}{42}=\frac17+\frac16\)
\(a,\dfrac{7}{15}=\dfrac{2}{15}+\dfrac{1}{3}\\ b,\dfrac{13}{27}=\dfrac{10}{27}+\dfrac{1}{9}\\ c,\dfrac{3}{18}=\dfrac{1}{18}+\dfrac{1}{9}\\ d,=\dfrac{1}{20}+\dfrac{1}{20}\)
Hi:D