Câu hỏi của Phan Hoàng Mai

Question

Tính :

$\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right)\times\frac{3}{8}-72:12^2$

Nguyễn Thanh Hằng · Accepted Answer

$\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2$

$=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}$

$=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}$

$=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}$

$=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}$

$=\dfrac{3}{8}$

Câu trả lời:

$\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2$

$=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}$

$=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}$

$=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}$

$=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}$

$=\dfrac{3}{8}$