Thực hiện phép tính 

a ) \(\frac{2}{5}+\frac{-1}{6}-\frac{3}{4}-\frac{-2}{3}\)

= \(\frac{2}{5}+\frac{-1}{6}+\frac{-3}{4}+\frac{2}{3}\)

= \(\left(\frac{2}{5}+\frac{-3}{4}\right)+\left(\frac{-1}{6}+\frac{2}{3}\right)\)

= \(\left(\frac{8}{20}+\frac{-15}{20}\right)+\left(\frac{-1}{6}+\frac{4}{6}\right)\)

= \(\left(\frac{8+\left(-15\right)}{20}\right)+\left(\frac{\left(-1\right)+4}{6}\right)\)

= \(\frac{-7}{20}+\frac{1}{2}\)

= \(\frac{-7}{20}+\frac{10}{20}=\frac{\left(7\right)+10}{20}=\frac{3}{20}\)

tk mk nha 

đang âm rất  nhiều rồi  , giúp nha !!!!!

nhanh

a)\(\left(\frac38+\frac{-3}{4}+\frac{7}{12}\right):\frac56+\frac12\)

=\(\left(\frac{9}{24}+\frac{-18}{24}+\frac{14}{24}\right)\times\frac65+\frac12\)

=\(\frac{5}{24}\times\frac65+\frac12\)

=\(\frac14+\frac12\)

=\(\frac14+\frac24\)

=\(\frac34\)

b)\(\frac12+\frac34-\left(\frac34-\frac45\right)\)

=\(\frac12+\frac34-\frac34+\frac45\)

=\(\left(\frac12+\frac45\right)+\left(\frac34-\frac34\right)\)

=\(\left(\frac{5}{10}+\frac{8}{10}\right)+0\)

=\(\frac{13}{10}\)

a) \(\frac{9}{20}\)                                                   c) \(\frac{-55}{4}\)                                                                                                                                 

b) \(\frac{116}{75}\)                                                d) \(\frac{-76}{45}\)

đúng hết đấy nhé mình tính kĩ lắm ko sai đâu

       chúc may mắn

|\(\frac32x\) + \(\frac12\)| = |4\(x\) - 1|

\(\left[\begin{array}{l}\frac32x+\frac12=-4x+1\\ \frac32x+\frac12=4x-1\end{array}\right.\)

\(\left[\begin{array}{l}\frac32x+4x=1-\frac12\\ \frac32x-4x=-1-\frac12\end{array}\right.\)

\(\left[\begin{array}{l}\frac{11}{2}x=\frac12\\ -\frac52x=-\frac32\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12:\frac{11}{2}\\ x=-\frac32:\frac{-5}{2}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12\times\frac{2}{11}\\ x=-\frac32\times\frac{-2}{5}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{1}{11}\\ x=\frac35\end{array}\right.\)

Vậy \(x\in\) {\(\frac{1}{11};\frac35\)}

|\(\frac54x\) - \(\frac72\)| - |\(\frac58x\) + \(\frac35\)| = 0

|\(\frac54x\) - \(\frac72\)| = |\(\frac58x\) + \(\frac35\)|

\(\left[\begin{array}{l}\frac54x-\frac72=-\frac58x-\frac35\\ \frac54x-\frac72=\frac58x+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac54x+\frac58x=\frac72-\frac35\\ \frac54x-\frac58x=\frac72+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac{15}{8}x=\frac{29}{20}\\ \frac58x=\frac{41}{10}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{29}{10}:\frac{15}{8}\\ x=\frac{41}{10}:\frac58\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{116}{75}\\ x=\frac{164}{25}\end{array}\right.\)

Vậy \(x\in\) {\(\frac{116}{75}\); \(\frac{164}{25}\)}

a) A = \(\frac{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}+\frac{4}{41}}\)= \(\frac{\frac{21}{35}+\frac{15}{35}-\frac{3}{11}}{\frac{28}{35}+\frac{20}{35}+\frac{4}{41}}\)= \(\frac{\frac{36}{35}-\frac{3}{11}}{\frac{48}{35}+\frac{4}{41}}\)= \(\frac{\frac{36}{35}-\frac{36}{132}}{\frac{48}{35}+\frac{48}{492}}\)

Từ đây bạn tự làm nha

b) \(\frac{-1}{2}+\frac{-2}{2}+\frac{-3}{4}\)

= \(\frac{-3}{2}\)+ \(\frac{-3}{4}\)

= \(\frac{-6}{4}\)+ \(\frac{-3}{4}\)

= \(\frac{-9}{4}\)

Dài quá mình làm 2 bài này thôi

Bài 1 câu c làm tương tự câu a

Bạn đăng lên nhiều bài quá làm đến đêm mất

Có khi làm đến đêm còn chưa xong nữa là

Bạn đăng lần lượt thôi chứ

a. 5,85

b. c. hỗn số hay không

d.\(\frac{23}{20}\)

e.\(\frac{13}{12}\)

a) \(\left(-0,75+\frac{1}{2}\right):\frac{4}{3}\)

\(=\frac{-1}{4}:\frac{4}{3}\)

\(=\frac{-3}{16}\)

b) \(\frac{5}{9}.\frac{2}{7}+\frac{5}{9}.\frac{5}{7}-\frac{8}{3}\)

\(=\frac{5}{9}.\left(\frac{2}{7}+\frac{5}{7}\right)-\frac{8}{3}\)

\(=\frac{5}{9}.1-\frac{8}{3}\)

\(=\frac{-19}{9}\)

c)  \(7,5.1\frac{3}{4}-6\frac{2}{5}\)

\(=\frac{15}{2}.\frac{7}{4}-\frac{32}{5}\)

\(=\frac{269}{40}\)

a)\(\left(4\frac{5}{37}-3\frac45+8\frac{15}{29}\right)-\left(3\frac{5}{57}-6\frac{14}{29}\right)\)

=\(4\frac{5}{37}-3\frac45+8\frac{15}{29}-3\frac{5}{37}+6\frac{14}{29}\)

=\(\left(4\frac{5}{37}-3\frac{5}{37}\right)+\left(8\frac{15}{29}+6\frac{14}{29}\right)-3\frac45\)

=\(\left\lbrack\left(4-3\right)+\left(\frac{5}{37}-\frac{5}{37}\right)\right\rbrack+\left\lbrack\left(8+6\right)+\left(\frac{15}{29}\right.\right.\)+\(\frac{14}{29})\) -\(\frac{19}{5}\)

=\(1+0+14+1-\frac{19}{5}\)

=\(15+1-\frac{19}{5}\)

=\(16-\frac{19}{5}\)

=\(\frac{80}{5}-\frac{19}{5}\)

=\(\frac{61}{5}\)