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\(\frac{\left(13\frac{1}{4}-2\frac{5}{7}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}=\frac{\left(\frac{53}{4}-\frac{19}{7}-\frac{65}{6}\right).\frac{5751}{25}+\frac{187}{4}}{\left(\frac{13}{10}+\frac{10}{3}\right):\left(\frac{37}{3}-\frac{100}{7}\right)}\)
\(=\frac{\left(\frac{1113}{84}-\frac{228}{84}-\frac{910}{84}\right).\frac{5751}{25}+\frac{187}{4}}{\left(\frac{39}{30}+\frac{100}{30}\right):\left(\frac{259}{21}-\frac{300}{21}\right)}\)
\(=\frac{\frac{-25}{84}.\frac{5751}{25}+\frac{187}{4}}{\frac{139}{30}:\frac{-41}{21}}\)
\(=\frac{\frac{-1917}{28}+\frac{1309}{28}}{\frac{139}{30}.\frac{-21}{41}}\)
\(=\frac{\frac{-608}{28}}{\frac{-973}{410}}=\frac{-152}{7}.\frac{410}{-973}=\frac{62320}{6811}\)
\(E=\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(E=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{5751}{25}+\dfrac{187}{4}}{\dfrac{100}{21}:\left(-\dfrac{41}{21}\right)}\)
\(E=\dfrac{\dfrac{25}{108}.\dfrac{5751}{25}+\dfrac{187}{4}}{-\dfrac{100}{41}}\)
\(E=\dfrac{\dfrac{213}{4}+\dfrac{187}{4}}{-\dfrac{100}{41}}\)
\(E=\dfrac{100}{-\dfrac{100}{41}}\)
\(E=-41\)
\(E=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{5751}{25}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)
\(=\dfrac{\dfrac{25}{108}.\dfrac{5751}{25}+\dfrac{187}{4}}{\dfrac{100}{21}:\left(\dfrac{-44}{21}\right)}\)
\(=\dfrac{53,25+\dfrac{187}{4}}{\dfrac{-25}{11}}\)
\(=\dfrac{100}{\dfrac{-25}{11}}\)
\(=-44\)
Ta có: \(\left(13\frac14-2\frac{5}{27}-10\frac56\right)\cdot230\frac{1}{25}+46\frac34\)
\(=\left(13+\frac14-2-\frac{5}{27}-10-\frac56\right)\cdot230,04+46,75\)
\(=\left(1+\frac14-\frac{5}{27}-\frac56\right)\cdot230,04+46.75\)
\(=\left(\frac{108}{108}+\frac{27}{108}-\frac{20}{108}-\frac{90}{108}\right)\cdot230,04+46,75\)
\(=\frac{25}{108}\cdot230,04+46,75=53,25+46,75=100\)
Ta có: \(\left(1\frac37+\frac{10}{3}\right):\left(12\frac13-14\frac27\right)\)
\(=\left(\frac{10}{7}+\frac{10}{3}\right):\left(12+\frac13-14-\frac27\right)\)
\(=\left(\frac{30}{21}+\frac{70}{21}\right):\left(-2+\frac13-\frac27\right)\)
\(=\frac{100}{21}:\left(-2+\frac{7}{21}-\frac{6}{21}\right)=\frac{100}{21}:\left(-2+\frac{1}{21}\right)=\frac{100}{21}:\frac{-41}{21}=\frac{-100}{41}\)
Ta có: \(\frac{\left(13\frac14-2\frac{5}{27}-10\frac56\right)\cdot230\frac{1}{25}+46\frac34}{\left(1\frac37+\frac{10}{3}\right):\left(12\frac13-14\frac27\right)}\)
\(=100:\frac{-100}{41}=-41\)