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Bài làm:
Dễ hiểu hơn: Ta có a là số lớn
, b là số nhỏ
còn d là chữ số hàng đơn vị của số lớn
Theo đề: a : 10 + d = b do đó 10b + d = a
thay vào: a + b = 10b + d + b = 11b + d = 1644
mà 1644 = 11 . 149 + 5 suy ra a = 149 . 10 + 5 = 1496
Bài giải
Tổng số phần bằng nhau là :
10+1=11 (phần)
Ta có : 1644:11=149(dư 5)
Số lớn là :
( 1644 - 5 ) : 11 x 10 + 5 = 1495
Đáp số:...................
hok tốt
Gọi số bé là abc, số lớn là abcd
abc + abcd = 1644
abc + abc x 10 + d = 1644
abc x 11 + d = 1644
abc x 11 = 1644 - d
=> 1644 - d chia hết cho 11
=> d = 5 thỏa mãn
abc x 11 = 1644 - 5
abc x 11 = 1639
=> abc = 1639 : 11
=> abc = 149 và abcd = 1495
Số lớn là 1495
Nếu không xóa, số lớn = 10 x số bé + sô hàng đơn vi
Số bé là : 1644 : (10 + 1) = 149
Và số dư 1644 : (10 + 1) là 5
Số lớn là : 159 x 10 + 5 = 1595
Bài giải
Tổng số phần bằng nhau là :
10+1=11 (phần)
Ta có : 1644:11=149(dư 5)
Số lớn là :
( 1644 - 5 ) : 11 x 10 + 5 = 1495
Đáp số:...................
hok tốt
là số 1495
Gọi số bé là abc, số lớn là abcd
abc + abcd = 1644
abc + abc x 10 + d = 1644
abc x 11 + d = 1644
abc x 11 = 1644 - d
=> 1644 - d chia hết cho 11
=> d = 5 thỏa mãn
abc x 11 = 1644 - 5
abc x 11 = 1639
=> abc = 1639 : 11
=> abc = 149 và abcd = 1495
Số lớn là 1495
Nếu ta thay chữ số trận cùng của số lớn = chữ số 0 thì Được số lớn mới gấp 10 lần số bé
Tổng hai số lúc này = 1644 - chữ số tận cùng của số lớn ban đầu
Phân số chỉ số bé
1:(1+10)=1/11 Tổng hai số lúc sau
=> Tổng hai số lúc sau phải là số chia hết cho 11
1664:11 dư 3
Như vậy chữ số tận cùng của số lớn là 3
Số bé là
(1664-3):11=151
Số lớn là 1513
Ta có: Số lớn gấp 10 lần số bé và cộng thêm R (R là chữ số hàng đơn vị)
(1644-R):11=149(dư 5)
Vậy số lớn là:
149x10+5=1495
Đ/s: 1495
theo mk la
ta da biet so be la 164
vay muon tim so lon ta chi viec lay tong tru di so be
1644 - 164=1480
theo mk nghi so lon la 1480
neu dung thi k cho mk nha mk bi tru nhieu diem lam hihi
tranthaiyen sai rồi;(
Dễ hiểu hơn : Ta có a là số lớn
, b là số nhỏ
còn d là chữ số hàng đơn vị của số lớn
Theo đề : a : 10 + d = b do đó 10b + d = a
thay vào : a + b = 10b + d + b = 11b +d= 1644
mà 1644= 11 . 149 + 5 suy ta a = 149 .10 +5 = 1495
kết quả là 1945
1945 la sai
1495 lafchinhs xác nhất
kết quả là 1495
vi sao lại chia 11
Gọi số lớn là abcd, suy ra số bé là abc
Theo bài ra, ta có: abcd + abc = 1644
Ta có thể đặt tính như sau:
Từ hàng đơn vị: d + c < 20, do đó nhớ < 2
Từ hàng chục: c + b < 20, do đó nhớ < 2
Từ hàng trăm: b + a < 20, do đó nhớ < 2
Từ hàng nghìn ta có: a + 0 = 1, vậy a = 1
Xét hàng trăm ta có: b + 1 + 1 (nhớ) = 6, vậy b = 4
Xét hàng chục ta có: c + 4 + 1 (nhớ) = 4, vậy c = 9
Xét hàng đơn vị ta có: d + 9 = 4, vậy d = 5
Số lớn là: 1495
ngô trúc ngân sai rồi
do ngu ket qua dung la 1495
1495.Mình làm trên violympic rồi
1945 day
1495 nha
ket qua la 1495
1495 đúng chính xác mình thi trên vilympic rồi mà
À 1495 đấy
1495 nha
1945
1945
1945
1945
1495 đấy bạn! mk làm trong violympic rùi
các bạn trả lời =1495 là đúng rồi
Gọi số lớn là abcd, suy ra số bé là abc
Theo bài ra, ta có: abcd + abc = 1644
Ta có thể đặt tính như sau:
Từ hàng đơn vị: d + c < 20, do đó nhớ < 2
Từ hàng chục: c + b < 20, do đó nhớ < 2
Từ hàng trăm: b + a < 20, do đó nhớ < 2
Từ hàng nghìn ta có: a + 0 = 1, vậy a = 1
Xét hàng trăm ta có: b + 1 + 1 (nhớ) = 6, vậy b = 4
Xét hàng chục ta có: c + 4 + 1 (nhớ) = 4, vậy c = 9
Xét hàng đơn vị ta có: d + 9 = 4, vậy d = 5
Số lớn là: 1495
1495 đó 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này 1495 co mà linh tinh gi ma 1945 day
=1513&151
Gọi số lớn là abcd, suy ra số bé là abc
Theo bài ra, ta có: abcd + abc = 1644
Ta có thể đặt tính như sau:
Từ hàng đơn vị: d + c < 20, do đó nhớ < 2
Từ hàng chục: c + b < 20, do đó nhớ < 2
Từ hàng trăm: b + a < 20, do đó nhớ < 2
Từ hàng nghìn ta có: a + 0 = 1, vậy a = 1
Xét hàng trăm ta có: b + 1 + 1 (nhớ) = 6, vậy b = 4
Xét hàng chục ta có: c + 4 + 1 (nhớ) = 4, vậy c = 9
Xét hàng đơn vị ta có: d + 9 = 4, vậy d = 5
Số lớn là: 1495
1495 là đúng đấy mình vừa làm trên violympic xong đấy
cac ban tim so lon hay so be vay the
ngu nhu trau