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a) 128 - [116-\(\left(132-128\right)^2\)]
= 128-[116-\(4^2\)]
= 128-[116-8]
=128-108
= 20
b) 371+(-590)+(-271)+730
=371-590-271+730
= 240
c) 279 -(145+279)
= 279-424
= -145
d) 2341-243+(-2240)
= 2341-243-2240
= -142
e) -26 +8 . (11+7)
= -26 + 8 . 18
= -26 +144
= 118
g) 47. (23+50) - 23 . (47 + 50)
= 47.73-23.97
= 3431-2231
= 1200
a. 128- [116-(132−128)\(^2\)]
= 128 - [ 116 - \(4^2\) ]
= 128 - [ 116 -16 ]
= 128 - 100
= 28
b. 371+(-590)+(-271)+730
= [ 371 + (-271) ] + [ 730 + (-590) ]
= 100 + 140
= 240
c. 279 - ( 145 +279)
= 279 - 145 - 279
= ( 279 -279 ) -145
= 0 - 145
= -145
d. 2341 - 243+(-2240)
= 2098 + (-2240)
= -142
e. -26 + 8 . ( 11+7)
= -26 + 8 . 18
= -26 + 144
= 118
g. 47 . ( 23+50) - 23. (47 +50)
= 47 . 73 - 23 . 97
= 3431 - 2231
= 1200
24.x-32.x=145-255:51
16.x-9.x=145-5
16.x-9.x=140
x.(16-9)=140
x.7=140
x=140:7
x=20
580:(x-24)=329-150:2=ko bít
7.(x-4)+35=25+279:9
7.(x-4)+35=25+31
7.(x-4)+35=56
7.(x-4)=56-35
7.(x-4)=21
x-4=21:7
x-4=3
x=3+4
x=7
Ủng
hộ
nha
!
a) \(2^4.x-3^2.x=145-\frac{255}{51}\Rightarrow x.\left(2^4-3^2\right)=145-5\)
\(\Rightarrow7.x=140\Rightarrow x=20\)
b) \(\frac{580}{x-24}=329-150.2\Rightarrow\frac{580}{x-24}=329-300\Rightarrow\frac{580}{x-24}=29\Rightarrow x-24=20\)
\(\Rightarrow x=44\)
c) \(7.\left(x-14\right)+35=25+\frac{279}{9}\Rightarrow7.\left(x-14\right)=25+31-35\)
\(\Rightarrow7.\left(x-14\right)=21\Rightarrow x-14=3\Rightarrow x=17\)
329 + (15 - 101) - (25 - 440)
= 329 + (-86) - (-415)
= 243 - (-415)
= 658
máy tính casio hân hạnh tài trợ :'>
Máy tính Casio hân hạnh tài trợ
\(c,\)\(C=279-\left(145+279\right)+145\)
\(C=279-145-279+145\)
\(C=\left(279-279\right)+\left(145-145\right)\)
\(C=0+0\)
\(C=0\)
Vậy C = 0
\(d,\)\(D=-479-\left(2002-479\right)+\left(2002-18\right)\)
\(D=-479-2002+479+2002-18\)
\(D=\left(-479+479\right)+\left(-2002+2002\right)-18\)
\(D=0+0-18\)
\(D=-18\)
Vậy D = -18
\(e,\)\(E=-\left(3251-243\right)+\left(3250-243\right)\)
\(E=-3251+243+3250-243\)
\(E=\left(-3251+3250\right)+\left(243-243\right)\)
\(E=-1+0\)
\(E=-1\)
Vậy E = -1
\(f,\)\(F=-3752-\left(29-3652\right)-51\)
\(F=-3752-29+3652-51\)
\(F=\left(-3752+3652\right)-\left(29+51\right)\)
\(F=-100-80\)
\(F=-180\)
Vậy F = -180
\(g,\)\(G=-329+\left(15-101\right)-\left(25-440-329\right)\)
\(G=-329+15-101-25+440+329\)
\(G=\left(-329+329\right)+\left(15-25\right)+\left(-101+440\right)\)
\(G=0-10+339\)
\(G=329\)
Vậy G = 329
Banh Bao Tong
\(C=279-\left(145+279\right)+145\)
\(C=279-145-279+145\)
\(C=\left(279-279\right)+\left[\left\{-145\right\}+145\right]\)
\(C=0+0\)
\(C=0\)
\(D=-479-\left(2002-479\right)+\left(2002-18\right)\)
\(D=-479-2002+479+2002-18\)
\(D=\left[\left\{-479\right\}+479\right]+\left[\left\{-2002+2002\right\}\right]-18\)
\(D=0+0-18\)
\(D=-18\)
\(E=-\left(3251-243\right)+\left(3250-243\right)\)
\(E=-3251+243+3250-243\)
\(E=\left[\left\{-3251+3250\right\}\right]+\left(243-243\right)\)
\(E=-1+0\)
\(E=-1\)
\(F=-3752-\left(29-3652\right)-51\)
\(F=-3752-29+3652-51\)
\(F=\left[\left\{-3752+3652\right\}\right]+\left(-29\right)-51\)
\(F=-100+\left(-29\right)-51\)
\(F=-180\)
\(G=-329+\left(15-101\right)-\left(25-440-329\right)\)
\(G=-329+15-101-25+440+329\)
\(G=\left[\left\{-329\right\}+329\right]+\left(15-25\right)+\left[\left\{-101\right\}+440\right]\)
\(G=0+\left(-10\right)+339\)
\(G=329\)