cccc\(\rarr\rho\larr\begin{cases}\rho\chi\delta\vartheta\Phi|_{\placeholder{}}^{\underset{\text{\placeholder{}}}{\overset{\underrightarrow{\overrightarrow{455\vartheta\varkappa\varpi}}}{\xrightarrow{}}}}\\ \placeholder{}\end{cases}\) ccccccccc

=[(-8)+(-3)]+10

= (-11)+10

=-1

CHÚC HỌC TỐT

NHỚ TICK :D

là:

\(\left(\right. - 8 \left.\right) + 10 + \left(\right. - 3 \left.\right)\)

Cách tính:

• Bắt đầu từ trái sang phải, đầu tiên tính \(\left(\right. - 8 \left.\right) + 10\):
  \(- 8 + 10 = 2\)
• Sau đó, cộng tiếp với \(- 3\):
  \(2 + \left(\right. - 3 \left.\right) = - 1\)

Vậy giá trị biểu thức là -1. 
Tham khảo

Hok tốt

Ta có :\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)=\(\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)= \(\frac{2^{10}.\left(2^{10}+1\right)}{2^{12}.\left(2^{10}+1\right)}\)=\(\frac{2^{10}}{2^{12}}\)= 4.

phải là 1/4 chứ 

\(A=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.\left(2^{18}+2^8\right)}{2^{12}.\left(1+2^{10}\right)}=\frac{2^8.\left(2^{10}+1\right)}{1+2^{10}}=2^8\)

\(A=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)

\(A=\frac{2^{12}\cdot\left(2^{18}+2^8\right)}{2^{12}\cdot\left(1+2^{10}\right)}\)

\(A=\frac{2^8\cdot\left(2^{10}+1\right)}{2^{10}+1}\)

\(\frac{2^{10}\cdot13+2^{10}\cdot37}{2^8\cdot90}\)

\(=\frac{2^{10}\cdot\left(13+37\right)}{2^8\cdot2\cdot3^2\cdot5}\)

\(=\frac{2^{10}\cdot50}{2^9\cdot3^2\cdot5}\)

\(=\frac{2^{10}\cdot2\cdot5^2}{2^9\cdot3^2\cdot5}=\frac{2^{11}\cdot5^2}{2^9\cdot3^2\cdot5}\)

\(=\frac{2^2\cdot5}{3^2}=\frac{20}{9}\)

\(\frac{2^{10}.13+2^{10}.27}{2^8.90}\)

=\(\frac{2^{10}.\left(13+27\right)}{2^8.90}\)

=\(\frac{2^{10}.40}{2^8.90}\)

=\(\frac{2^2.4}{1.9}\)

=\(\frac{4.4}{9}\)

=\(\frac{16}{9}\)

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=3\)

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^2.78}{104}=\frac{2^2.2.39}{2^3.13}=\frac{2^3.39}{2^3.13}=3\)

a: \(23\cdot37+13\)

=851+13

=864

b: 45-30:5

=45-6

=39

c: \(\left(7^2+3^8\right)-10^2\)

\(=49+6561-100\)

=6610-100

=6510

a) \(23 \times 37 + 13\)

\(23 \times 37 = 851 , 851 + 13 = 864\)

b) \(45 - 30 : 5\)

\(30 : 5 = 6 , 45 - 6 = 39\)

c) \(\left(\right. \frac{7}{27} + \frac{3}{8} \left.\right) - \frac{1}{10}\)

• Tìm mẫu chung:
  \(\frac{7}{27} + \frac{3}{8} = \frac{137}{216}\)
  \(\frac{137}{216} - \frac{1}{10} = \frac{577}{1080}\)