A.  $d: \frac{x-1 }{-3 }=\frac{y }{2 }=\frac{z-4 }{1 }$

B.  $d: \frac{x-1 }{3 }=\frac{y }{1 }=\frac{z-4 }{1 }$

C.  $d: \frac{x-1 }{-3 }=\frac{y }{-1 }=\frac{z-4 }{1 }$

D.  $d: \frac{x-1 }{-3 }=\frac{y }{2 }=\frac{z-4 }{-1 }$

A.  $∆: \frac{x-1}{1}=\frac{y+1}{2}=\frac{z}{3}$

B.  $∆: \frac{x-2}{1}=\frac{y-3}{2}=\frac{z-1}{3}$

C.  $∆: \frac{x-3}{1}=\frac{y-3}{2}=\frac{z+2}{3}$

C.  $∆: \frac{x-1}{3}=\frac{y+1}{2}=\frac{z}{1}$

A.  $\frac{x-1}{-1}=\frac{y-3}{2}=\frac{z+2}{3}$

B.  $\frac{x-1}{-1}=\frac{y-3}{2}=\frac{z+2}{-3}$

C.  $\frac{x-1}{-1}=\frac{y-2}{-2}=\frac{z+3}{-3}$

D.  $\frac{x-1}{-1}=\frac{y+3}{-2}=\frac{z-2}{-3}$

A.  $\left(\alpha \right)$: -7x + 11y + z - 3 = 0

B. $\left(\alpha \right)$: 7x - 11y + z - 1 = 0

C. $\left(\alpha \right)$: -7x + 11y + z + 15 = 0

D. $\left(\alpha \right)$: 7x - 11y - z + 1 = 0

A.  $\left(S\right): {\left(x+2\right)}^2+{\left(y+4\right)}^2+{\left(z+3\right)}^2=1$

B. $\left(S\right): {\left(x-2\right)}^2+{\left(y-4\right)}^2+{\left(z-3\right)}^2=6$

C. $\left(S\right): {\left(x-2\right)}^2+{\left(y-4\right)}^2+{\left(z-3\right)}^2=\frac{2}{7}$

D. $\left(S\right): {\left(x-2\right)}^2+{\left(y+4\right)}^2+{\left(z+4\right)}^2=8$

A. x+2y+3z $-$9 = 0

B. x+2y+3z $-$13 = 0

C. x+2y+3z+5 = 0

D. x+2y+3z+13 = 0

A. 4x + 5y – 3z + 22 = 0.

B. 4x – 5y – 3z -12 =0

C. 2x + y – 3z – 14 = 0.

D. 4x + 5y – 3z – 22 = 0

A.   $\frac{x-1}{6}=\frac{y+2}{-1}=\frac{z-1}{2}$

B.  $\frac{x-1}{2}=\frac{y+2}{1}=\frac{z-1}{-5}$

C.  $\frac{x-1}{6}=\frac{y+2}{1}=\frac{z-1}{2}$

D.  $\frac{x-1}{-2}=\frac{y+2}{1}=\frac{z-1}{5}$

A.  ${\left(x+1\right)}^2+{\left(y+1\right)}^2+{\left(z+1\right)}^2=6$

B.  ${\left(x+1\right)}^2+{\left(y-1\right)}^2+{\left(z+1\right)}^2=6$

C.  ${\left(x-1\right)}^2+{\left(y-1\right)}^2+{\left(z+1\right)}^2=6$

D.  ${\left(x+1\right)}^2+{\left(y+1\right)}^2+{\left(z-1\right)}^2=6$