\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(=\left(\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{1}{12}+\frac{1}{24}\right)+\left(\frac{1}{48}+\frac{1}{96}\right)\)

\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)

\(=\frac{21}{32}\)

Đáp án là :\(\frac{21}{32}\)

1/3 +1/6+1/12+1/24 +1/48 + 1/96

= 1/3 + 1/3 – 1/6 + 1/6 – 1/12+1/12 – 1/24 +1/24 – 1/48+1/48 -1/96

=2/3 – 1/96

= 21/32

1/1.3 + 1/3.2 + 1/2.6 + 1/6.4 + 1/4.12 + 1/12.8

= 1 - 1/3 + 1/3 - 1/2 + 1/2 - 1/6 + 1/6 - 1/4 + 1/4 -1/12 + 1/12 - 1/8 

= 1 - 1/8

= 8/8 - 1/8

=7/8

đúng 100% nha...

nhớ tích mk nha

  \(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

= \(\frac{1}{3}+\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{12}+\frac{1}{12}-\frac{1}{24}+\frac{1}{24}-\frac{1}{48}+\frac{1}{48}-\frac{1}{96}\)

= \(\frac{1}{3}+\frac{1}{3}-\frac{1}{96}\)

= \(\frac{2}{3}-\frac{1}{96}\)

= \(\frac{21}{32}\)

\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)

\(2\times A=\frac{2}{3}+\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}\)

\(2\times A-A=\left(\frac{2}{3}+\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}\right)-\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\right)\)

\(A=\frac{2}{3}-\frac{1}{96}\)

\(A=\frac{21}{32}\)