4/5 x 0,5 + 12/5 x 0,3 + 8 : 10 x 0,2

=4/5 x 0,5 + 12/5 x 0,3 + 4/5 x 0,2

=(4/5 + 12/5 + 4/5) x (0,5 + 0.3 + 0,2)

=4 x 1

=4

\(\frac{4}{5}x0,5+\frac{12}{5}x0,3+8:10x0,2=\)\(\frac{4}{5}x0,5+\frac{12}{5}x0,3+\frac{8}{10}x0,2=\)\(\frac{4}{5}x0,5+\frac{12}{5}x0,3+\frac{4}{5}x0,2=\)

\(=\frac{4}{5}x\left(0,5+0,2\right)+\frac{12}{5}x0,3\)\(=\frac{4}{5}x\frac{7}{10}+\frac{12}{5}x0,3=\frac{32}{25}\)

\(=\frac{4}{11}\times\left(\frac{5}{13}+\frac{8}{13}\right)\)

\(=\frac{4}{11}\times1\)

\(=\frac{4}{11}\)

Chúc cậu học tốt

\(=\frac{4}{11}\times\left(\frac{5}{13}+\frac{8}{13}\right)\)

\(=\frac{4}{11}\times1\)

\(=\frac{4}{11}\)

a)\(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{1}{3}\right)+3\)

\(=1+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3\)

\(=1+3+\frac{7}{9}\)

\(=4\frac{7}{9}\)

\(=\frac{43}{9}\)

b)\(\frac{8}{5}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{2}{5}-1\)

\(=\frac{4}{7}\cdot\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}\cdot2-1\)

\(=\frac{8}{7}-1\)

\(=\frac{1}{7}\)

a) \(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3=4\frac{7}{9}\)

b)\(\frac{8}{5}.\frac{4}{7}+\frac{4}{7}.\frac{2}{5}-1\)

\(=\frac{4}{7}.\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}.2-1\)

\(=\frac{8}{7}-\frac{7}{7}=\frac{1}{7}\)

= ( 25% + 35% + 65% + 75% ) x ( 1 + 2/3 + 4 + 1/3 )

= ( ( 25% + 75% ) + ( 35% + 65% ) ) x 6

= 2 x 6 = 12

\(\left(\frac{1}{4}+35\%+0,65+75\%\right)\)\(x\left(1\frac{6}{9}+4\frac{8}{24}\right)\)

\(=\left(\frac{1}{4}+\frac{7}{20}+\frac{65}{100}+\frac{3}{4}\right)\)\(x\left(\frac{15}{9}+\frac{13}{3}\right)\)

\(=\left(\frac{5}{20}+\frac{7}{20}+\frac{13}{20}+\frac{15}{20}\right)\)\(x6\)

\(=2x6\)

\(=12\)

\(\frac{3}{4}\)x \(\frac{15}{7}\)+ \(\frac{6}{7}\)x \(\frac{6}{8}\)

= \(\frac{45}{28}\)+ \(\frac{9}{14}\)

= \(\frac{9}{4}\)

#Hoctot

\(\frac{3}{4}\times\frac{15}{7}+\frac{6}{7}\times\frac{6}{8}\)

\(=\frac{3}{4}\times\frac{15}{7}+\frac{6}{7}\times\frac{3}{4}\)

\(=\frac{3}{4}\times\left(\frac{15}{7}+\frac{6}{7}\right)\)

\(=\frac{3}{4}\times3\)

\(=\frac{9}{4}\)

Học tốt

1 nha

chúc bạn học tốt

click cho mình xin 1 điểm hỏi đáp

ok

\(\frac{1}{2}\)x \(\frac{9}{10}\)+ \(\frac{8}{10}\)+ \(\frac{2}{4}\)+ \(\frac{3}{10}\)x \(0,5\)

= \(0,5\)x \(0,9\)+ \(0,8\)+ \(0,5\)x \(0,5\)

\(=0,45\)x \(1,3\)x \(0,5\)

\(=0,45\)x \(0,65=0,2925\)

bài 6 \(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+\ldots+\frac{2}{80\times82}+\frac{2}{82\times84}\)

= \(\frac12-\frac14+\frac14-\frac16+\frac16-\cdots+\frac{1}{80}-\frac{1}{82}+\frac{1}{82}-\frac{1}{84}\)

= \(\frac12-\left(\frac14-\frac14\right)-\left(\frac16-\frac16\right)-\cdots-\left(\frac{1}{82}-\frac{1}{82}\right)-\frac{1}{84}\)

=\(\frac12-0-0-\frac{1}{84}\)

=\(\frac12\) - \(\frac{1}{84}\)

=\(\frac{42}{84}-\frac{1}{84}\)

=\(\frac{41}{84}\)

Bài 7

a)\(\frac{19}{4}=4\frac34\)

b)\(\frac{27}{5}=5\frac25\)

c)\(\frac{56}{8}=7\frac08\)

A = \(\left(\frac{3}{10}+\frac{4}{5}x\frac{1}{2}\right):\left(1\frac{8}{9}-1\frac{1}{3}\right)\)

= \(\left(\frac{3}{10}+\frac{4}{10}\right):\left(\frac{17}{9}-\frac{4}{3}\right)\)

=\(\frac{7}{10}:\left(\frac{17-12}{9}\right)\)

= \(\frac{7}{10}:\frac{5}{9}\)

= \(\frac{7}{10}x\frac{9}{5}\)

= \(\frac{63}{50}\)

\(A=\left(\frac{3}{10}+\frac{4}{5}\times\frac{1}{2}\right):\left(1\frac{8}{9}-1\frac{1}{3}\right)\)

\(\Rightarrow A=\left(\frac{3}{10}+\frac{2}{5}\right):\left(\frac{17}{9}-\frac{4}{3}\right)\)

\(\Rightarrow A=\frac{7}{10}:\frac{5}{9}\)

\(\Rightarrow A=\frac{63}{50}\)

tíc mình nha

ai giải được

\(8\frac{7}{10}+2\frac{3}{4}=\frac{87}{10}+\frac{11}{4}=\frac{174}{20}+\frac{55}{20}=\frac{229}{20}\)

Bạn chỉ cần đưa về phân số xong tính bình thường. Muốn đổi từ hỗn số sang phân số, ta chỉ cần lấy phần nguyên nhân cho mẫu rồi cộng với tử là xong. Chứ bạn cứ hỏi mấy bài dễ như thế này thì k giỏi đc đâu!!!

a) \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{5}{11}+\frac{2}{5}+\frac{19}{13}=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{5}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)=1+1+2=4\)

b) \(\frac{6}{5}\times\frac{3}{8}+\frac{5}{8}\times\frac{6}{5}-\frac{4}{5}=\frac{6}{5}\times\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{4}{5}=\frac{6}{5}-\frac{4}{5}=\frac{2}{5}\)

c) \(\frac{4\times5\times6\times7\times8}{8\times10\times12\times14\times16}=\frac{1}{2\times2\times2\times2\times2}=\frac{1}{32}\)

a, \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{6}{11}+\frac{2}{5}+\frac{19}{13}\)

\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{6}{11}+\frac{6}{11}\right)\)

\(=1+2+\frac{12}{11}\)

\(=3+\frac{12}{11}\)

\(=\frac{45}{11}\)