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a, 2\(\dfrac{3}{5}\) \(\times\) 1\(\dfrac{1}{4}\) + \(\dfrac{5}{2}\)
= \(\dfrac{13}{5}\) \(\times\) \(\dfrac{5}{4}\) + \(\dfrac{5}{2}\)
= \(\dfrac{13}{4}\) + \(\dfrac{5}{2}\)
= \(\dfrac{13}{4}\) + \(\dfrac{10}{4}\)
= \(\dfrac{23}{4}\)
a, 6/9+5/7+1/3=2/3+5/7+1/3=5/7+1=12/7
b, 17/7+6/5-20/14=17/7+6/5-10/7=6/5+1=11/5
c,2/5x1/4+3/4x2/5=2/5x(1/4+3/4)=2/5x1=2/5
d, 6/11:4/6+5/11:2/3=6/11:2/3+5/11:2/3=(6/11+5/11):2/3=3/2
nha
\(\frac{9}{16}:\frac{27}{8}=\frac{3^2:3^3}{2^4:2^3}=\frac{\frac{1}{3}}{2}=\frac{1}{6}\)
b tương tự nha
\(\frac{9}{16}:\frac{27}{8}=\frac{9}{16}\cdot\frac{8}{21}=\frac{3\cdot3\cdot4\cdot2}{8\cdot2\cdot7\cdot3}=\frac{14}{3}\)
\(\frac{40}{7}:\frac{5}{14}=\frac{40}{7}\cdot\frac{14}{5}=\frac{4\cdot5\cdot2\cdot7\cdot2}{7\cdot5}=\frac{16}{1}=16\)
Chúc bạn học tốt
\(\frac{23}{12}\)
\(\frac{314}{105}\)
\(\frac{59}{60}\)
\(\frac{199}{90}\)
\(\frac{1}{18}\)
\(\frac{13}{36}\)
\(\frac{4}{221}\)
\(\frac{4}{85}\)
Câu 1\(\frac{9}{8}.\frac{9}{3}=\frac{81}{24}\)
Câu 2 \(\frac{19}{5}+\frac{9}{5}=\frac{28}{5}\)
Câu 3 \(\frac{31}{7}:\frac{22}{5}=\frac{31.5}{7.22}=\frac{155}{154}\)
Câu 4 \(\frac{12}{1}-\frac{31}{5}=\frac{60}{5}-\frac{31}{5}=\frac{29}{5}\)
bài 6 \(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+\ldots+\frac{2}{80\times82}+\frac{2}{82\times84}\)
= \(\frac12-\frac14+\frac14-\frac16+\frac16-\cdots+\frac{1}{80}-\frac{1}{82}+\frac{1}{82}-\frac{1}{84}\)
= \(\frac12-\left(\frac14-\frac14\right)-\left(\frac16-\frac16\right)-\cdots-\left(\frac{1}{82}-\frac{1}{82}\right)-\frac{1}{84}\)
=\(\frac12-0-0-\frac{1}{84}\)
=\(\frac12\) - \(\frac{1}{84}\)
=\(\frac{42}{84}-\frac{1}{84}\)
=\(\frac{41}{84}\)
Bài 7
a)\(\frac{19}{4}=4\frac34\)
b)\(\frac{27}{5}=5\frac25\)
c)\(\frac{56}{8}=7\frac08\)
c. 1/6+7/2=11/3
Chúc bạn học tốt nếu đúng thì giúp mình nhé.
8/9:6/27-3=4-3=1
Bài làm :
\(c,\frac{1}{6}+\frac{5}{2}\times\frac{7}{5}\)
\(=\frac{1}{6}+\frac{7}{2}\)
\(=\frac{11}{3}\)
\(\frac{8}{9}:\frac{6}{27}-3\)
\(=\frac{8}{9}\times\frac{9}{2}-3\)
\(=4-3\)
\(=1\)
Học tốt
\(\frac{1}{6}+\frac{5}{2}×\frac{7}{5}=\frac{1}{6}+\frac{7}{2}=\frac{11}{3}\)
\(\frac{8}{9}:\frac{6}{27}-3=4-3=1\)
\(c,\frac{1}{6}+\frac{5}{2}\cdot\frac{7}{5}=\frac{1}{6}+\frac{5\cdot7}{2\cdot5}=\frac{1}{6}+\frac{7}{2}=\frac{1}{6}+\frac{21}{6}=\frac{22}{6}=\frac{11}{3}\)
\(\frac{8}{9}:\frac{6}{27}-3=\frac{8}{9}\cdot\frac{27}{6}-3=\frac{2\cdot4\cdot9\cdot3}{9\cdot2\cdot3}-3=4-3=1\)
\(\frac{1}{6}+\frac{5}{2}\times\frac{7}{5}\)
\(=\frac{1}{6}+\frac{5\times7}{2\times5}\)
\(=\frac{1}{6}+\frac{7}{2}\)
\(=\frac{11}{3}\)
\(\frac{8}{9}:\frac{6}{27}-3\)
\(=4-3=1\)
\(\frac{1}{6}+\frac{5}{2}\times\frac{7}{5}=\frac{11}{3}\)
\(\frac{8}{9}\div\frac{6}{27}-3=1\)