64 ;  128 ; 256

36 ; 49 ; 64

13 ; 21 ; 34

42 ; 56 ; 72            

Đặt A = 1 + 2 + 4 + ... + 2048

A = 1 + 2 + 2² + ... + 2¹¹

2A = 2 + 2² + 2³ + ... + 2¹²

2A - A = ( 2 + 2² + 2³ + ... + 2¹² ) - ( 1 + 2 + 2² + ... + 2¹¹ )

A = 2¹² - 1

4095

HỌC TỐT

a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)

\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)

b)\(5+\dfrac{3}{5}=\dfrac{25}{5}+\dfrac{3}{5}=\dfrac{28}{5};10-\dfrac{9}{16}=\dfrac{160}{16}-\dfrac{9}{16}=\dfrac{151}{16}\)

\(\dfrac{2}{3}-\left(\dfrac{1}{6}+\dfrac{1}{8}\right)=\dfrac{2}{3}-\left(\dfrac{8}{48}+\dfrac{6}{48}\right)=\dfrac{2}{3}-\dfrac{14}{48}=\dfrac{32}{48}-\dfrac{14}{48}=\dfrac{3}{8}\)

3(1/2+1/4+1/8+1/16.....1/128)

A=(1/2+1/4+1/8+1/16....1/128)

2A-A=A

2A=(1/2+1/4+1/8....1/128)*2

=1+1/2+1/4....1/64

2A-A=1+1/2+1/4+1/8....1/64-(1/2+1/4+1/8......1/128)

A=1-1/128=127/128

Đáp số:3*127/128=381/128

= (3/2+3/32)+(3/4+3/64)+(3/8+3/128)+3/16

= 51/32 +51/64 +51/128 +3/16

= (51/32+51/128)+(51/64+3/16)

=255/128 +63/64

=255/128 + 126/128

=381/128

giúp tôi với

ý a bạn nhé

`->D` 

vì : `4/16=(4:4)/(16:4)=1/4`

      `2/8=(2:2)/(8:2)=1/4`

      `3/12=(3:3)/(12:3)=1/4`

a/=9/12+8/12+5/12=9+8+5/12=22/12=11/6

160 dễ mà.

\(16\cdot2+8\cdot4+32\cdot3\)

\(=32+32+32\cdot3\)

\(=32\cdot\left(1+1+3\right)\)

\(=32\cdot5=160\)