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42 + 43 + 44 + 45 - 32 - 33 - 34 - 35
= (42 - 32)+(43 - 33)+(44 - 34)+(45 - 35)
= 10+10+10+10
= 40
(64+65+66+67+68) - (54+55+56+57+58)
= 64+65+66+67+68 - 54-55-56-57-58
= (64 - 54)+(65 - 55) +(66 - 56) + (67- 57) + (68 -58)
= 10+10+10+10+10
= 50
Bài 1a) \(-\left(-29\right)+59-11+13=29+59-11+13=90\)
Bài 2 :a) \(66-x=-34\Leftrightarrow x-66-\left(-34\right)=100\)
b) Xét 2 trường hợp : TH1 : \(-5x=-75\Rightarrow x=\left(-75\right)\div\left(-5\right)=15\)
TH2 : \(-5\left(-x\right)=75\Leftrightarrow5x=75\Leftrightarrow x=75\div5=15\)
c) \(x^2=4=2^2\Leftrightarrow x=2\) d) \(x^3=-27=\left(-3\right)^3\Rightarrow x=-3\)
\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)
\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{^{14}}\right)^2}\)
\(=\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2\cdot3^{28}}\)
\(=\frac{3^{29}}{3^{28}}\cdot\frac84=3\cdot2=6\)
a: 29+131+237+763
=160+1000
=1160
b: 65+327+15+73
=65+15+327+73
=80+400
=480
c: \(12+54:8-8\)
=12+3-8
=15-8
=7
d: \(45\cdot58+45\cdot42\)
\(=45\cdot\left(58+42\right)\)
\(=45\cdot100=4500\)
e: \(35\cdot34+35\cdot26+40\cdot35\)
\(=35\cdot\left(34+26+40\right)\)
\(=35\cdot100=3500\)
f: \(65\cdot25+65\cdot45+30\cdot65\)
\(=65\cdot\left(25+45+30\right)\)
\(=65\cdot100=6500\)
g: \(750:\left\lbrace32-\left\lbrack2^2+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace+100\)
\(=\frac{750}{32-\left\lbrack4+5\cdot9-42\right\rbrack}+100=\frac{750}{32-4-45+42}+100\)
\(=\frac{750}{28-3}+100\)
=750:25+100
=30+100
=130
h: \(\left\lbrace630:\left\lbrack16+3\cdot\left(6+3\cdot4\right)\right\rbrack\right\rbrace-1\)
\(=\frac{630}{16+3\cdot\left(6+12\right)}-1=\frac{630}{16+3\cdot18}-1\)
\(=\frac{630}{70}-1\)
=9-1=8
i: \(5871:\left\lbrack928-\left(247-82\right)\cdot5\right\rbrack+2175^0\)
\(=\frac{5871}{928-165\cdot5}+1\)
\(=\frac{5871}{928-825}+1=\frac{5871}{103}+1=57+1=58\)
k: \(375:\left\lbrace32-\left\lbrack4+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace-14\)
\(=\frac{375}{32-\left\lbrack4+5\cdot9-42\right\rbrack}-14\)
\(=\frac{375}{32-\left\lbrack4+45-42\right\rbrack}-14=\frac{375}{32-\left(4+3\right)}-14=\frac{375}{32-7}-14\)
\(=\frac{375}{25}-14\)
=15-14
=1
a) (-30) + 17 + (-70) + 33
=[-30+(-70)]+(17+33)
=-100+50
=-50
b) 56 - 15 - 6 + (-75)
=(56-6)-[15+(-75)]
=50-(-60)
=110
c) (157 - 56) - (44 + 57)
=157-56-44+57
=(-157-57)-(56+44)
=-100-100
=-200
d) (-24 + 174) - (174 - 24)
=-24+174-174+24
=(-24+24)+(174-174)
=0+0
=0
e) (35 - 47) - (-123 + 35) + [20 - (123 - 57)]
=35-47+123-35+[20-123+57]
=35-47+123-35+20-123+57
=(35-35)+(123-123)+(-47+57)
=0+0+(-10)
=-10
