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a) \(-\frac{4}{15}\cdot\left(-\frac{3}{8}\right)\cdot\left(\frac{15}{-4}\right)\cdot8\)
\(=\left(-\frac{4}{15}\cdot\left(\frac{15}{-4}\right)\right)\cdot\left(-\frac{3}{8}\cdot8\right)\)
\(=1\cdot\left(-3\right)=-3\)
b) \(-\frac{2}{3}\cdot\frac{4}{19}+\frac{5}{3}\cdot\frac{4}{19}\)
\(=\frac{4}{19}\cdot\left(\frac{5}{3}-\frac{2}{3}\right)\)
\(=\frac{4}{19}\cdot1=\frac{4}{19}\)
c) \(-\frac{1}{2}\cdot\frac{5 }{3}+\frac{1}{2}\cdot\frac{8}{3}\)
\(=\frac{1}{2}\left(\frac{8}{3}-\frac{5}{3}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)
\(\frac{4^{10}.9^6+3^{12}.8^5}{6^{13}.4-2^{16}.3^{12}}\)
\(=\frac{\left(2^2\right)^{10}.\left(3^2\right)^6+3^{12}.\left(2^3\right)^5}{\left(2.3\right)^{13}.2^2-2^{16}.3^{12}}\)
\(=\frac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2-2^{16}.3^{12}}\)
\(=\frac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{12}.3-3^{12}.2^{16}}\)
\(=\frac{2^4}{3}\)
a: \(B=\frac12-\left\lbrack\frac38+\left(-\frac74\right)\right\rbrack\)
\(=\frac12-\frac38+\frac74\)
\(=\frac48-\frac38+\frac{14}{8}=\frac{15}{8}\)
b: \(-\frac{4}{12}-\left(-\frac{13}{39}-0,25\right)+0,75\)
\(=-\frac13+\frac13+0,25+0,75\)
=0,25+0,75
=1
c: \(\frac12-\frac13+\frac{1}{23}+\frac16\)
\(=\left(\frac12-\frac13+\frac16\right)+\frac{1}{23}\)
\(=\left(\frac16+\frac16\right)+\frac{1}{23}=\frac13+\frac{1}{23}=\frac{26}{69}\)
d: \(\left(-\frac{13}{7}-\frac49\right)-\left(-\frac{10}{7}-\frac49\right)\)
\(=-\frac{13}{7}-\frac49+\frac{10}{7}+\frac49\)
\(=-\frac{13}{7}+\frac{10}{7}=-\frac37\)
e: \(\left(\frac78-\frac52+\frac47\right)-\left(-\frac37+1-\frac{13}{8}\right)\)
\(=\frac78-\frac52+\frac47+\frac37-1+\frac{13}{8}\)
\(=\frac{20}{8}-\frac52=0\)
f: \(-\frac37+\left(3-\frac34\right)-\left(2,25-\frac{10}{7}\right)\)
\(=-\frac37+3-\frac34-2,25+\frac{10}{7}\)
\(=\frac77+0,75-\frac34\)
=1
g: \(\left(\frac53-\frac37+9\right)-\left(2+\frac57-\frac23\right)+\left(\frac87-\frac43-10\right)\)
\(=\frac53-\frac37+9-2-\frac57+\frac23+\frac87-\frac43-10\)
\(=\left(\frac53+\frac23-\frac43\right)+\left(-\frac37-\frac57+\frac87\right)+\left(9-2-10\right)\)
\(=\frac33+7-10=1-3=-2\)
\(\dfrac{4^{10}.9^6+3^{12}.8^5}{6^{13}.4-2^{16}.3^{12}}\)
\(=\dfrac{\left(2^2\right)^{10}.\left(3^2\right)^6+3^{12}.\left(2^3\right)^5}{\left(2.3\right)^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{13}-2^{16}.3^{12}}\)
\(=\dfrac{2^{15}.3^{12}.\left(2^5+1\right)}{2^{15}.3^{13}.\left(3-2\right)}\)
\(=\dfrac{2^5+1}{3-2}\)
\(=\dfrac{32+1}{1}=33\)
35×(52−103)−58:(14−23)35×(52-103)-58:(14-23)
=35×(156−206)−58:(312−812)=35×(156-206)-58:(312-812)
=35×(−56)−58:
\(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{5}{2}\) - \(\dfrac{10}{3}\)) - \(\dfrac{5}{8}\): ( \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\))
\(\dfrac{3}{5}\) \(\times\) \(\dfrac{5}{2}\) - \(\dfrac{3}{5}\) \(\times\) \(\dfrac{10}{3}\) - \(\dfrac{5}{8}\): (-\(\dfrac{5}{12}\))
= \(\dfrac{3}{2}\) - 2 + \(\dfrac{3}{2}\)
= (\(\dfrac{3}{2}\) + \(\dfrac{3}{2}\)) - 2
= 3 - 2
= 1