1, A=\(\frac{3}{2}.\frac{4}{3}.\frac{5}{4}....\frac{100}{99}\)

   A= \(\frac{100}{2}\)

   A=50

2, B=\(\frac{-1}{2}.\frac{-2}{3}....\frac{-98}{99}\)

     B= \(\frac{1}{99}\)

\(A=\left(\frac{1}{2}+1\right)\cdot\left(\frac{1}{3}+1\right)\cdot\left(\frac{1}{4}+1\right)......\left(\frac{1}{99}+1\right)\)

     \(=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}......\frac{99}{98}\cdot\frac{100}{99}\)

     \(=\frac{100}{2}\)

       \(=50\)

\(B=\left(\frac{1}{2}-1\right)\cdot\left(\frac{1}{3}-1\right)\cdot\left(\frac{1}{4}-1\right)......\left(\frac{1}{99}-1\right)\)

     \(=\left(-\frac{1}{2}\right)\cdot\left(-\frac{2}{3}\right)\cdot\left(-\frac{3}{4}\right).....\left(-\frac{97}{98}\right)\cdot\left(-\frac{98}{99}\right)\)

       \(=-\frac{1}{99}\)

a) \(=\frac{3}{2}.\frac{4}{3}....\frac{100}{99}=\frac{100}{2}=50\)

a) =3/2 . 4/3 . 5/4 ...100/99

   =\(\frac{3.4.5...100}{2.3.4..99}\)

  =\(\frac{100}{2}\)

b) =

biết làm bài 1 thôi

\(\left(\frac{1}{2}+1\right)\times\left(\frac{1}{3}+1\right)\times\cdot\cdot\cdot\times\left(\frac{1}{999}+1\right)\)

= \(\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\cdot\cdot\cdot\times\frac{1000}{999}\)

lượt bỏ đi còn :

\(\frac{1000}{2}=500\)

Bài 2:

B = (1/2 - 1)(1/3 -1).(1/4 -1)...(1/1000 - 1)

B = (1/2 - 2/2).(1/3 - 3/3)...(1/1000 - 1000/1000)

B = (-1/2).(-2/3)...(-999/1000)

Xét dãy số: 1; 2 ;3;...999

Dãy số trên có 999 số hạng vậy B là tích của 999 số âm

B = - 1/1000

\(P=\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right).....\left(1+\frac{1}{99}\right)\)

     \(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.....\frac{100}{99}\)

     \(=\frac{100}{2}\)

     =500

1+1=3 :)))

\(A=\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right)..........\left(\frac{1}{99}+1\right)\)

\(=\frac{3}{2}.\frac{4}{3}.........\frac{100}{99}\)

\(=\frac{100}{2}=50\)

\(B=\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right).........\left(\frac{1}{100}-1\right)\)

\(=-\frac{1}{2}.-\frac{2}{3}..........-\frac{99}{100}\)

\(=\frac{-1}{100}\)

\(A=\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right)\left(\frac{1}{4}+1\right)......\left(\frac{1}{99}+1\right)\)

  \(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.....\frac{100}{99}\)

\(=\frac{3.4.5.....100}{2.3.4.....99}\)

 \(=\frac{100}{2}=50\)

\(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right)\cdot\cdot\left(1+\frac{1}{99}\right)\)

\(=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot\cdot\cdot\cdot\frac{100}{99}\)

\(=\frac{100}{2}=50\)

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{99}\right)\)

\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{100}{99}\)

\(=\frac{3.4.5...100}{2.3.4...99}\)

\(=\frac{100}{2}\)

\(=50\)

Bài 1:

1/6 + -5/7 : x = - 7/18

5/7: x = 1/6 + 7/18

5/7: x = 3/18 + 7/18

5/7: x = 5/9

x = 5/7 : 5/9

x = 5/7 x 9/5

x = 9/7

Vậy x = 9/7

Bài 2:

Câu a:

(1/2 + 1).(1/3 + 1).(1/4 + 1)...(1/999 + 1)

= (1/2 + 2/2).(1/3 + 3/3)...(1/999 + 999/999)

= 3/2.4/3....1000/999

= 1000/2

= 500