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22 tháng 9 2025

a: \(\left(\frac{11}{4}-\frac78\right):\frac{11}{2}\)

\(=\left(\frac{22}{8}-\frac78\right)\times\frac{2}{11}\)

\(=\frac{15}{8}\times\frac{2}{11}=\frac{15}{4\times11}=\frac{15}{44}\)

b: Sửa đề: \(\frac{29}{44}:\frac{15}{44}\times\frac{15}{88}:\frac{165}{16}\)

\(=\frac{29}{44}\times\frac{44}{15}\times\frac{15}{88}\times\frac{16}{165}\)

\(=\frac{29}{88}\times\frac{16}{165}=29\times\frac{2}{11\times165}=\frac{58}{1815}\)

29 tháng 9 2025

\(6-\left(\frac76+\frac{7}{18}\right)\)

\(=6-\left(\frac{7\times3}{6\times3}+\frac{7}{18}\right)\)

\(=6-\left(\frac{21}{18}+\frac{7}{18}\right)\)

\(=6-\left(\frac{21+7}{18}\right)\)

\(=6-\frac{28}{18}\)

\(=6-\frac{28:2}{18:2}\)

\(=6-\frac{14}{9}\)

\(=\frac{6\times9}{1\times9}-\frac{14}{9}\)

\(=\frac{36}{9}-\frac{14}{9}\)

\(=\frac{54-14}{9}\)

\(=\frac{40}{9}\)

2 tháng 11 2025

cong hai cái số trong ngoac rồi lấy 6 đổi ra 6'1 trừ đi

4 tháng 2 2018

\(\frac{9}{8}>\frac{8}{9}\)

\(\frac{16}{23}>\frac{16}{25}\)

\(\frac{8}{11}< \frac{8}{10}\)

\(\frac{10}{13}>\frac{19}{26}\)

\(\frac{13}{15}< \frac{11}{10}\)

\(\frac{11}{9}=\frac{44}{36}\)

9/8 > 8/9 

16/23 > 16/25 

8/11 < 8/10 

10/13 > 19/26 

13/15 < 11/10 

11/9 = 44/36 

Tham khảo nha !

Chúc bạn học giỏi !

20 tháng 7 2018

\(\left(2.8x-32\right):\frac{2}{3}=90\)

\(2.8\cdot x-32=90\cdot\frac{2}{3}\)

\(\frac{14}{5}x-32=60\)

\(\frac{14}{5}x=60+32\)

\(\frac{14}{5}x=92\)

\(x=\frac{230}{7}\)

B , c , d tương tự

6 tháng 7 2017

\(a.\left(\frac{6}{11}+\frac{5}{11}\right).\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}b.\frac{3}{5}\cdot\frac{7}{9}+\frac{3}{5}\cdot\frac{2}{9}=\frac{3}{5}\cdot\left(\frac{7}{9}+\frac{2}{9}\right)=\frac{3}{5}\cdot1=\frac{3}{5}\)

6 tháng 8 2025

16 tháng 8 2015

a) \(\frac{27}{36}=\frac{3}{4}\)

b) \(\frac{45}{60}=\frac{3}{4}\)

c) \(\frac{2}{4}=\frac{1}{2}\)

d) \(\frac{10}{12}=\frac{5}{6}\)

e) \(\frac{112}{252}=\frac{4}{9}\)

Đúng nha bạn !!@@

 

16 tháng 8 2015

\(\frac{1}{3}+\frac{3}{4}x\frac{5}{9}=\frac{1}{3}+\frac{5}{12}=\frac{3}{4}\)

\(\frac{7}{12}-\frac{5}{4}x\frac{2}{15}=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\)

\(y+\frac{1}{4}=\frac{7}{8}-\frac{3}{8}=y+\frac{1}{4}=\frac{1}{2}=\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\)

\(y-\frac{5}{12}=\frac{2}{3}-\frac{1}{4}=y-\frac{5}{12}=\frac{5}{12}=\frac{5}{12}+\frac{5}{12}=\frac{5}{6}\)

\(\frac{12}{7}xy=\frac{16}{21}=\frac{16}{21}:\frac{12}{7}=\frac{4}{9}\)

\(\frac{5}{4}:y=\frac{7}{12}=\frac{5}{4}:\frac{7}{12}=\frac{15}{7}\)

28 tháng 8 2017

1    \(A=\left(1+\frac{1}{2}\right)\times\left(1+\frac{1}{3}\right)\times\left(1+\frac{1}{4}\right)\times.........\times\left(1+\frac{1}{2016}\right)\times\left(1+\frac{1}{2017}\right)\)

\(A=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times......\times\frac{2016}{2017}\times\frac{2018}{2017}\)

\(A=\frac{2018}{2}=1009\)

\(B=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+.......+\frac{2}{43.45}\)

\(B=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-......+\frac{1}{43}-\frac{1}{45}\)

\(B=\frac{1}{3}-\frac{1}{45}\)

\(B=\frac{14}{45}\)

2     \(\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{2018}\times\frac{2017}{47}\)

\(=\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{47}\times\frac{2017}{2018}\)

\(=\frac{2017}{2018}\times\left(\frac{23}{47}+\frac{24}{47}\right)\)

\(=\frac{2017}{2018}\times1\)

=\(\frac{2017}{2018}\)

bạn nào xem giải thế có đúng ko

\(1,\frac{3}{5}+\frac{7}{2}-\frac{4}{7}=\frac{42}{70}+\frac{245}{70}-\frac{40}{70}=\frac{247}{70}\)

\(2,\frac{4}{5}-\frac{1}{3}+\frac{3}{4}=\frac{48}{60}-\frac{20}{60}+\frac{45}{60}=\frac{73}{60}\)

\(3,\frac{1}{3}\times\frac{5}{7}:\frac{7}{2}=\frac{5}{21}:\frac{7}{2}=\frac{10}{147}\)

\(4,\frac{1}{2}:\frac{2}{7}\times\frac{4}{7}=\frac{7}{4}\times\frac{4}{7}=1\)

\(5,\frac{19}{15}\times\frac{3}{7}:\frac{4}{9}=\frac{19}{35}:\frac{4}{9}=\frac{171}{140}\)

\(6,\frac{11}{3}:\frac{9}{16}:\frac{3}{8}=\frac{176}{27}:\frac{3}{8}=\frac{1408}{81}\)

_Chúc bạn học tốt _

4 tháng 3 2019

1) \(\frac{4}{5}.\frac{8}{3}.\frac{x}{7}=\frac{96}{105}\)

\(\frac{32.x}{105}=\frac{96}{105}\)

\(32x=96\)

\(x=3\)

26 tháng 6 2025

Bài 1: Tìm \(x\)

\(\frac45\times\frac83\times\) \(\frac{x}{7}\) = \(\frac{96}{105}\)

\(\frac{32}{15}\) x \(\frac{x}{7}\) = \(\frac{32}{35}\)

\(\frac{x}{7}\) = \(\frac{32}{35}\) : \(\frac{32}{15}\)

\(\frac{x}{7}\) = \(\frac{32}{35}\) x \(\frac{15}{32}\)

\(\frac{x}{7}\) = \(\frac37\)

\(x=\frac37\times7\)

\(x=3\)

b; \(\frac74\times\frac{3}{x}\times\) \(\frac{11}{5}\) = \(\frac{231}{200}\)

\(\frac74\) x \(\frac{3}{x}\) = \(\frac{231}{200}\) : \(\frac{11}{5}\)

\(\frac74\times\frac{3}{x}\) = \(\frac{231}{200}\) x \(\frac{5}{11}\)

\(\frac74\) x \(\frac{3}{x}\) = \(\frac{21}{40}\)

\(\frac{3}{x}\) = \(\frac{21}{40}\) : \(\frac74\)

\(\frac{3}{x}\) = \(\frac{21}{40}\) x \(\frac47\)

\(\frac{3}{x}\) = \(\frac{3}{10}\)

\(x=3:\frac{3}{10}\)

\(x=3\times\frac{3}{10}\)

\(x=10\)