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M=10/56+10/140+10/260+...+10/1400
=5/28+5/70+5/130+...+5/700
=5/4.7+5/7.10+5/10.13+...+5/25.28
=5/3(3/4.7+3/7.10+3/10.13+...+3/25.28)
=5/3(1/4-1/7+1/7-1/10+1/10-1/1+...+1/25-1/28)
=5/3.(1/4-1/28)
=5/3.3/14
=5/14
M=5/28+5/70+...+5/700=5/4.7+5/7.10+...+5/25.28=>3M=5(1/4-1/7+1/7-1/10+...+1/25-1/28)
=>3M=5(1/4-1/28)=>3M=15/14=>M=5/14
Đầu tiên rút gọn M trước
M= 5/28 + 5/70 +.....+10/700
= 5/(4.7)+5/(7.10)+....5/(25.28)
3M= 5( 1/4 - 1/7 +1/7-1/10+......+1/25-1/28)
3M= 5 (1/4-1/28)
3M=15/14
M= 5/14 :D
Đặt S= 5/28 + 5/70 + 5/130 +.....+5/700
= 5/4.7 + 5/7.10 + ......+ 5/ 25.28
3S/5=1/4-1/7+1/7-1/10+.....+1/25-1/28
3S/5=1/4-1/28
3S/5=3/14
3S=3/14x5
3S=15/14
S=15/14x1/3
S=15/42
= 5/28+5/70+5/130+...+5/700
=5/3.(3/4.7+3/7.10+3/10.13+...+3/25.28)
=5/3.(1/4-1/7+1/7-1/10+1/10-1/13+...+1/25-1/28)
=5/3.(1/4-1/28)=5/3.3/14=5/14
k mik nha
Sửa đề: \(M=\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+\cdots+\frac{10}{1400}\)
Ta có: \(M=\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+\cdots+\frac{10}{1400}\)
\(=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+\cdots+\frac{5}{700}\)
\(=\frac{5}{4\cdot7}+\frac{5}{7\cdot10}+\frac{5}{10\cdot13}+\cdots+\frac{5}{25\cdot28}\)
\(=\frac53\left(\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\cdots+\frac{3}{25\cdot28}\right)\)
\(=\frac53\left(\frac14-\frac17+\frac17-\frac{1}{10}+\cdots+\frac{1}{25}-\frac{1}{28}\right)\)
\(=\frac53\left(\frac14-\frac{1}{28}\right)=\frac53\cdot\frac{6}{28}=\frac53\cdot\frac{3}{14}=\frac{5}{14}\)