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a, 19 x 64 + 76 x 34
= 19 x 2 x 32 + 38 x 2 x 34
= 38 x 32 + 38 x 68
= 38 x ( 32 + 68 )
= 38 x 100
= 3800
b, 35 x 12 + 65 x 13
= 35 x 12 + 65 x 12 + 65
= ( 35 + 65 ) x 12 + 65
= 100 x 12 + 65
= 1200 + 65
= 1265
d, ( 2 + 4 + 6 + ... + 1000) x ( 36 x 333 - 108 x 111 )
= ( 2 + 4 + 6 + ... + 1000 ) x ( 36 x 3 x 111 - 108 x 111)
= ( 2 + 4 + 6 + ...+ 1000 ) x ( 108 x 111 - 108 x 111 )
= ( 2 + 4 + 6 + ... + 1000 ) x 0
= 0
Câu c chịu
a) = 35 x 12 + 65 x 12 + 65 = (35 + 65) x 12+ 65 = 100 x 12 + 65 = 1200 + 65 = 1265
b) tuong tu a
b) (2 + 4 + 6 + ...+ 100) x ( 36 x 3 x 111 - 36 x 3 x 111) = (2 + 4 + 6 + ...+ 100) x 0 = 0
\(\left(2+4+6+...+100\right).\left(36.333-108.111\right)=\)\(\left(2+4+6+...+100\right).\left(36.3.111-36.3.111\right)\)\(=\left(2+4+6+...+100\right).0\)\(=0\)
Ta có:
( 2+4+6+....+100) X ( 36X333 - 108X111)
=( 2+4+6+....+100) X ( 36X3X111 - 108X111)
( 2+4+6+....+100) X ( 108X111 - 108X111)
( 2+4+6+....+100) X 0
=0
a) = 35 x 12 + 65 x 12 + 65 = (35 + 65) x 12+ 65 = 100 x 12 + 65 = 1200 + 65 = 1265
b) (2 + 4 + 6 + ...+ 100) x ( 36 x 3 x 111 - 36 x 3 x 111) = (2 + 4 + 6 + ...+ 100) x 0 = 0
35x12+65x13=1265
(2+4+6+.....100) x(36x333-108x111)=0
Ta có
(2 + 4 + 6 + ...+ 100) x ( 36 x 3 x 111 - 36 x 3 x 111)
= (2 + 4 + 6 + ...+ 100) x 0
= 0
hok tốt
b/
(2+4+6+ 7...+100) x (36x3 x111 - 36 x 3 x111)
=(2 + 4 +6...+100 )x 0
= 0
bạn trần thị loan ơi,cho mik hỏi,65 ở cuối cùng chỗ:(35+65)x12+65 ấy!
35x12+65x13 = 35x12+65x(12+1) = 35x12+65x12+65 = 12x(35+65) +65 = 12x100+65 =1200+65 =1265
(2+4+6+...+100)x(36x333-108x111)
=(2+4+6+...+100)x(36x3x111-108x111)
= (2+4+6+...+100)x(108x111-108x111)
=(2=4+6+..+100)x0
=0
35x12+65x13
=35x12+65x12+1
=12.(35+65)+1
=12.100+1
=1200+1
=1201
b) (2+4+6+...+100)x(36x333-108x111)
=A x (11988-11988)
=Ax0
=0
35x12+65x12=(35+65)x12
=100x12
=1200
(2+4+6+...+100)x(36x333-108x111)=(2+4+6+...+100)x(36x333-(108:3)x(111x3))
=(2+4+6+...100)x(36x333-36x333)
=(2+4+6+...+100)x0
=0