cái dấu gạch ngang dài bên trên là chỉ phân số nhé

đúng rồi đấy

a) \(\frac{2^{10}\times13+2^{10}\times65}{2^8\times104}=\frac{2^{10}\times\left(13+65\right)}{2^8\times104}=\frac{2^{10}\times78}{2^8\times104}=\frac{2^8\times312}{2^8\times104}=\frac{312}{104}=3\)

b) \(\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times\left(65\times111-13\times15\times37\right)\)

\(=\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times\left(65\times111-13\times5\times3\times37\right)\)

\(=\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times\left(65\times111-65\times111\right)\)

\(=\left(1+2+...+100\right)\times\left(1^2+2^2+...+10^2\right)\times0\)

\(=0\)

_Chúc bạn học tốt_

\(\frac{2^{10}.78}{2^8.2^2.26}\)

=\(\frac{2^{10}.78}{2^{10}.26}\)

=\(\frac{78}{26}\)

=3

a) \(\frac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}\)

\(=\frac{2^{10}\cdot\left(13+65\right)}{2^8\cdot104}\)

\(=\frac{2^{10}\cdot78}{2^8\cdot104}\)

\(=\frac{39}{13}\)

\(=3\)

b) \(\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot\left(65\cdot111-13\cdot15\cdot37\right)\)

\(=\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot\left(13\cdot5\cdot111-13\cdot15\cdot27\right)\)

\(=\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot\left(13\cdot555-13\cdot555\right)\)

\(=\left(1+2+...+100\right)\cdot\left(1^2+2^2+...+10^2\right)\cdot0\)

\(=0\)

đó là phần a còn phần b là:

(1+2+3+......+100).(1²+2²+3²+.....+10²).(195.37-195.37)

=(1+2+3+......+100).(1²+2²+3²+.....+10²).0

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