AI GIÚP MÌNH VỚI!!!

1) \(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right)\)\(.x-8\) \(\left(\frac{3}{5}+0,415+\frac{1}{200}\right)\)\(:0,01\)

2) \(\left(\frac{1}{1.101}+\frac{1}{2.102}+...+\frac{1}{10.110}\right)\)\(.x=\) \(\frac{1}{1.11}+\frac{1}{2.12}+...+\frac{1}{100.110}\)

3) \(x-\) \(\frac{20}{11.13}\)\(-\) \(\frac{20}{13.15}\)\(-\)\(\frac{20}{15.17}\)\(-...-\) \(\frac{20}{53.55}=\frac{3}{11}\)

4) \(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)

GIÚP MÌNH ĐI MÀ!!!😭😭😭

Tính hợp lí :

a,\(\frac{-3}{5}\)* \(\frac{2}{7}\)+\(\frac{-3}{7}\)*\(\frac{3}{5}\)+\(\frac{-3}{7}\)

b, \(\left(\frac{-5}{24}+0.75+\frac{7}{12}\right)\): \(\left(-2\frac{1}{4}\right)\)

c,\(\frac{4}{9}\): \(\left(-\frac{1}{7}\right)\)+\(6\frac{5}{9}\): \(\left(\frac{-1}{7}\right)\)

d, \(\frac{6^4\cdot3^2\cdot25^2-8^3\cdot9^2\cdot125}{5^2\cdot4^3\cdot3^4}\)

giúp mk nha

Tính hợp lý (nếu được)

\(a\) \(19\frac{5}{8}\)\(:\)\(1\frac{5}{7}\)\(-\) \(15\frac{5}{8}\) \(:\) \(\frac{12}{17}\)\(-\)\(1\frac{1}{3}\)

\(b\) \(\frac{2}{5}\)\(.\)\(\frac{1}{3}\)\(-\) \(\frac{2}{15}\)\(:\) \(\frac{1}{5}\)\(+\) \(\frac{3}{5}\)\(.\) \(\frac{1}{3}\)

\(c\)\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)

\(f\)\(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)

\(g\)\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}.\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\)

\(h\)\(\frac{4}{9}.19\frac{1}{3}-\frac{4}{9}.39\frac{1}{3}\)

\(k\)\(125\%.\left(\frac{-1}{2}\right)^2:\left(1\frac{5}{16}-1,5\right)+2008^0\)

\(m\)\(F=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)

Làm bao nhiêu cũng được nha, càng nhiều càng tốt

Tính giá trị biểu thức :

\(\left(\frac{1}{2}-1\right)\): \(\left(\frac{1}{3}-1\right)\):\(\left(\frac{1}{4}-1\right)\)\(:...:\)\(\left(\frac{1}{99}-1\right)\)\(:\left(\frac{1}{100}-1\right)\)

\(Các\)\(bạn\)\(giúp\)\(mk\)\(nha\)\(!\)^-^ \(Thanks\)

Bài 1

\(\frac{1}{2}+\frac{1}{2.3}+\frac{1}{3.4}+.......+\frac{1}{x.\left(x+1\right)}=\frac{49}{50}\)

\(\frac{2x+3}{x-1}\)có giá trị là số nguyên \(\left(x\inℤ,x\ne0\right)\)

\(\frac{x-4}{y-3}=\frac{4}{3}\)và \(x-y=5\)\(\left(y\ne3\right)\)

Tìm x,y nguyên dương để: \(\frac{1}{x}+\frac{y}{2}=\frac{5}{8}\)

\(\left(x+3\right)^2+\left(y-1\right)^2< 4\left(x;y\inℤ\right)\)

\(\left(x+3\right)^2.\left(y-3\right)=-4\left(x;y\inℤ\right)\)

a) A = \(\left(1-\frac{1}{2}\right)\). \(\left(1-\frac{1}{3}\right)\). \(\left(1-\frac{1}{4}\right)\). . . . . \(\left(1-\frac{1}{1000}\right)\)

a) A =\(\left(1-\frac{1}{5}\right)\) \(\left(1-\frac{2}{5}\right)\). \(\left(1-\frac{3}{5}\right)\). . . . .  \(\left(1-\frac{2005}{5}\right)\)

c) C = \(\frac{8}{9}\). \(\frac{15}{16}\). \(\frac{24}{25}\). . . . . \(\frac{2499}{2500}\)

a) A = \(\left(1-\frac{1}{3}\right)\). \(\left(1-\frac{1}{6}\right)\). \(\left(1-\frac{1}{10}\right)\). . . . . \(\left(1-\frac{1}{780}\right)\)