\(\frac{10^4.81-16.15^2}{4^4.675}=\frac{\left(2.5\right)^4.3^4-2^4\left(3.5\right)^2}{2^8.5^2.3^3}=\frac{2^4.3^2.5^2\left(5^2.3^2-1\right)}{2^8.5^2.3^3}=\frac{255-1}{16.3}=\frac{14}{3}\)

\(\frac{10^4.81-16.15^2}{4^4.675}=\frac{10^4.3^4-4^2.15^2}{4^4.5^4}=\frac{30^4-60^2}{20^4}=\frac{900^2-60^2}{400^2}=\frac{20^2\left(45^2-3^2\right)}{20^2.2^2}=\frac{2016}{4}=504\)

\(\frac{10^4.81-16.15^2}{4^4.675}=\frac{\left(2.5\right)^4.3^4-2^4\left(3.5\right)^2}{2^8.5^2.3^3}=\frac{2^4.3^2.5^2\left(5^2.3^2-1\right)}{2^8.5^2.3^3}=\frac{255-1}{16.3}=\frac{14}{3}\)

$\frac{10^4.81-16.15^2}{4^4.675}=\frac{10^4.3^4-4^2.15^2}{4^4.5^4}=\frac{30^4-60^2}{20^4}=\frac{900^2-60^2}{400^2}=\frac{20^2\left(45^2-3^2\right)}{20^2.2^2}=\frac{2016}{4}=504$104.81−16.15244.675 =‍104.34−42.15244.54 =304−602204 =9002−6024002 =202(452−32)202.22 =20164 =504

\(A=\frac{10^4\cdot81-16\cdot15^2}{4^4\cdot675}\)

\(=\frac{2^4\cdot5^4\cdot3^3-2^4\cdot3^2\cdot5^2}{2^8\cdot3^3\cdot5^2}\)

\(=\frac{2^4\cdot5^2\cdot3\left(5^2\cdot3-3\right)}{2^8\cdot3^3\cdot5^2}\)

\(=\frac{5^2\cdot3-3}{2^4\cdot3^2}\)

\(=\frac{3\cdot\left(5^2-1\right)}{2^4\cdot3^2}=\frac{24}{48}=\frac{1}{2}\)

các bạn ơi 500 nhân 687= bao nhiêu

\(=\dfrac{2^4\cdot5^4\cdot3^4-2^4\cdot3^2\cdot5^2}{2^8\cdot3^3\cdot5^2}=\dfrac{2^4\cdot3^2\cdot5^2\left(5^2\cdot3^2-1\right)}{2^8\cdot3^3\cdot5^2}\)

\(=\dfrac{1}{16}\cdot\dfrac{1}{3}\cdot\dfrac{224}{1}=\dfrac{224}{48}=\dfrac{14}{3}\)

\(\dfrac{10^4.81-16.15^2}{4^4.675}\)

\(=\dfrac{2^4.5^4.9^2-2^4.3^2.5^2}{2^8.5^4}\)

\(=\dfrac{1.25.9^2-1.3^2.1}{1.1}=1.25.9^2-1.3^2.1\)

\(=1899\)

Chúc bạn học tốt

Ở dòng thứ 2, 5^4 đâu bằng 675

\(=\frac{14}{3}nha!\)

a)\(\left[\frac{3}{7}\cdot\frac{4}{15}+\frac{1}{3}\cdot\left(9^{15}\right)\right]^0\cdot\frac{1}{3}\cdot\frac{6^8}{12^4}\)

\(=1\cdot\frac{1}{3}\cdot\frac{6^4\cdot6^4}{12^4}=\frac{1}{3}\cdot\frac{36^4}{12^4}=\frac{1}{3}\cdot81=27\)

a: \(A=\dfrac{2^{12}\cdot3^{10}+2^3\cdot2^9\cdot3^9\cdot3\cdot5}{2^{12}\cdot3^{12}+2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{11}\cdot3^{11}\cdot7}\)

\(=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot7}=\dfrac{2}{3}\cdot\dfrac{6}{7}=\dfrac{12}{21}=\dfrac{4}{7}\)

b: \(B=\left(\dfrac{12}{105}+\dfrac{9^{15}}{3}\right)\cdot\dfrac{1}{3}\cdot\dfrac{6^8}{6^4\cdot2^4}\)

\(=\dfrac{12+35\cdot9^{15}}{105}\cdot\dfrac{1}{3}\cdot3^4\)

\(=\dfrac{12+35\cdot9^{15}}{105}\cdot3^3=\dfrac{9\left(12+35\cdot9^{15}\right)}{35}\)

$\textbf{a)}$

$A=\dfrac{\left(\dfrac49\right)^2\cdot\left(-\dfrac9{16}\right)\cdot(-1)^{19}}{\left(\dfrac4{25}\right)^2\cdot\left(-\dfrac{25}{144}\right)^2\cdot\left(-\dfrac{49}{144}\right)^2}$

$=\dfrac{\dfrac{16}{81}\cdot\left(-\dfrac9{16}\right)\cdot(-1)}{\dfrac{16}{625}\cdot\dfrac{625}{144^2}\cdot\dfrac{49^2}{144^2}}$

$=\dfrac{\dfrac19}{\dfrac{49^2}{144^4}}$

$=\dfrac19\cdot\dfrac{144^4}{49^2}$

$=\dfrac19\cdot\dfrac{(2^4\cdot3^2)^4}{7^4}$

$=\dfrac{2^{16}\cdot3^6}{7^4}$

$=\dfrac{47775744}{2401}.$

$\textbf{b)}$

$B=\dfrac{10^4\cdot81-16\cdot15^2}{4^4\cdot675}$

$=\dfrac{2^4\cdot5^4\cdot3^4-2^4\cdot3^2\cdot5^2}{2^8\cdot3^3\cdot5^2}$

$=\dfrac{2^4\cdot3^2\cdot5^2(3^2\cdot5^2-1)}{2^8\cdot3^3\cdot5^2}$

$=\dfrac{2^4\cdot3^2\cdot5^2\cdot224}{2^8\cdot3^3\cdot5^2}$

$=\dfrac{224}{2^4\cdot3}$

$=\dfrac{14}{3}.$