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$\textbf{a)}$
$4\cdot\left(\dfrac14\right)^2+25\cdot\left[\left(\dfrac34\right)^3:\left(\dfrac54\right)^3\right]:\left(\dfrac32\right)^3$
$=\dfrac14+25\cdot\left(\dfrac35\right)^3:\left(\dfrac32\right)^3$
$=\dfrac14+25\cdot\dfrac{27}{125}\cdot\dfrac8{27}$
$=\dfrac14+\dfrac85$
$=\dfrac{5+32}{20}$
$=\boxed{\dfrac{37}{20}}.$
$\textbf{b)}$
$2^3+3\cdot\left(\dfrac12\right)^0+(-1)+\left[(-2)^2:\dfrac12\right]-8$
$=8+3\cdot1-1+\dfrac4{1/2}-8$
$=8+3-1+8-8$
$=\boxed{10}.$
Biểu thức 1
$3\dfrac12\cdot\dfrac4{49}-\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{8}\right)$
$=\dfrac72\cdot\dfrac4{49}-\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\left(-\dfrac4{21}\right)$
$=\dfrac27-6\cdot\left(-\dfrac4{21}\right)$
$=\dfrac27+\dfrac87$
$=\dfrac{10}{7}.$
Biểu thức 2
$\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot3\dfrac13\right):\dfrac43$
$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac{10}{3}\right):\dfrac43$
$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac43\cdot\dfrac34$
$=\dfrac{10}{81}\cdot\dfrac{99}{250}-1$
$=\dfrac{11}{225}-1$
$=-\dfrac{214}{225}.$
Câu 1:
(3/5)^15 : (9/25)^5
= (3/5)^15 : (3/5)^10
= (3/5)^5
Câu 2:
5 - (-5/11)^0 + (1/3)^2 - 3
= 5 - 1 + 1/9 - 3
= (5 - 1 - 3) + 1/9
= 1 + 1/9
= 10/9
\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)
\(=3-\left(-1\right)\)
\(=4\)
b) \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)
\(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)
\(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)
\(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)
\(=\frac{199}{16}:\left(12-2\right)\)
\(=\frac{199}{16}:10\)
\(=\frac{199}{160}\)
c) \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)
\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)
\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)
1, \(5-\left(-\frac{5}{11}\right)^0+\left(\frac{1}{3}\right)^2.\frac{1}{3}=5-1+\frac{1}{9}.\frac{1}{3}=4+\frac{1}{27}=4\frac{1}{27}\)
2, \(2^3+3.1+\left(4.2\right).8=8+3+8.8=75\)
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