4⁶.9⁵+6⁹.120 / 8⁴.3¹²-6¹¹

=(2²)⁶.(3²)⁵+(2.3)⁹.2³.3.5 / (2³)⁴.3¹²-(2.3)¹¹

=2¹².3¹⁰+2⁹.3⁹.2³.3.5 / 2¹².3¹²-2¹¹.3¹¹

=2¹².3¹⁰+2¹².3¹⁰.5 / 2¹¹.3¹¹.(2.3-1)

=2¹².3¹⁰.(1+5) / 2¹¹.3¹¹.(6-1)

=2¹².3¹⁰.6 / 2¹¹.3¹¹.5

=2¹³.3¹¹ / 2¹¹.3¹¹.5

=2²/5

=4/5

4/5 chắc chắn luôn

a.

A = 72^3.54^2/108^4

A = (72.54:108)^2:108^2.72

A = 36^2:108^2.72

A = (36:108)^2.72

A = (1/3)^2.72

A = 72/9

A = 8

B = \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)

B = \(\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\)

B = \(\frac{3^{10}.16}{3^9.16}\)

B = 3

\(\frac{8^4.3^{12}-6^{11}}{4^9.9^5+6^9.120}\)Dề thế này à

\(-5^2-5\cdot32=5\left(5-32\right)=5\cdot\left(-27\right)=-135\)

\(4^6\cdot9^5+6^9\cdot120=241864704+1209323520=1451188224\)

(chả có cái đề nào ra kết quả như vày cả, có sai ko z?)

\(5^3+5^2\cdot3^2=125+25\cdot9=125+225=350\)

\(8^4\cdot3^{12}-6^{11}\)

\(=\left(2^3\right)^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-6^{11}\)

\(=6^{12}-6^{11}\)

\(=6^{11}\cdot6-6^{11}\cdot1\)

\(=6^{11}\cdot5\)

\(4^6\cdot9^5+6^9\cdot120\)

\(=\left(2^2\right)^6\cdot\left(3^2\right)^5+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)

\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

\(8^4\cdot3^{12}-6^{11}\)

\(=\left(2^3\right)^4\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}=2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)\)

\(=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)